Jornada segunda
DON ALONSO, MOSCATEL
(A) zero (B)
4
0σV µ
(C) 2
0σV
µ (D) µ0σV
14. Magnetic force per unit area on the upper plate, including its direction -
(A) µ0σ2V2 upward (B) 2
v2
0σ2
µ upward
(C) 2µ0σ2V2 downward (D) 2
V2
0σ2
µ downward
15. At what speed V would the magnetic force balance the electrical force, where C is the speed of light - (A) 0. 5 C (B) 0.2 C
Passage: II (Ques. 16 to 18)
Initially circuit is in steady state.
S 6 µF 6 Ω
18 V
3 µF a b 3 Ω
16. When switch S is open, then Vb– Va is -
(A) 6V (B) – 6 V (C) 18 V (D) – 18 V 17. When switch S is closed then Vb – Va is -
(A) 6V (B) 0 V (C) 18 V (D) – 6 V 18. How much does the charge on capacitor 6µF change
when S is closed -
(A) 16 µC (B) 18 µC (C) 36 µC (D) 72 µC This section contains 2 questions (Questions 19, 20).
Each question contains statements given in two columns which have to be matched. Statements (A, B, C, D) in Column I have to be matched with statements (P, Q, R, S, T) in Column II. The answers to these questions have to be appropriately bubbled as illustrated in the following example. If the correct matches are A-P, A-S, A-T;
B-Q, B-R; C-P, C-Q and D-S, D-T then the correctly bubbled 4 × 5 matrix should be as follows :
A B C D
P
Q R S T
T S P
P P Q R
R R Q Q
S S T
T P Q R S T
Mark your response in OMR sheet against the question number of that question in section-II. + 8 marks will be given for complete correct answer (i.e. +2 marks for each correct row) and No Negative marks for wrong answer.
19. For one dimensional motion if
Vav = average speed V→av = average velocity Vinst = instantaneous speed
Vinst = instantaneous velocity; v = speed Then match the following
Column-I Column-II
(A) V→inst= V→av (P) for uniform motion in any direction
(B) |V→inst| = V (Q) for uniform motion in given direction (C) Vinst = Vav (R) Always true (D) |V→inst| < V (S) Never true
20. Match the following
Column-I Column-II
(A) Motion of dropped (P) Two dimensional ball motion
(B) Motion of a snake (Q) Three dimensional motion
(C) Motion of a bird (R) One-Dimensional motion (D) Earth (S) Absolute rest
(T) None of these
C HEMISTRY
Questions 1 to 8 are multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE is correct. Mark your response in OMR sheet against the question number of that question. + 3 marks will be given for each correct answer and – 1 mark for each wrong answer.
1. The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6 is -
(A) 0 (B) 2.84
(C) 4.90 (D) 5.92
2. The crystalline salt, Na2SO4xH2O on heating loses 55.9% of its weight. The formula of the crystalline salt is -
(A) Na2SO4.5H2O (B) Na2SO4.7H2O (C) Na2SO4.10H2O (D) None of these
3. The correct order of increasing C–O bond length in CO, CO23–, CO2 is -
(A)CO32–< CO2 < CO (B) CO2 < CO32–< CO (C) CO < CO32–< CO2 (D) CO < CO2 < CO23– 4. If the wavelength of series limit of Lyman series for
He+ ion is x Å then what will be the wavelength of series limit of Balmer series for Li+2 ion ?
(A) 4
x
9 Å (B)
7 x
4 Å
(C) 4
x
5 Å (D)
9 x 16 Å 5. The correct order of acidic strength is –
(A) Cl2O7>SO2>P4O10 (B) CO2>N2O5 <SO3 (C) Na2O>MgO>Al2O3
(D) K2O>CaO>MgO
6. In a hypothetical solid C atoms form CCP lattice with A atoms occupying all the Tetrahedral voids and B atoms occupying all the octahedral voids. A and B atoms are of the appropriate size such that there is no distortion in the CCP lattice. Now if a plane is cut (as shown) then the cross section would like –
Plane
CCP unit cell
(A)
C C
C C
B
B B B
A
A
B
(B)
C C
C
B B B
C C
C C
(C) C
C
B B B
C C
C C
A A A A
(D)
C C
C
B B B
C C
C C
7. Regarding graphite the following informations are available :
3.35Å
Top view
The density of graphite = 2.25 gm/cm3. What is C–C bond distance in graphite ?
(A) 1.68Å (B) 1.545Å (C) 2.852 Å (D) 1.426Å
8. The geometrical shapes of XeF5+, XeF6 and XeF82–
respectively are -
(A) trigonal bipyramidal, octahedral and square planar
(B) square based pyramidal, distorted octahedral and octahedral
(C) planar pentagonal, octahedral and square anti prismatic
(D) square based pyramidal, distorted octahedral and square anti prismatic
Questions 9 to 12 are multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which MULTIPLE (ONE OR MORE) is correct. Mark your response in OMR sheet against the question number of that question. + 4 marks will be given for each correct answer and – 1 mark for each wrong answer.
9. Which of the following is/are correct ? (A) α-rays are more penetrating than β-rays (B) α-rays have greater ionizing power than β-rays (C) β-particles are not present in the nucleus, yet they
are emitted from the nucleus
(D) γ-rays are not emitted simultaneously with α and β-rays
10. Select the correct curve (s)
If v = Velocity of electron in Bohr's orbit r = Radius of electron in Bohr's orbit
P.E. = Potential energy of electron in Bohr's orbit K.E. = Kinetic energy of electron in Bohr's orbit
(A) v 1/n
(B) r
n
(C) 1/n
z
P.E. (D) K.E.
n
11. In which of the following molecules there is no S—S bond(s)?
(A) S2O42– (B) S2O52–
(C) S2O32– (D) S2O72–
12. During the electrolysis of AgNO3 (using Pt electrodes) concentration around cathode as well as anode falls from 4 M to 3 M. What will happen if this happened with Ag electrodes ?
(A) Result will remain same
(B) Concentration around cathode will fall from 4 M to 3 M but around anode will increase from 4 M to 5 M
(C) Reverse of statement 'b'
(D) Concentration increases from 4 M to 5 M on both the electrodes
This section contains 2 paragraphs; each has 3 multiple choice questions. (Questions 13 to 18) Each question has 4 choices (A), (B), (C) and (D) out of which ONLY ONE is correct. Mark your response in OMR sheet against the question number of that question. + 4 marks will be given for each correct answer and – 1 mark for each wrong answer.
Passage : I (Ques. 13 to 15)
According to Einstein, when light of some particular frequency falls on surface of metal, the photon give its entire energy to the electron of the metal atom.
The electron will be dislodged or detached form the metal atom only if the energy of the photon is sufficient to over come the force of attraction of the electron by the nucleus. That is why photoelectrons are ejected only when the incident light has a certain minimum frequency. According to Einstein
hν = hν0 + 2 1 mv2 ,
Where ν is the frequency of its incident light and ν0 is the minimum energy and v is the velocity of electron. A graph can be plotted between the kinetic energy and frequency of absorbed photons :
Frequency Kinetic Energy of photoelectrons
v0
... (K.E.) = hν – hν0
13. As per the experiments carried out for PEE; we can say -
(A) As the intensity of light increases, velocity of photoelectron increases.
(B) As the intensity of light increases, energy of photoelectron increases.
(C) As the intensity of light increases, no. of photoelectrons decreases.
(D) Kinetic energy of photoelectron is proportional to frequency of incident light.
14. When a light of frequency ν1 is incident on a metal surface the photoelectron emitted had twice the kinetic energy as did the photoelectrons emitted when the same metal had irradiated with light of frequency ν2. What will be threshold frequency.
(A) ν0 = ν1 – ν2 (B) ν0 = 2ν2 – ν1 (C) ν0 = 2ν1 – ν2 (D) ν0 = ν1 + ν2
15. The equation of photoelectric effect represents an equation of -
(A) straight line (B) parabola (C) ellipse (D) None
Passage: II (Ques. 16 to 18)
The colligative properties of electrolytes require a slightly different approach than the one used for the colligative properties of non-electrolytes. The electrolytes dissociate into ions in solution. It is the number of solute particles that determines the colligative properties of a solution. The electrolyte solution therefore, show abnormal colligative properties. To account for this effect we define a quantity called the van't Hoff factor, given by i = Numberofformulaunitsinitiallydissolvedinsolution
on dissociati after
solution in particles of
number Actual
i = 1 (for non-electrolyte);
i > 1 (for electrolytes, undergoing dissociation)
16. Certain substance trimerises when dissolved in a solvent A. The van't Hoff factor 'i' for the solution is :
(A) 1 (B) 1/3
(C) 3 (D) unpredictable
17. For a solution of a non-electrolyte in water, the van't Hoff factor is :
This section contains 2 questions (Questions 19, 20).
Each question contains statements given in two columns which have to be matched. Statements (A, B, C, D) in Column I have to be matched with statements (P, Q, R, S, T) in Column II. The answers to these questions have to be appropriately bubbled as illustrated in the following example. If the correct matches are A-P, A-S, A-T;
Mark your response in OMR sheet against the question number of that question in section-II. + 8 marks will be given for complete correct answer (i.e. +2 marks for each correct row) and No Negative marks for wrong answer.
19. Column-I Column-II (Ionic species) (Shapes)
(A) XeF5+ (P) Tetrahedral
(P) Projectile capture (Q) Spallation (R) Fusion
(S) Projectile capture and particle emission (T) Fission
MATHEMATICS
Questions 1 to 8 are multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE is correct. Mark your response in OMR sheet against the question number of that question. + 3 marks will be given for each correct answer and – 1 mark for each wrong answer.
1. The range of k for which ||x–1|–5| = k have four distinct solutions -
(A) [0, 5] (B) (–∞, 5) (C) [0, ∞) (D) (0, 5)
2. Let f(x) be a second degree polynomial function such that lnf(x) > 0 ∀ x ∈ R & the equation f '(x) + 786 f(x), has no real roots. If g(x) = e786x f(x), then -
(A) g(x) is an increasing function (B) f(x) is a decreasing function changes concavity about the point R
which of the following conic section can have eccentricity 'a' -
(A) circle (B) parabola
7. If P = 2 3 4 n–1 n 1/(n 1) 8. Maximum value of the expression