Session 13
Introduction to Field Effect
Transistors (FET)
Electronic Components and Circuits
Field Effect Transistors
FET
OBJECTIVES
•
To know the structure of the device and the transistor
•
To know the structure of the device and the transistor
effect
•
To know and distinguish different FET transistor types
•
To understand the current-voltage characteristic of the
device
•
To identify the operating regions
Cut-off, Saturation, Ohm (triode)
Cut-off, Saturation, Ohm (triode)
•
To analyze FET circuits basic cases in DC
Field Effect Transistors (FET)
Types
Mode
Channel
MOSFET
(Metal-Oxide Semiconductor FET)
Enhancement/ Accumulation
Channel N (or N-MOS) Channel P (or P-MOS)
Depletion Channel N (or N-MOS)
Channel P (or P-MOS)
JFET
(Joint FET)
Junction Channel N
Channel P
Unipolar: only one carrier type (electrons in N-channel and holes in P-channel)
Basic characteristics
channel)
Control of Current (I) through Voltage(V) (BJT devices control I through I) Three terminals:
Structure of Channel-n
Enhancement MOS Transistor
D G S
Metal Oxide (SiO2)
W
Drain (D)
Gate (G) Source (S) Metal Oxide
(SiO2)
n+ Channel n+
region
L p-type
substrate (Body) B
p-type substrate (Body) Drain region
Source region
n+ n+
Channel region
L
D
S
B G
D
S
B G
D
S G
D
S
G B
n-MOS Transistor Operation
G
D S V
GS
induced
n-type
channel
p-type substrate
B
GND
e
-e- e
-e
-+
u u +
G D
S VGS
VDS
iD i
G= 0 i
S=iD
p-type substrate
B
GND induced
n-typechannel
+
u u +
n-MOS Operation:
Triode region
iD (mA)
0,4
0,3
vGS= Vt+2 V
vGS= Vt+1,5 V
G D
S VGS
VDS (small)
iD i
G= 0 i
S=iD
vDS (mV)
0,2
0,1
0 50 100 150 200
vGS≤ Vt
vGS= Vt+0,5 V vGS= Vt+1 V
p-type substrate
B
GND induced
n-typechannel
+
u u +
n-MOS Operation:
Saturation region
iD
Saturation Triode
vDS<vGS- vt vDS≥ vGS - vt
G D
S VGS
VDS
iD
iG= 0
iS=iD
vDS
vGS > vt
vDSsat = vGS - vt
p-type substrate
B
GND n-channel
+
u u +
Current-Voltage Characteristic
VDS +
-iD
iG= 0
Saturation region Triode
region
vDS<vGS - vt vDS≥ vGS - vt
iD (mA)
2,0 v = V +2,0
Triode region
[
2]
−
−
=
VGS +
-iD= iS vDS= vGS- vt
vDS(V) 1,5
2,0
1,0
0,5
0 1 2 3 4
vGS≤ Vt (cutoff) vGS= Vt+0,5
vGS= Vt+1,0 vGS= Vt+2,0
vGS= Vt+1,5
[
2]
)
(
2
GS t DS DSD
K
V
V
V
V
i
=
−
−
2
)
(
GS tD
K
V
V
i
=
−
Saturation region (I
Ddoes not depend on V
DS)
L
W
C
K
µ
n oxOutput Characteristics: Saturation
iD (mA)
2,0
1,5
1,0
0,5
0 0,5 1 1,5 2 2,5 3
vDS≥ vGS- vt
2
)
(
GS tD
K
V
V
i
=
−
Saturation region (I
Ddoes not depend on V
DS)
vGS (V)
Current-Voltage Characteristic
Saturation region Triode
region
iD
vGS= Vt+2,0V
Slope = 1/ro
vDS
vGS≤ Vt (cutoff)
vGS= Vt+0,5V vGS= Vt+1,0V vGS= Vt+1,5V
-V
A= -1/
λ
)
1
(
)
(
GS t 2 DSD
K
V
V
V
i
=
−
+
λ
V
A is the channel modulation voltage, producing a similar effect to the Early voltage in BJT
devices.
If we consider this effect then:
p-channel MOSFET (P-MOS)
Drain (D)
Gate (G) Source (S) Source (S) Gate (G) Drain (D)
Polysilicon Gate Oxide
Thick
In
enhancement p-mos
there is a
channel if:
V
≤
V
<
0
p
+p
+p-type body
S
B G
S
B G
S
G
n
+n
+n-well
Thick SiO2 (isolation)
channel if:
triode region
saturation region
0
<
≤
tGS
V
V
t GS
DS
V
V
V
≥
−
t GS
DS
V
V
V
≤
−
S S D D
D
Depletion MOSFET
Equivalent behavior to enhancement MOSFET devices, except for
Manufactured channel:
When V
GS<0 channel is reduced (e
-leave Gate region)
When
V
≤
V
<
0
channel disappears (
cut-off
region)
When
V
GS≤
V
t<
0
channel disappears (
cut-off
region)
D
S
B G
D
S G
Saturation region Triode
region
vDS= vGS- vt
vDS<vGS- vt vDS ≥ vGS - vt
iD (mA)
24 32
20 28
vGS= 2V (Vt+6)
vGS= 1V (Vt+5) 36
S D
G B
vDS (V)
16
8
0 4 8 12
vGS≤ -4 V (Vt)
vGS= -3V (Vt+1)
2 6 10 14
12
4 vGS= -2V (Vt+2)
vGS= 0V (Vt+4)
Summary
In
enhancement
n-MOS there is a
channel if:
in triode region
in saturation region
0
>
≥
t GSV
V
t GSDS
V
V
V
≤
−
t GS
DS
V
V
V
≥
−
In
enhancement
p-MOS there is a
channel if:
in triode region
in saturation region
0
<
≤
t GSV
V
t GSDS
V
V
V
≥
−
t GS
DS
V
V
V
≤
−
in saturation region
t GS
DS
V
V
V
≥
−
in saturation region
t GS
DS
V
V
V
≤
−
iD
0 vGS
n-channel enhancement p-channel enhancement p-channel depletion n-channel depletion
In
depletion
n-MOS there is a
channel if:
in triode region
in saturation region
0
,
<
≥
t tGS
V
V
V
t GS
DS
V
V
V
≤
−
t GS
DS
V
V
V
≥
−
In
depletion
p-MOS there is a
channel if :
in triode region
in saturation region
0
,
>
≤
t tGS
V
V
V
t GS
DS
V
V
V
≥
−
t GS
DS
V
V
V
≤
−
Junction Field Effect Transistor (JFET)
N channel
P channel
Drain Gate p -t y p e G a te n-type C h a n n e l Drain Gate n -t y p e G a te p-type C h a n n e l Drain Gate Gate Drain 2 2
/
,
)
(
GS p DSS pD
K
V
V
K
I
V
i
=
−
=
2
1
−
=
p GS DSS DV
V
I
i
Source Source Gate SourceSaturation region
Triode region
vDSsat= vGS - vp
vGS0 = 0
vGS1 = VGS0
Saturation
I
DSI
DSSource
vGS4 < VP
vGS3 < VGS2
vGS2 = VGS1
Cutoff region
Saturation
region
Triode
region
v
GSv
pV
DSCutoff region
DC bias point:
Load line
Saturation Triode
ID v = V
VDD
v1
+
vo= vDS
vGS=v1
-RD
Saturation Triode
ID
IDQ
Q
Load line slope = -1/RD
v = V
vGS= V1B
vGS< V1B vGS> V1B vGS= VDD
B C
vGS=v1
-vDS=vo 0 VOB=VIB-VIt
vGS= … vGS= V1Q
A
FET transistor as amplifier:
VDD
v
oQ1 in triode region Q1in
saturation Q1
cutoff
A
VDD
Q
B
C X
Time VOQ=VOQ
VOB
V
vO Slope at Q = voltage gain
VDD
VOC
Vt VIQ VIB=VOB+Vt
v
i
Small-signal model
+
v
gsg
mv
gsG
D
+
v
gsg
mv
gsG
D
r
oSaturation Triode
iD
vGS= Vt+2,0V
Saturation Triode
vDS= vGS- vt
vDS<vGS- vt vDS≥ vGS- vt
iD (mA)
1,5
2,0 vGS= Vt+2,0
-v
gsg
mv
gsS
-v
gsg
mv
gsS
r
oSlope = 1/ro
vDS
vGS≤ Vt
(cutoff) vGS= Vt+0,5V
vGS= Vt+1,0V
vGS= Vt+2,0V
vGS= Vt+1,5V
-VA= -1/λ
vDS= vGS- vt
vDS(V) 1,5
1,0
0,5
0 1 2 3 4
vGS≤ Vt(cutoff)
vGS= Vt+0,5
vGS= Vt+1,0
Small-signal parameters
+
-v
gsg
mv
gsG
D
r
o)
(
2
GS tV v GS D
m
K
V
V
V
i
g
DSQ ds−
=
∂
∂
=
=In MOSFETs
In JFETs
-S
iD ID An almostlinear segment Slope = gm
id t Q
−
−
=
∂
∂
=
= p GS p DSS V v GS D mV
V
V
I
V
i
g
DSQ ds1
2
In JFETs
0 v vGS
t
vgs
vOV
Small-signal parameters
+
v
g v
G
D
r
A D D
DS D
o
V
I
I
v
i
r
∂
≈
=
∂
=
λ
1
+
-v
gsg
mv
gsS
r
oSaturation Triode
Slope = 1/r
iD
vGS= Vt+2,0V
D A o
I
V
r
=
Slope = 1/ro
vDS
vGS≤ Vt
(cutoff) vGS= Vt+0,5V
vGS= Vt+1,0V
vGS= Vt+1,5V
Exercise:
Operation regions. Saturation
EXAMPLE
|V
t| = 2 V
L=10um
W=100um
λ
=0
2
/
20
uA
V
C
oxn
=
µ
V
DD= 10 V
VD R ID
a) Design the circuit in order to obtain a I
D=0.4mA
Exercise:
Operation regions. Triode region
EXAMPLE
V
DD= 5 V
K = 0.5 mA/V
2|V
t| = 1 V
V
DD= 5 V
VD= 0,1 V R
ID
a) Design the circuit for obtaining V
D=0.1V
Proposed exercise
Example
VDD= +10V
K = 0.5 mA/V
2|V
t| = 1 V
RG2= 10 MΩ
RG1= 10 MΩ
RS= 6 kΩ
RD= 6 kΩ