N A L E S E D L ’IN IT ST T U
F O U R IE
ANNALES
DE
L’INSTITUT FOURIER
Evgueni DOUBTSOV & Artur NICOLAU
Symmetric and Zygmund measures in several variables Tome 52, no1 (2002), p. 153-177.
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SYMMETRIC AND ZYGMUND MEASURES
IN SEVERAL VARIABLES
by
E. DOUBTSOV and A. NICOLAU1.
Introduction.
A
(signed)
finite Borel measure J-l on the unit circle T is called aZygmund
measure if there exists a constant C =C(p)
> 0 such thatfor any
pair
ofadjacent
arcsI+,
I- of the samelength - 11_1.
Ifthe constant C can be taken
arbitrarily
smallas 11+1 tends
to0, p
is calleda small
Zygmund
measure.Corresponding
to theZygmund
measures, there are the Bloch func-tions,
thatis, analytic
functionsf
in the unit disc for which there exists apositive
constant C =C( f )
> 0 such thatThe little Bloch space consists of those Bloch functions
f satisfying
P.
Duren,
H.Shapiro
and A. Shieldsproved
thefollowing
result.The second author is supported in part by the DGICYT grant PB98-0872 and CIRIT grant 2000 SGR00059.
Keywords: Doubling measures - Zygmund measures - Harmonic extensions - Quadratic
condition.
Math. classification: 28A15 - 31B10.
THEOREM A
([9]).
- Let p be a finite measure on the unit circle and letH (p)
be itsHerglotz transform,
Then it is a
(small) Zygmund
measure if andonly
is a(little)
Blochfunction.
A finite
positive
measure p on the unit circle is calleddoubling
ifthere exists a
positive
constant C = > 0 such thatfor any
pair
ofadjacent
arcs ofequal length. Symmetric
measures are thosedoubling
measuressatisfying
A classical result of
Beurling
and Ahlfors says that ahomeomorphism
fromthe unit circle onto itself extends
quasiconformally
to the wholecomplex plane
if andonly
if its distributional derivative is a measuresatisfying
the
doubling
condition(1.2). Also, symmetric
measurescorrespond
toquasiconformal
extensions whose conformal distortion tends to 0 at the unit circle([11]).
The connection with the
previous setting
is that(1.2)
is the "multi-plicative"
version of the "additive" condition(1.1),
see[10].
In the
spirit
of TheoremA,
thefollowing description
ofsymmetric
measures has been obtained.
THEOREM B
([l]).
-Let it
be apositive
measure in T and let be itsHerglotz transform,
Then IL is
symmetric
if andonly
ifThe nature of Theorems A and B is
purely
real butcomplex analysis
techniques
are used at certainsteps
of thecorresponding proofs.
The mainaim of this note is to
study symmetric
andZygmund
measures in theEuclidean space.
We now fix some notations which will be used
throughout
the paper.The
symbol
m denotesLebesgue
measure. Given a set E ClEI
-m(E).
Theupper-half
space will be denotedby
R’, y
>0}. Also, Q+
andQ-
denote twoadjacent
cubes in R~ ofequal
volume. More
precisely, Q+ = 11
x ... xIn, Q_ == Ji
x ’" xJn
whereIi, Jk
are intervals ofequal length f(Q+) == ~(Q-)
andIi
=Ji
for anyi, 1
i x n,except
forexactly
one index s,1 s
n, for whichIS
andJs
are
adjacent.
Aregular
gauge function will be apositive non-decreasing,
bounded function w :
(0, oo)
~(0, oo)
such that for somepositive
numberc >
0,
the functionw(t)/t1-E:
isdecreasing.
Observe that aregular
gauge function w satisfies thatw(t) /w(s)
isuniformly
bounded if1/2 tls
2and that
limt-o
= 00.Given a finite measure tc in let u be its harmonic
extension,
thatis,
where
P(x, y)
is the Poisson kernel of theupper-half
space,where
Cn
is chosen so thatJ~ P(x, y)drrt(x)
= 1.Let w be a
regular
gauge function. A(signed)
Borel measure it in R~is called
w-Zygmund
if there exists apositive
constant C such thatfor any
pair Q+, Q_
C R~ ofadjacent
cubes. Our first result is an Euclidean version of theDuren-Shapiro-Shields
characterization.THEOREM 1.1. -
Let 1L
be a(signed)
finite Borel measure in I1~~ and be aregular
gauge function. Let u be the harmonic extension of A.The
following properties
areequivalent:
(a) p
is anw-Zygmund
measure.(b)
There exists apositive
constant C > 0 such thatfor any
point
A
positive
Borel measure p in R’ is calleddoubling
if there exists aconstant C > 0 such that
for any
pair Q+, Q-
C R’ ofadjacent
cubes.Clearly
adoubling
measurecan not be finite.
Similarly,
a finitepositive
measure ti is calledw-symmetric
if there exists a
positive
constant C > 0 such thatfor any
pair
ofadjacent
cubesQ+, Q_
with.~(Q+)
1. So aw-symmetric
measure satisfies the
doubling
condition for cubes ofsidelength
smallerthan 1.
Let u be a
positive
harmonic function in~¡+1.
Harnack’sinequality
asserts that
for any
point (x, y)
E]R~+1.
Thisinequality
is bestpossible
as one caneasily
seeby taking
p a Delta mass.Actually,
if P denotes the Poissonkernel,
one hasy8yP(0, y) = -nP(O, y).
The
analogue
of Theorem B is thefollowing
result.THEOREM 1.2. - Let w be a
regular
gaugefunction, w(0+)
= 0. Letp be a
finite, positive
measure in and let u be its harmonic extension.Then the
following
conditions areequivalent:
(a)
p isw-symmetric.
(b)
There exists a constant C = > 0 such thatfor any
point (x, y)
eIl~+ 1.
The situation for
doubling
measures is not so nice.THEOREM 1.3. -
Let p
be apositive
measure in R~. Assume that+ oo and let u be its harmonic extension.
(a) If p
isdoubling,
then there exists a constant p n such thatfor any
(b)
If there exists a constant p1,
such thatfor any
(x, y)
EIR~+ 1, then p
isdoubling.
Remark. It is convenient to mention the
following phenomena
indimension one. Let p be a
positive
measure in the real line and let u be its harmonic extension.1. Assume that p is a
doubling
measure and itsdoubling
constant issufficiently
close to1,
thatis,
assume that there exists E > 0 such thatfor all intervals I of the real
line,
then there exists a constant p = 1 if E issufficiently small,
such thatfor any
2. On the other
hand,
aspart (b)
of Theorem 1.3asserts,
iffor any
then p is
doubling.
The
proofs
of Theorems1.1,
1.2 and 1.3 aregiven
in Section2,
butthe main idea can be
explained
as follows.Integrating by parts,
one may relate the size ofy) with
cancellationproperties
of the measure p,namely
with the sizeof where L+,
L- C R~ areadjacent parallelepipeds.
In the one-dimensional case,L+
and L- are intervalsand one uses
directly
thedoubling
condition(1.2)
or the condition(1.1).
However when n >
1,
we need to transfer the information we have in cubes toparallelepipeds.
This is the main technicaldifficulty
in the paper. The idea is to considerpartitions
ofL+
and L- intopairwise disjoint dyadic cubes, L+ - UQt,
L- ==UQ~ ,
whereQ+
andQk
aresymmetric
withrespect
the common sideof L+
and L-.Hence, Q+
andQ~
are notadjacent
and to estimate
(Q) 2013u(Q | we
need to take into account the distance fromQ+
toQ~ .
This leads to some technical difficulties whichrequire
adetailed
analysis
of theZygmund
and thedoubling
conditions. Aprecise
statement is
proved
in Section 4.Classical constructions
provide examples
ofpositive singular symmet-
ric(small Zygmund)
measures. See[5], [9], [12], [15], [16].
It is also well known that in the one-dimensional case, thequadratic
conditiongoverns the existence of
singular w-Zygmund (w-symmetric)
measures. See[5], [17].
Our next results tell that the
quadratic
condition(1.3)
also governs the situation inhigher
dimensions.THEOREM 1.4. - Let w be a
regular
gauge function.(a)
Assume thatThen any
w-Zygmund
measure ~c isabsolutely continuous,
thatis, p
=f dm.
Moreover for any cube
Q
C R~ and any A >0,
one has(b)
Assume thatthen there exists a
positive, finite, singular w-Zygmund
measure on R’.The
corresponding
result forsymmetric
measures is thefollowing.
THEOREM 1.5. - Let w be a
regular
gaugefunction, w(O+)
= 0.(a)
Assume thatThen any
w-symmetric
measure isabsolutely continuous,
thatis,
/-i =f dm.
Moreover for any cubeQ
in R~ and any A >0,
one has(b)
Assume thatthen there exists a
positive, finite, singular w-symmetric
measure on lRn.The
proof
of these results isgiven
in Section 3. In both cases,part
(b)
followseasily
from the one-dimensional constructions. Inpart (a)
ofTheorem
1.4,
to showthat I-L
isabsolutely continuous,
one considers its harmonic extension u. As it is wellknown,
Green’s formula relates the measure /i with a truncated version of the area function of u, which can be estimatedusing
Theorem 1.1 and theintegral
condition in theassumption.
Similar considerations
applied
tolog
u, alsogive
the absolutecontinuity
ofthe measure p in the
part (a)
of Theorem 1.5. In bothresults,
the statementon the
integrability
of thedensity
of the measure p isdeeper
and usesmartingale techniques. Namely,
let0k
be thecr-algebra generated by
thedyadic
cubes ofsidelenght 2-~, 1~ >
0. In Theorem1.4,
one considers thedyadic martingale
M =corresponding
to the measure p =f dm
defined as where
Q
is adyadic
cube of 0.Also,
consider themartingale
difference functionMk -
and the
quadratic
variation of themartingale,
SM =I:~=1 (AMk)2 .
Thefact that p is a
w-Zygmund
measure and theintegral
condition in theassumption
tell that thequadratic
variation SM isuniformly
bounded andour result follows from a Theorem of
Chang,
Wilson and Wolff([7]).
Part(a)
of Theorem 1.5 isproved by applying
similar considerations to thelogarithmic transform {N k}
of themartingale {M k }.
A similar idea wasused in
[Br].
It turns out that p bew-symmetric
translates to have increments boundedby w and
the considerations above can beapplied
tothis
martingale.
The letter C will denote an absolute constant which may
depend
onthe dimension whose value may
change
from line to line.Also, C(a)
willdenote a constant
depending
on theparameter
a.2.
Harmonic
extensions.In many different
situations,
the normal derivative8yu
of a harmonicfunction u in the
upper-half
space controls the wholegradient
of u. See forinstance
Chapter
V of[17].
In our case, we have thefollowing
result.LEMMA 2.1. - Let w be a
regular
gauge function. Let u be a harmonic function in theupper-half
space Assume(a)
Thefollowing
two conditions areequivalent.
(a.l)
There exists a constantC1
> 0 such thatfor any
(a.2)
There exists a constantC2
> 0 such thatfor any
(b)
Assume u ispositive
and there exists a constantC3
> 0 such thatfor any Then there exists a constant
C4
> 0 such thatfor any
Proof. Recall that the letter C denotes an absolute constant which may
depend
on the dimension whose value maychange
from line to line.Observe that the mean value
property gives
that for any x E R~ andy > 3/2
one hasSo in the
proof
of(a)
we may assume that 0 y3/2. By
Harnack’sinequality
we may also assume 0 y3/2
in theproof
of(b).
Assume
(a.l)
holds. Fixed i =1,..., n and
0 y3/2,
one hasLet B be the ball centered at
(x, t)
of radius2-1 t,
the mean valueproperty
and the fact that w isregular give
Thus,
for 0 y3/2,
one hasSince is
decreasing,
one hasand
(a.2)
holds becauselimy-o w(y)/y
= 00.Conversely,
assume(a.2)
holds. Let B C be the ball centered at(x, t)
of radiust/2.
The mean valueproperty
and the fact that w isregular give
Thus,
theharmonicity
of uyields
As
before,
we deduce that for 0 y3/2,
one hasThe
proof
of(b)
isalong
the same lines and weonly
sketch it. One may assumec,~(0+)
=0,
sinceotherwise,
oneapplies
Harnack’sinequality.
Hence, given c
>0,
one hasIndeed, choose q
> 0 such that2~ ( 1 - q)
> 1. Sincew(0+) = 0,
onehas
u(x, y/2)
>(1 - y)
for all y > 0 smallenough.
Thereforeu(x, y/2)(y/2)-£
>2~ (1 - 71)u(x, y)y-£
anditerating
thisinequality
oneobtains
(2.1).
As in the
Zygmund
case, the mean valueproperty gives
where
D2
denotes any second derivative of u.By (2.1), w (y) u (x, y) -> Cy
if0 y
2,
so to prove(b)
it is sufficient to show thefollowing
estimate:We bound the
integral by
a fixedmultiple
ofNow,
oneonly
has to observe thatand since
w(0+)
=0,
one may assumewhen
2 ky
issufficiently
small. To estimate the rest of the sum, one usesthat
cv(y)u(x, y)/y
is bounded below when y is small. 0 One can also write estimatesequivalent
to(a.l)
and(a.2) using
derivatives of
higher
order. Forinstance,
under thehypothesis
of Lemma2.1,
let k >1,
the estimatefor any
point
isequivalent
to(a.l)
and(a.2). Similarly,
for any
point (X, Y)
EJR¡+ 1,
isequivalent
to the condition in(b).
In the
proof
of Theorems 1.1 and 1.2 anintegration by parts argument
is used. Forconvenience,
it is collected in thefollowing
result.For x E E
(xi, Xl +t1)
x ... x(Xn, Xn + tn)
(with
obvious modifications forarbitrary t
E We say thatLt(x)
is aparallelepiped. Usually
we writeLt
inplace
ofLt (0) .
LEMMA 2.2. -
Let J1
be asigned
measure on R~ WithfJR.n (1
+oo. Assume
~c(aL) -
0 for anyparallelepiped
L CLet u be the harmonic extension
of li.
Then for anypoint (x, y) E II~+ 1,
one has
and
Proof. The two formulas are
proved
in a similar way. So weonly
show the first one. One
only
has to show thatbecause the formula will follow after a
change
of variables.To
simplify
thenotation,
assume x - 0. Fix a > 0 andput
f (t)
=f.~,, (t) = u(t, a),
t E R". We use the notation t -(ti, t’),
wheretj
E and t’ E R We havef(., t’)
E for all t’ EJRn-1
and0 as
It 1 I ~
oo.Hence, integration by parts gives
Since
f
E we mayapply
Fubini’s theorem andrepeat
theintegration by parts. Repeating
it n times weget
Now,
we claim that the lemma follows as 0. Indeeddp weakly*
as0,
so the convergence for the left hand sides holds. On the otherhand,
if z ELt (z V Lt),
thenfLt z) dm(T) /
1(respectively
B 0)
as 0. Hencesince = 0.
Now,
weapply Lebesgue’s
theorem. 0Remark. - If ft is
symmetric
orZygmund,
thenJ-l( 8L) ==
0 for anyparallelepiped
L.When
applying
Lemma2.2,
one needs to understand the cancellationproperties
of the measure onparallelepipeds.
LEMMA 2.3. and
Put t
(a)
Assume that p is anw-Zygmund
measure on Then(b)
Assumethat p
is anw-symmetric
measure on JRn.Then,
The
proof
of Lemma 2.3 is very technical and isgiven
in Section 4.Proof of Theorem 1.1
(a)
-(b). By
Lemma2.2,
we havewhere
(I)
is the lastintegral
over the ballQy (0) = ~t
ER’ : ~/}
and(II)
is theintegral
overR’ B Qy(0).
The estimateand Lemma 2.3
yield
On the other
hand, w(t)tc-1
isdecreasing,
thusTherefore,
the estimateand Lemma 2.3
give
In other
words,
we obtainand Lemma 2.1 finishes the
proof.
(b)
F(a).
Thisimplication
isessentially
known(compare
with[13],
where a similar
problem
forgeneral Lipschitz
domains isinvestigated).
Indeed,
fix > 0 and consideradjacent
cubesQ±
C R’of sidelength f
andwith centers x±
c R’. Put xo -
Then,
Green’s formula onQ±
x[E, .~~ applied
to the functions v and y and the estimate(b) yield
Since v (x, .~) ~ Cw (f)
if x EQ±,
the estimate(b) gives
thatsince w is
increasing. Hence,
thetriangular inequality gives
The latter estimate
yields J-l( 8Q) ==
0 for all cubesQ. Therefore, tending
E -
0,
we obtainProof of Theorem 1.2. - Assume that
(a)
holds. As in theproof
ofTheorem
1.1,
one uses Lemma 2.2 to writeUsing
Lemma 2.3 and(2.2)
one can estimate theintegral
overIt (z- Rn : by
where the last
inequality
follows from the estimateI itl
y.Using
the estimateif
and Lemma
2.3,
one bounds theintegral
overby
where , Since
and
one deduces
Lemma 2.1 finishes the
argument.
Conversely,
assume that(b)
holds with C = 1.First,
as in theZygmund
case, weapply
Green’s formula to the functions u and y.Namely,
let > 0 andQ±
C R~ beadjacent
cubesof
sidelength é
with centers X:f: E R~. Thenwhere dais surface measure.
Secondly,
for x EQ±
and 0 y.~,
we havePut xo -
(x+
+~-)/2.
Note that Harnack’sinequality gives
thatthere exists a constant C > 0 such that for all x E
Q± -
When
checking
thesymmnetry
condition on the cubesQ~
we may assume that is so small that1/2.
ThenHence
Therefore,
we obtainAlso
and
So, tending E
-~ 0 in(2.5),
onegets
and we deduce
Clearly (b) implies
thatand hence
Proof of Theorem 1.3.
(a) By
Harnack’sinequality
we may assume n > 2. Asimple
calcula-tion shows
Denote
by
Observe
that n and
+c2)}
at anypoint t
C R n Since thedoubling
condition(1.2) holds,
the measureiL can not be too concentrated
in ~ t
Etll Actually,
Hence,
where p n
depends
on thedoubling
constant of p.(b)
We first observe thatgiven
N >No(n,p)
there exists a constant C =C(N, p)
> 0 such thatfor any
point (x, y)
EII~+ 1.
HereNQy(x)
denotes the ballIt
Elit
-N y ~ . Indeed,
since n, one hasGiven c >
0,
there exists N =N(e)
such thatK(x, t, y) >
1 - ~ for anyt E
NQy (x). Hence,
if(2.6)
does nothold,
one would deduce that for any c > 0 there existpoints (x, y)
E such thatSo
(2.6)
isproved. Now,
an easy estimate of the Poisson kernel and(2.6)
give
thatSo,
for any
point (x, y)
EIl~+ ~, where
C is a constantdepending
on N. NowHarnack’s
inequality gives
and one deduces that p is
doubling.
DIt is convenient to mention that the bound p 1 in
part (b)
can notbe
replaced by
p nif n >
2.Actually
let a be adoubling
measure and letp be its restriction to
~x
EIlxll > 1}. So, p
is notdoubling.
Observethat for any
point (X, y)
E and any E > 0 one hasLet u be the harmonic extension of M.
Arguing
as in(a),
one deducesfor any
(x, y)
E~¡+1,
where p n is a constantonly depending
on thedoubling
constant of a.3. Best
decays.
This section is devoted to the
proofs
of Theorems 1.4 and 1.5.Proof of Theorem 1.4. - Part
(b).
Assume(1.3)
does not hold. Letv E
M(R)
be anw-Zygmund positive singular
measure withcompact support (see
e.g.[12]).
Fix acompactly supported
Holder continuous function h E and consider the measure p = v x Wenow check
that p
isw-Zygmund.
Theonly
non-trivial case arises whenQ± =
I xJ±
C areadjacent
cubes of side f 1(i.e.,
I C R is aninterval, 111
-é,
andJ±
CIEgn-1
areadjacent cubes).
Then there existsx~ E
J±
such that~~c(Q+) - p(Q_) I = CV(I)fn
since tt E
LiP1. Now, applying
theZygmund
condition one can check thatv(I) x 111-1.
ThusC1w(f),
becausew(t)/t1-E
decreases.
Part
(a).
We assume that ca satisfies(1.3). Let p
be aw-Zygmund
measure. We claim
that p
isabsolutely
continuous.Indeed,
fix a cubeQ
C 1. Since A(~c2)
=2 ~V~~,
Green’s formulayields
where da is surface measure.
First, by
Theorem1.1,
hence
Secondly, by
Theorem 1.1 andFubini, for y
E(0, f],
we haveFinally,
for y E.~~,
chooset(y)
E[y, f)
such thatNote that
ing.
Thussince
w(t)lt
is decreas-Therefore, (3.1 ) provides
Recall that
weakly*
as E -0,
so the latter estimategives
= withf
EL2(Q).
Now we
investigate
the localintegrability properties
off.
As in[7], [13] and [14],
we considerdyadic martingales
on a cubeQo
=[0,
CR n,
l E
(o,1J . Namely,
let be theo,-algebra generated by
thedyadic
subcubes of
Qo
ofsidelenght 2"~, ~ ~
0. Themartingale
M =(Mk, corresponding
to the measure 1L =fdm,
is defined asMk
where
Qk
is adyadic
cube of rankk, k >
0.Define
AMk =
and(the martingale
difference functions and the square function of the
martingale).
It A is anw-Zygmund
measure, thenPut
limk-+oo
Recall that it =f dm,
soLebesgue’s
differentiation theorem
yields f (x)
at m-almost everypoint
x E R~ . On the other
hand, (3.2) gives
So
put Nk = Mk -
andapply
thefollowing
result ofChang,
Wilson and Wolff(see [7]) :
THEOREM C. Let be a real
dyadic martingale
onQo, No - 0,
and(2A)-1
oo. Then exists a.e. andProof of Theorem 1.5. - Part
(a).
Assume w does notsatisfy (1.3)
and consider a
singular w-symmetric
measure p on T(see
e.g.[1]). Identify
p and its"periodic" counterpart
on R. Thene-Itl dp(t)
is a finitew-symmetric
measure on R.
Now,
it is sufficient to observe that pi x A2 isw-symmetric
on
R 2
if J-l1 and p2 arew-symmetric
on R.Part
(b).
Assume c,~ satisfies(1.3).
Fix a cubeQ
C R~ with centerxo, 1. The
identity
and Green’s formulagive
Then Theorem 1.2
yields
On the other
hand,
we haveTherefore
where
o (A)
denotes aquantity
such thato (A) /A
tends to 0when Q ~
tendsto 0. Observe that for all x E
Q.
ThusThe
property
is established in the
proof
of Theorem 1.2(part (b)
F(a)).
HenceIt is well-known
(see
e.g.[8], Chapter 4)
that the latter estimateprovides
thefollowing
"local"Aoo-property:
There exist absolute constants 6 >0,
C > 0independent
of E such thatfor any measurable subset E of a cube
Q
CR’~, é(Q) x
1. Now it followseasily that p
isabsolutely continuous, /-t
=f drrz.
See for instance[8], Chapter
4 .To
investigate
theintegrals
overcubes,
weapply
anargument
from[14],
p. 34. So we considerdyadic martingales
on a cubeQo - [0, (0,1 . Namely, put
where
Qk
CQo
is adyadic
cube ofsidelenght 2-~.~, 1~ >
0.Since A
is
w-symmetric,
wehave
Now we consider thelogarithmic
transformMk
of themartingale Zk.
The identitiesMo ==
log Zo
= 0 andAMk
= arthZk-1 )I 1,
define thecorresponding
realmartingale
withuniformly
bounded differences. Moreprecisely,
Therefore,
as in theZygmund
case,since
oo,given
A >
0,
we obtainJ~
exp expoo since exp
(Mk - lj2Sk(M)).
The definition ofZk
andLebesgue’s
differentiation theorem
give
theequality
m-a.e.In other
words,
we have4.
Cubes and parallelepipeds.
This section is devoted to the
proof
of Lemma 2.3.Proof of Lemma 2.3. - We
represent
theparallelepiped L+
as a unionof
dyadic
cubes. Moreprecisely,
letUl
be the collection ofdyadic
cubes oflength f /2
which are contained inL+.
On thestep
we choose the cubes"of
generation
k"which are contained in
L+ B Uk-1 (here
is the union of the cubes selected on theprevious steps).
Let p
be aw-Zygmund
measure with constant C = 1.By induction,
we will compare
dyadic
cubes contained inL~ .
In whatfollows,
we use the"=b" notation for the
dyadic
setssymmetric
withrespect
to theorigin.
Inparticular, Q+ = (0, R)n
andQ- - (-R, 0)’.
We will showby
inductionthat
for any
dyadic
cubeStep
1. LetQl
CQ~
bedyadic
cubes ofgeneration
1. Without loss ofgenerality,
we assume thatC~i
=(0, f/2)n.
PutL+ = (0,
x(0, t/2)n-i
0jn.Thus
hence
On the other
hand,
thereforeStep
k -f- 1.Repeating
theargument
instep
1 we haveHence
Therefore, by
induction(4.1)
holds.Finally,
observe that there are at mostn2 k(n-1)
cubes ofgeneration
1~ in the
decomposition
ofL+.
Thus(4.1) gives
The
proof
iscompleted
in theZygmund
case.Now,
we consider sym- metric measures. Let p be aw-symmetric
measure and L aparallelepiped
with 1. For
l~ = 1, 2, ...,
letQk
denote a cube of thefamily Uk.
We will showand
Let us prove them for k = 0. We have
Hence We deduce
So
adding
the chain of estimates above weget
Therefore
Note also that
So,
we haveproved (4.2)
and(4.3)
for k = 0. When 1~ >0,
theproof proceeds by
inductionusing
the same idea.Finally,
we haveUsing (4.3),
weproceed recurrently
and estimate the latter double sum.Namely,
letAk
be the first term in theright
half side of(4.3),
that isFix k + 1 E N. First of
all,
there exist at mostn2 (k+l)(n- ’)
different cubesQ +1
CL+
ofgeneration
+ 1.Respectively,
the coefficient whichcorresponds
to and"originates"
on thestep k
+ m +1, nt e N,
is atmost i Hence
To finish the
argument,
oneonly
has to proveIndeed,
N solarge
thatThen, by (4.2)
This
yields
the estimate inquestion
and ends theproof
of thelemma. D
BIBLIOGRAPHY
[1]
A.B. ALEKSANDROV, J.M. ANDERSON and A. NICOLAU, Inner functions, Blochspaces and symmetric measures, Proc. London Math. Soc., 79
(1999),
318-352.[2]
J.M. ANDERSON, J.L. FERNANDEZ and A.L. SHIELDS, Inner functions and cyclicvectors in the Bloch space, Trans. Amer. Math. Soc., 323, no. 1
(1991),
429-448.[3]
C. BISHOP, Bounded functions in the little Bloch space, Pacific J. Math., 142(1990),
209-225.
[4]
J. BROSSARD, Intégrale d’aire et supports d’une mesure positive, C.R.A.S. Paris, Ser. I Math., 296(1983), 231-232.
[5]
L. CARLESON, On mappings, conformal at the boundary, J. d’Analyse Math., 19(1967),
1-13.[6]
J.J. CARMONA and J. DONAIRE, On removable singularities for the analytic Zygmund class, Michigan Math. J., 43(1996),
51-65.[7]
S.Y.A. CHANG, J.M. WILSON and T.H. WOLFF, Some weighted norm inequalities concerning the Schrödinger operator, Comment. Math. Helv., 60(1985),
217-246.[8]
J. GARCíA-CUERVA and J.L. RUBIO de FRANCIA, Weighted Norm Inequalities andRelated Topics, Math. Studies, 116, North-Holland, 1985.
[9]
P.L. DUREN, H.S. SHAPIRO and A. SHIELDS, Singular measures and domains not of Smirnov type, Duke Math. J., 33(1966),
247-254.[10]
R.A. FEFFERMAN, C.E. KENIG and J. PIPHER, The theory of weights and theDirichlet problem for elliptic equations, Ann. of Math., 134
(1991),
65-124.[11]
F.P. GARDINER and D.P. SULLIVAN, Symmetric structures on a closed curve, American J. Math., 114(1992),
683-736.[12]
J.P. KAHANE, Trois notes sur les ensembles parfaits linéaires, Enseignement Math.,15
(1969), 185-192.
[13]
J.G. LLORENTE, Boundary values of harmonic Bloch functions in Lipschitz do-mains : a martingale approach, Potential Analysis, 9
(1998),
229-260.[14]
N.G. MAKAROV, Probability methods in the theory of conformal mappings, Leningrad Math. J., 1(1990),
1-56.[15]
G. PIRANIAN, Two monotonic, singular, uniformly almost smooth functions, DukeMath. J., 33
(1966),
255-262.[16]
W. SMITH, Inner functions in the hyperbolic little Bloch class, Michigan Math. J., 45, no. 1(1998), 103-114.
[17]
E. STEIN, Singular integrals and differentiability properties of functions, PrincetonUniv. Press, 1970.
Manuscrit reCu le 25 septembre 2000, revise le 14 mai 2001,
accepté le 13 juillet 2001.
Evgueni DOUBTSOV, St Petersburg State University Department of Mathematical Analysis Bibliotechnaya pl. 2
Staryi Petergof
198904 St Petersburg
(Russia).
ed@ED8307.spb.edu
&
Artur NICOLAU,
Universitat Autonoma de Barcelona
Departament de Matematiques
08193 Bellaterra, Barcelona
(Spain).
artur~manwe.mat.uab.es