Contents lists available atScienceDirect
International Journal of Approximate Reasoning
www.elsevier.com/locate/ijar
Modus tollens with respect to uninorms: U -Modus Tollens
Isabel Aguiló
a,
b, Juan Vicente Riera
a,
b,∗ , Jaume Suñer
a,
b, Joan Torrens
a,
baSoftComputing,ImageProcessingandAggregation(SCOPIA)ResearchGroup,Dept.ofMathematicsandComputerScience,Universityof the BalearicIslands,Ctra.deValldemossa,Km.7.5,07122Palma,Spain
bBalearicIslandsHealthResearchInstitute(IdISBa),07010Palma,Spain
a r t i c l e i n f o a b s t r a c t
Articlehistory:
Received16January2020
Receivedinrevisedform6October2020 Accepted8October2020
Availableonline19October2020
Keywords:
ModusTollens Uninorm
Implicationfunction RU -implication
Infuzzylogicandapproximatereasoning theinferencerulegivenbytheModusTollens usually derives into an inequality involving three logical operators: a conjunction, an implicationfunctionandanegation.Untilnow,inthisscenariotheconjunctionhasbeen commonly modeled by a t-norm, but recently the possibility of using a more general conjunctionhasbeenpointedout.Inthiswork,wewanttogeneralizetheModusTollens inequality byusingaconjunctiveuninorm insteadofat-norm,leading tothe so-called U -ModusTollens.First,wegiveastudyofthisnewpropertyforimplicationfunctionsin generalandthenwespeciallyfocusonresidualimplicationsderivedfromuninorms.Inall cases,weprovethatthere arealotofsolutionsofthe U -ModusTollensand wegivea characterizationofallthesolutionsinsomeparticularcases.
©2020TheAuthors.PublishedbyElsevierInc.ThisisanopenaccessarticleundertheCC BY-NC-NDlicense(http://creativecommons.org/licenses/by-nc-nd/4.0/).
1. Introduction
Implicationfunctionsarecommonlyusednotonlytomodelfuzzyconditionals, butalsotocarry outall inferencepro- cessesinanyfuzzyrulebasedsystem.Thus,theimportanceofimplicationfunctionsmainlyliesintheirapplications,which cover awide rangeof differentfields,inparticular, all thosewhere fuzzycontrol andapproximatereasoningcan be ap- plied(seeforinstance[3,5,18]).Thisisalsothemainreasonforwhichitisimportanttohaveawiderangeofimplication functionstobeusedindifferentcontexts(see[29]).
Fromthetheoreticalpointofview,oneofthemaininterestingtopicsonimplicationfunctionsisthestudyandthechar- acterization ofthoseimplicationsthatsatisfycertainadditionalpropertiesthatusuallyarisefromtheconcreteapplications.
Therearemanyoftheseproperties,butwecanhighlightamongthemthosederivedfromthebasicinferencerules:Modus PonensandModusTollens(see [9,10,12]).Intheframeworkoffuzzylogic,theseinferencerulesareguaranteedwhenthe involvedlogicaloperatorssatisfythefollowingfunctionalinequalities,respectively:
T
(
x,
I(
x,
y)) ≤
y for all x,
y∈ [
0,
1],
(1)and
T
(
N(
y),
I(
x,
y)) ≤
N(
x)
for all x,
y∈ [
0,
1],
(2)*
Correspondingauthorat:SoftComputing,ImageProcessingandAggregation(SCOPIA)ResearchGroup,Dept.ofMathematicsandComputerScience, Universityofthe BalearicIslands,Ctra.deValldemossa,Km.7.5,07122Palma,Spain.E-mailaddresses:[email protected](I. Aguiló),[email protected](J.V. Riera),[email protected](J. Torrens).
https://doi.org/10.1016/j.ijar.2020.10.003
0888-613X/©2020TheAuthors.PublishedbyElsevierInc.ThisisanopenaccessarticleundertheCCBY-NC-NDlicense (http://creativecommons.org/licenses/by-nc-nd/4.0/).
whereT isat-norm, I isanimplicationfunctionandN isanegation.
When implicationfunctionshaveto be usedin managing inferenceprocesses, one ofthesetwo propertiesorboth of them are essential.Thus, dueto their significance,both inequalities havebeenlargely studied inthe literature formany authors(seeforinstance[2,3,16,18,26–28,30]).Firststudieswerecarriedoutforimplicationfunctionsderivedfromt-norms andt-conorms.Specifically,residuatedimplicationfunctionsand
(
S,
N)
-implicationswerestudiedin[2,26,27],whereasthe caseof Q L and D-implicationswas studiedin[28].Asageneralizationoftheseclassesofimplications,theircounterparts derived from more general kinds ofaggregation functions havebeen introduced, specially those derived fromuninorms like RU -implicationsand(
U,
N)
-implications(seeforinstance[1,4,6,17,22–24]).Recently,boththeModusPonensandthe Modus Tollens have been studied also for these two kinds of implications derived from uninorms, (see [16] and [15], respectively).Infact,althoughuninormswereinitiallyintroducedintheframeworkofaggregationfunctions(see[8,31]),theyhavealso beenstudiedandusedaslogicaloperatorsduetothefactthatthey arealwaysconjunctive(theirvalue inthepoint
(
0,
1)
is0)ordisjunctive(theirvaluein(
0,
1)
is1).Inparticular,conjunctiveuninormsarecommonlyusedasfuzzyconjunctions.Thus, the idea of substituting the t-norm T by a conjunctive uninorm U in the Modus Ponensand the Modus Tollens inference rules becomes naturaland it turns out to be an interesting line of research. Note that, in the Modus Ponens case,thisideawasalreadycarriedout in[19] leadingtotheso-calledU -Modus Ponens(orequivalently U -conditionality).
Initial resultsintheseworksprovethat theusualimplications derivedfromt-normsandt-conorms,aswell asgenerated Yager implications, never satisfy U -Modus Ponens, whereas implications derived fromuninorms appear to be the most suitable onesto satisfyit. Inthisdirection, thecaseof RU -implications hasalreadybeensolved in[19], andthe caseof
(
U,
N)
-implicationshasbeenrecentlystudiedin[20].Onthecontrary,asimilarstudyforthecaseoftheModusTollensisstillmissing.Inthispaper,wewanttodealprecisely withthistaskandwewanttostudy thesamegeneralizationoftheModusTollens.Thatis,wewanttostudytheproperty obtained from Equation (2) by substituting the t-norm T by a conjunctive uninorm U , that we will call the U -Modus Tollens:
U
(
N(
y),
I(
x,
y)) ≤
N(
x)
for all x,
y∈ [
0,
1],
(3)where U is aconjunctive uninorm, I is an implicationfunction andN is afuzzy negation.We wanttohighlight that in uninorm-basedfuzzylogics(see[14])apropositionP isconsideredtruewhenitsassignedvalueisgreaterthanorequalto e (wheree denotestheneutralelementofuninormU ).Inthiscontext,therulegivenbyEquation(3) couldbeinterpreted asfollows:“IfthevalueofnotQ isgreaterthanorequaltoe andthevalue of P
→
Q isgreaterthanorequaltoe,then thevalueofnotP isalsogreaterthanorequaltoe”.Thispaperisorganized asfollows.Afterthisintroduction,Section 2isdevotedtosome preliminariescompilingall the notationsandconceptsnecessarytofollowthearticle.InSection3theU -ModusTollensisintroducedanditisanalyzedfor generalimplicationfunctions.Section4isdevotedtothecaseofRU -implicationsderivedfromthethreemostusualclasses ofconjunctiveuninorms:uninormsin
U
min,representableuninorms andidempotentuninorms.Finally,Section 5includes someconclusionsandsomefutureworkproposals.2. Preliminaries
Werecallsomeconceptsthatwewillusealongthepaper.
Definition2.1.([11]) A function N
: [
0,
1] → [
0,
1]
is said to be a fuzzynegation if it is decreasing with N(
0) =
1 and N(
0) =
1.AfuzzynegationN issaidtobe•
Strict whenitisstrictlydecreasingandcontinuous.•
Strong whenitisaninvolution,i.e.,N(
N(
x)) =
x forallx∈ [
0,
1]
.Definition2.2.([3,7]) AbinaryoperatorI
: [
0,
1] × [
0,
1] → [
0,
1]
issaidtobeanimplicationfunction,oranimplication,ifit satisfies:(I1) I
(
x,
z) ≥
I(
y,
z)
whenx≤
y,forallz∈ [
0,
1]
. (I2) I(
x,
y) ≤
I(
x,
z)
when y≤
z,forallx∈ [
0,
1]
. (I3) I(
0,
0) =
I(
1,
1) =
1 andI(
1,
0) =
0.Notethatitfollowsfromthedefinition,that I
(
0,
x) =
1 and I(
x,
1) =
1 forallx∈ [
0,
1]
whereasthesymmetricalvalues I(
x,
0)
andI(
1,
x)
arenotderivedfromthedefinition.Specialinterestingpropertiesforimplicationfunctionsare:
•
Theneutralityproperty,I
(
1,
y) =
y for all y∈ [
0,
1].
(N P )•
Theidentityprinciple,I
(
x,
x) =
1 for all x∈ [
0,
1].
(I P )•
Thecontrapositiveproperty withrespecttoanegationNI
(
x,
y) =
I(
N(
y),
N(
x))
for all x,
y∈ [
0,
1].
(C P(
N)
)Definition2.3.([3,7]) Let I be a fuzzyimplication function. The function NI givenby NI
(
x) =
I(
x,
0)
forall x∈ [
0,
1]
is alwaysafuzzynegation,whichiscalledthenaturalnegation of I.Definition2.4.([8,31]) Auninorm isatwo-placefunctionU
: [
0,
1]
2−→ [
0,
1]
whichisassociative,commutative,increasing ineachplace,andsuchthatthereexistssomeelemente∈ [
0,
1]
,calledneutralelement,suchthatU(
e,
x) =
x forallx∈ [
0,
1]
.Itisclearthatuninormsgeneralizebotht-normsandt-conorms,sincetheyareretrievedfromuninormsjusttakinge
=
1 ande=
0,respectively.Foranyother valuee∈]
0,
1[
,theoperationworksasat-norminthesquare[
0,
e]
2,asat-conorm in[
e,
1]
2,anditsvaluesarebetweenminimumandmaximuminthesetofpoints A(
e)
givenbyA
(
e) = [
0,
e[ × ]
e,
1] ∪ ]
e,
1] × [
0,
e[.
We will usually denote a uninorm with neutralelement e and underlying t-norm T and t-conorm S, by U
≡
T,
e,
S. Moreover, forauninorm U ,itisalways U(
1,
0) ∈ {
0,
1}
andU issaid tobe conjunctive whenU(
1,
0) =
0,anddisjunctive whenU(
1,
0) =
1.Therearemanydifferentkindsofuninorms.Themostcommononescanbefoundin[13].Letusrecallherethestructure ofthethreemost-usedclassesofconjunctiveuninormsthatwillbeusedalongthepaper.
Proposition2.1.([8,13])LetU
: [
0,
1]
2→ [
0,
1]
beauninormwithneutralelemente∈ ]
0,
1[
.IfU(
0,
1) =
0,thenthefunction x→
U(
x,
1)
iscontinuousexceptforx=
e ifandonlyifU isgivenbyU
(
x,
y) =
⎧ ⎪
⎨
⎪ ⎩
eTxe
,
yeif
(
x,
y) ∈ [
0,
e]
2,
e+ (
1−
e)
S x−e 1−e,
1y−−eeif
(
x,
y) ∈ [
e,
1]
2,
min(
x,
y)
if(
x,
y) ∈
A(
e),
whereT isat-normandS isat-conorm.
Wewilldenoteby
U
minthefamilyoftheseuninormsandbyU≡
T,
e,
SmintheuninorminU
minwithneutralelement e andunderlyingt-norm T andt-conormS.Idempotentuninormswerecompletelycharacterizedforthegeneralcasein[25] inthefollowingway.
Proposition2.2.([25,13])AbinaryoperatorU
: [
0,
1]
2→ [
0,
1]
isanidempotentuninormwithneutralelemente∈ [
0,
1]
ifandonly ifthereexists adecreasingfunctiong: [
0,
1] → [
0,
1]
,symmetricwithrespecttothemaindiagonal,withg(
e) =
e,suchthatU
(
x,
y) =
⎧ ⎪
⎨
⎪ ⎩
min
(
x,
y)
if y<
g(
x)
or(
y=
g(
x)
and x<
g2(
x)),
max(
x,
y)
if y>
g(
x)
or(
y=
g(
x)
and x>
g2(
x)),
x or y if y=
g(
x)
and x=
g2(
x),
whereg2
(
x) =
g(
g(
x))
,beingU commutativeinthepoints(
x,
y)
suchthaty=
g(
x)
withx=
g2(
x)
.AnyidempotentuninormU withneutralelemente andassociatedfunction g willbedenotedbyU
≡
g,
eide,andthe class ofidempotent uninormswillbe denotedby Uide.Obviously,foranyoftheseuninormsthe underlyingt-norm TU is theminimumandtheunderlyingt-conormSU isthemaximum.Anotherwellknownclassofuninormsistheonegivenbyalluninormsthatcanberepresentedbyunaryfunctions.
Definition2.5.([8,13]) Auninorm U with neutralelement e
∈
]0,
1[ is said to be representable ifthere exists a strictly increasingandcontinuousfunctionh: [
0,
1] → [−∞, +∞]
withh(
0) = −∞
,h(
e) =
0 andh(
1) = +∞
suchthat U isgiven byU
(
x,
y) =
h−1(
h(
x) +
h(
y))
if(
x,
y) / ∈ {(
0,
1), (
1,
0)},
0(
or 1)
otherwise.
Functionh iscalledanadditivegeneratorofU .Thusitisclearthattherearetwodifferentrepresentableuninormswith thesamegeneratorh,aconjunctiveone(which isthenleft-continuous)andadisjunctiveone(whichisright-continuous).
Any representable uninorm U withneutralelement e andadditive generator h willbe denotedby U
≡
e,
hrep, andthe classofrepresentableuninormswillbedenotedbyUrep.Moreover,foranyrepresentableuninormU≡
e,
hrepthefunctionNh
(
x) =
h−1( −
h(
x))
for all x∈ [
0,
1]
isalwaysastrongnegationassociatedtotheuninormU .
Ontheother hand,differentclassesofimplications derivedfromuninorms havealsobeenstudied.Amongthem,only RU -implicationswillbeusedalongthepaperandforthisreasontheyarerecalledhere.
Definition2.6.([6]) LetU beauninorm.Theresidualoperation derivedfromU isthebinaryoperationgivenby
IU
(
x,
y) =
sup{
z∈ [
0,
1] |
U(
x,
z) ≤
y}
(4)forallx
,
y∈ [
0,
1]
.Proposition2.3.([6])LetU beauninormandIUitsresidualoperation.ThenIUisanimplication,calledRU -implication,ifandonly ifthefollowingconditionholds
U
(
x,
0) =
0 for all x<
1.
(5)Thispropertyincludesallconjunctiveuninormsbutalsomanydisjunctiveones,forinstancetheclassesofrepresentable andidempotentuninormswith g
(
0) =
1 (see[6] and[22]).However,whenwedealwithleft-continuousuninormsU ,we clearly havethat U satisfiescondition (5) if andonly ifit is conjunctive. There are some properties of RU -implications derived fromuninorm,that canbe deduceddirectlyfromthedefinition,orcan beproved inthe similarwaythat itwas doneforthosederivedfromt-norms.Formoredetailssee[6].3. Modustollenswithrespecttouninorms:U -ModusTollens
Aswehavealreadymentioned,themainobjectiveofthisworkisthestudy ofthegeneralization oftheModusTollens property obtainedby changingthet-norm T bya uninorm U ,ina similarwayasit was doneforthe ModusPonensin [19].ForobviousreasonswewillrefertothisgeneralizationastheU -ModusTollens.Thus,letusbeginbygivingtheformal definitionintheframeworkoffuzzylogic.
Definition3.1.LetI beafuzzyimplicationfunction,U auninormandN afuzzynegation.ItissaidthatI andN satisfythe U -ModusTollens propertywithrespecttoU when
U
(
N(
y),
I(
x,
y)) ≤
N(
x)
for all x,
y∈ [
0,
1].
(6)Note that the definition has been given for a uninorm in generaland not for a conjunctive one.1 This is because this propertyonU isdirectlyderivedfromthedefinitionofU -ModusTollensasitisprovedinthefollowingproposition.
Proposition3.1.LetI beafuzzyimplicationfunctionandN anegationthatsatisfytheU -ModusTollenswithrespecttoauninormU . ThentheuninormU mustnecessarilybeconjunctive.
Proof. If I and N satisfy the U -Modus Tollens with respect to U , just take x
=
1 and y=
0 in Equation (6) to obtain U(
N(
0),
I(
1,
0)) ≤
N(
1)
,thatis,U(
1,
0) =
0.Inviewofthepropositionabove,fromnowon,wewillconsideronlyconjunctiveuninormsintheU -ModusTollensprop- erty. By Definition 3.1,in general, U -Modus Tollensdepends on the uninorm U , the fuzzy implication I,and the fuzzy negation N. Example3.1showsthat,foranyconjunctiveuninorm U ,ifwe requireU -Modus Tollenstobevalidforsome particularnegationN,the admissibleimplicationsI dependonthechoiceofN.
Example3.1.Letusseehowthe U -Modus Tollensbehaves inthecases wheretheextremefuzzynegations are involved, thatis,whenweconsiderthesmallestandlargestfuzzynegations.
1 Recallthatat-normT isusedtomodelaconjunctioninfuzzylogic.Thus,thenormalgeneralizationwouldbetotakeaconjunctiveuninorm.
i) Letusconsiderthesmallestfuzzynegation N
=
ND1,givenby ND1(
x) =
1 if x=
0,
0 if x>
0.
Note that,if we take anyconjunctiveuninorm U andthe negation ND1,any implicationfunction I trivially satisfies Equation (6) forall y
>
0 (becausethen ND1(
y) =
0) andalso when x=
0 (becausethen ND1(
x) =
1). On theother hand,when y=
0 andx>
0 Equation(6) holdsifandonlyifU
(
N(
0),
I(
x,
0)) =
U(
1,
NI(
x)) ≤
N(
x) =
0,
which impliesNI
(
x) =
0 forall x>
0.Thus, we getthefollowing conclusion:“AnimplicationfunctionI satisfiestheU - ModusTollenswithrespecttoaconjunctiveuninormU andthefuzzynegationND1ifandonlyif NI=
ND1”.ii) Letusconsidernowthegreatestfuzzynegation N
=
ND2,givenby ND2(
x) =
1 if x
<
1,
0 if x=
1.
Asimilarargumentshowsthefollowingconclusion:“AnimplicationfunctionI fulfills theU -ModusTollenswithrespect toaconjunctiveuninormU andthefuzzynegationND2 ifandonlyifI
(
1,
y) =
0 forall y<
1”.Similarly tothe caseoft-norms, whenthe uninorm U isleft-continuous, wecan easily derivea generalresultabout U - ModusTollensasfollows.
Proposition3.2.LetU beaconjunctiveleft-continuousuninorm,IU itsresidualimplicationfunctionandN afuzzynegation.Then, animplicationfunctionI satisfiestheU -ModusTollenswithrespecttoU andN ifandonlyif
I
(
x,
y) ≤
IU(
N(
y),
N(
x))
for all x,
y∈ [
0,
1],
Proof. JustrecallthatwhenU isleft-continuoustheresiduationpropertyholds(see[6])andthen U
(
N(
y),
I(
x,
y)) ≤
N(
x) ⇐⇒
I(
x,
y) ≤
IU(
N(
y),
N(
x)).
However, the abovecondition doesnot holdwhen U is not left-continuousandmoreover, evenwhen itholds, itcan be difficult to check itin manycases. Thus,we want to deeplystudy the U -Modus Tollenscondition to give more spe- cific results. Afirst analysisof the U -Modus Tollensallows usto give some generalresults that we listin thefollowing proposition.
Proposition3.3.LetI beafuzzyimplicationfunctionandN anegationthatsatisfytheU -ModusTollenswithrespecttoaconjunctive uninormU .Lete betheneutralelementofU ,thenthefollowingpropertiesaresatisfied
1. U
(
N(
y),
I(
1,
y)) =
0 forally∈ [
0,
1]
.2. NI
(
x) ≤
N(
x)
forallx∈ [
0,
1]
.Also,forallx∈ [
0,
1]
suchthatNI(
x) ≥
e itmustbeN(
x) =
1.3. Take
α
N=
sup{
x∈ [
0,
1] |
N(
x) ≥
e}
.Then a) Ifα
N=
0 thenN(
x) <
e forallx>
0.b) If
α
N>
0 thenitmustbeI(
1,
y) =
0 forally< α
N. 4. IfI satisfies(N P),thenα
N=
0.5. IfI satisfies(I P) andN isnonfilling(N
(
x) <
1 forx>
0),itmustbeα
N=
0.Proof. Letusprovethemstepbystep.
1. ThisfirstitemisadirectconsequenceoftheU -ModusTollensproperty,justtakingx
=
1 inEquation(6).2. Consider NI
(
x) =
I(
x,
0)
,thenwehaveNI
(
x) =
U(
e,
I(
x,
0)) ≤
U(
1,
I(
x,
0)) ≤
N(
x),
wherethelastinequalityfollowsbytakingy
=
0 inEquation(6).Ontheotherhand,ifNI
(
x) ≥
e,takingagainy=
0 inEquation(6),weobtain N(
x) ≥
U(
N(
0),
I(
x,
0)) =
U(
1,
NI(
x)) ≥
U(
1,
e) =
1.
3. Letusconsidernow
α
N=
sup{
x∈ [
0,
1] |
N(
x) ≥
e}
.a) If
α
N=
0,wedirectlyderivefromthedefinitionofα
N that N(
x) <
e forallx>
0.b) If
α
N>
0 wegetN(
y) ≥
e forall y< α
N andconsequently, I(
1,
y) =
U(
e,
I(
1,
y)) ≤
U(
N(
y),
I(
1,
y)) ≤
N(
1) =
0,
thatis,I
(
1,
y) =
0 forall y< α
N.4. If
α
N>
0,wegetI(
1,
y) =
0 forall y< α
N andconsequentlyI doesnotsatisfy(N P).5. Suppose inthiscasethat I
(
x,
x) =
1 forall x∈ [
0,
1]
andN(
x) <
1 for x>
0.Inthiscase, supposeagainthatthere is somex>
0 withN(
x) ≥
e.Takingx=
y inExpression(6) wewillgetN
(
x) ≥
U(
N(
x),
I(
x,
x)) ≥
U(
e,
1) =
1,
whichisacontradiction.Thus,itmustbeagainN
(
x) <
e forallx>
0 andconsequently,α
N=
0. Remark3.1.SomeinterestingconsequencescanbederivedfromProposition3.3asfollows.(i) IfwewanttodealwithcontinuousfuzzynegationsintheU -ModusPonens,thenwewillhave
α
N>
0.FromItem4in Proposition3.3wegetthat anypossiblesolutionoftheU -ModusPonensfailsto satisfy(N P).Consequently,allusual implicationsderivedfromt-normsandt-conorms(thatis,R,(
S,
N)
,Q L andD-implications),aswellasYagergenerated implications,never satisfy U -ModusTollens(sinceall ofthemsatisfy (N P)).Fortunately, we willseeinnext sections thatmanysolutionscanbefoundamongthoseimplicationsderivedfromuninorms,especiallyamongRU -implications.(ii) On the other hand, if we want to consider implication functions satisfying (N P), the same argument leads to the necessityofconsideringnegationswith
α
N=
0,thatis,negations N suchthat N(
x) <
e forallx>
0 andconsequently, non-continuous.Intherestofthissectionwewilldealwiththecase
α
N=
0 andalsowhentheinvolvedimplications satisfy(N P).We willcharacterizeinparticularall solutionsinthecasewhenthenegation N isstrictlydecreasingintheinterval]
0,
e[
and U isauninorminU
min.Westartbyprovingthatforthiskindofuninorms,U-ModusTollensalwaysholdsforallx≤
y and soitissufficienttoproveitfor(
x,
y)
suchthat y<
x.Proposition3.4.LetI beanimplicationfunction,N afuzzynegationwith
α
N=
0,andU auninorminU
minwithneutralelement e∈]
0,
1[
.ThenI,
N satisfytheU -ModusTollenswithrespecttoU ifandonlyifU
(
N(
y),
I(
x,
y)) ≤
N(
x)
for all y<
x.
Proof. WeonlyneedtoprovethattheU -ModusTollensisalwayssatisfiedinpointswherex
≤
y.Sinceitisobviouswhen x=
0,wedealwithvalues0<
x≤
y.InthiscasewehaveN(
y) ≤
N(
x)
andsinceα
N=
0,itisN(
x) <
e forall x>
0.Then wehavetwocases:a) IfI
(
x,
y) >
e,thenU
(
N(
y),
I(
x,
y)) ≤
U(
N(
x),
I(
x,
y)) =
min{
N(
x),
I(
x,
y) } =
N(
x).
b) IfI
(
x,
y) ≤
e,thenU
(
N(
y),
I(
x,
y)) ≤
U(
N(
x),
I(
x,
y)) =
eTU N(
x)
e,
I(
x,
y)
e
≤
e N(
x)
e
=
N(
x).
Wenowstudythecaseinwhichtheimplication I satisfies(N P),whichisthecaseofmostoftheimplicationsderived fromt-normsandt-conorms.
Proposition3.5.LetI beanimplicationfunctionthatsatisfies(N P),N afuzzynegation,andU aconjunctiveuninormwithneutral elemente
∈]
0,
1[
.IfI,
N satisfytheU -ModusTollenswithrespecttoU ,then:1. U
(
N(
y),
y) =
0 forally∈ [
0,
1]
.2. N
(
x) =
0 forallx≥
e andN(
x) <
e forallx>
0.3. U
(
N(
y),
I(
e,
y)) =
0 forally∈ [
0,
1]
.4. IfN isstrictlydecreasingintheinterval
]
0,
e[
,thenI(
x,
y) <
e forally<
x<
e.Proof. Letusproveallitemsonebyone.
1. U
(
N(
y),
y) =
0 forall y∈ [
0,
1]
followsdirectlybytakingx=
1 inEquation(6) since I satisfies(N P).2. AccordingtoProposition3.3weknowthatifI satisfies(N P),then
α
N=
0 andN(
x) <
e forallx>
0.Moreover,justby putting y=
e intheprevious condition,we obtain N(
e) =
U(
N(
e),
e) =
0 andconsequently, N(
x) =
0 forall x≥
e,by decreasingness.3. Now,takingx
=
e inEquation(6) wegetU(
N(
y),
I(
e,
y)) ≤
N(
e) =
0,andsoU(
N(
y),
I(
e,
y)) =
0 forall y∈ [
0,
1]
. 4. To prove thisitem letusconsider some x,
y such that y<
x<
e and supposethat I(
x,
y) >
e.First, note that y>
0becauseI
(
x,
0) =
NI(
x) ≤
N(
x) <
e.Consequently,wehaveN(
y) <
e andso,sinceN isstrictlydecreasingin]
0,
e[
,U
(
N(
y),
I(
x,
y)) ≥
min{
N(
y),
I(
x,
y) } =
N(
y) >
N(
x),
leadingtoacontradiction.Thus,weobtainI
(
x,
y) <
e forall y<
x<
e.WhenN isanegationstrictlydecreasingintheinterval
]
0,
e[
andtheimplicationI satisfies(N P),wecangiveacharac- terizationofthoseuninormsinU
minthatsatisfytheU -ModusTollens,asfollows.Theorem3.1.LetI beanimplicationfunctionthatsatisfies(N P),U
≡
TU,
e,
SUminauninorminU
minwithneutralelemente∈ ]
0,
1[
,andN afuzzynegationstrictlydecreasingin]
0,
e[
.ThenI,
N satisfytheU -ModusTollenswithrespecttoU ifandonlyifthe followingpropertieshold:1. U
(
N(
y),
I(
e,
y)) =
0 forally∈ [
0,
1]
.2. N
(
x) =
0 forallx≥
e andN(
x) <
e forallx>
0.3. I
(
x,
y) <
e forally<
x<
e.4. IandNverifytheModusTollenswithrespecttoTUforally
<
x,whereIandNaregivenbyI
(
x,
y) =
1 if x
≤
y,
I(ex,ey)
e if y
<
x.
(7)N
(
x) =
1 if x=
0,
N(ex)
e otherwise
.
(8)Proof. Let ussupposefirstthat I and N satisfythe U -Modus Tollenswithrespectto U .Properties 1,2and3holdfrom Proposition3.5andthus,weonlyneedtoprovethat IandN satisfytheModusTollenswithrespectto TU forall y
<
x.Wewilldistinguishtwocases:
•
If y=
0 then,TU
(
N(
y),
I(
x,
0)) =
TU1
,
I(
ex,
0)
e=
I(
ex,
0)
e
=
NI(
ex)
e
≤
N(
ex)
e
=
N(
x),
wherethelastinequalityisduetoProposition3.3.
•
If y>
0,wehaveTU
(
N(
y),
I(
x,
y)) =
TU N(
ey)
e
,
I(
ex,
ey)
e=
U(
N(
ey),
I(
ex,
ey))
e
≤
N(
ex)
e
=
N(
x),
wherethelastinequalityholdsbecauseI
,
N satisfyU -ModusTollenswithrespecttoU .Conversely, supposethat conditions1-4holdandwewill provethat I
,
N satisfy theU -Modus Tollenswithrespectto U . According to Proposition3.4 the U -Modus Tollensneeds to be checkedonly inpoints(
x,
y)
where y<
x. Thus, we will considerthreecases:•
If y=
0,thenU
(
N(
y),
I(
x,
y)) =
U(
1,
I(
x,
0)) =
U(
1,
NI(
x)) =
NI(
x),
wherethelastequalityholdsbecauseU
∈ U
min.ThentheresultfollowsfromProposition3.3.•
If0<
y<
x<
e thenI(
x,
y) <
e and N(
y) <
e byconditions3and2,respectively.Inthiscase, U(
N(
y),
I(
x,
y)) =
e·
TU N(
y)
e,
I(
x,
y)
e
=
e·
TU N y e,
I x e,
ye
≤
e·
Nx e=
N(
x),
wherethelastinequalityholdsfromcondition4.
Fig. 1. Plot of the fuzzy negation Ne(left) and structure of the fuzzy implication Ie (right) given in Example3.2.
•
Ifx≥
e,thenI(
x,
y) ≤
I(
e,
y)
andhence,U
(
N(
y),
I(
x,
y)) ≤
U(
N(
y),
I(
e,
y)) =
0,
whereinthiscasethelastequalityisduetocondition1.
Remark3.2.Letuspointouttwointerestingfacts.
i) According to the theorem above, the proof that I
,
N satisfy the U -Modus Tollens with respect to a uninorm U≡
TU,
e,
SUmin inU
min, requires in particular to check that I and N satisfy the Modus Tollens withrespect to TU. However, thisquestion was alreadysolved in[26,27] and consequently, our characterizationtheorem iscomplete. In fact,manyexamplescanbederivedfromconditionsinTheorem3.1(seeExample3.2below).ii) NotethatinTheorem3.1,thet-conormSU playsnoroleinthesatisfactionoftheU -ModusTollensandso,SU canbe anyt-conorm.Moreover,thesamepropertyholdswhenthevaluesoftheimplicationI areoutoftherectangle
[
0,
e[
2, withtheuniqueconditionthatitsatisfies(N P).Example3.2.Letusconsidertheuninormin
U
min,U≡
TU,
e,
SUminwhereTU=
TLK istheŁukasiewiczt-normandSU is anyt-conorm.LetNe bethenegationgivenbyNe
(
x) =
⎧ ⎪
⎨
⎪ ⎩
1 if x
=
0,
e−
x if 0<
x<
e,
0 if x≥
e.
Ontheotherhand,weconsiderthefollowingfuzzyimplication
Ie
(
x,
y) =
⎧ ⎪
⎨
⎪ ⎩
1 if x
=
0 or y=
1,
max
(
e−
x,
y)
if 0<
x≤
e and 0≤
y≤
e,
y otherwise
.
It is easy to seethat these operators satisfy all the conditionsof Theorem 3.1and therefore Ie
,
Ne satisfy the U -Modus TollenswithrespecttotheuninormU (Fig.1).4. ModusTollensforR U -implications
Inthissection,givenaconjunctiveuninormU andafuzzynegationN,wewillinvestigatewhichRU -implicationssatisfy theU -ModusTollensinequality.WewilldoitforRU -implicationsderivedfromthethreeclassesofuninormsrecalledinthe preliminaries.Notethatintheprevioussectionwehaveseenthat,forfuzzynegationsN with
α
N>
0 (casethatincludesall continuousnegations),onlyimplications I suchthat I(
1,
y) =
0 forall y< α
N cansatisfytheU -ModusTollens.Fortunately, thisconditionissatisfiedby RU -implicationsderivedfromrepresentableuninormsandforsomeidempotentsonesandso, inthesecaseswewillseethatcontinuous(evenstrictandstrong)negationscanbeconsidered.WewillstudytheU -ModusTollens forRU -implicationsderivedfromuninormsintheclassof
U
min,fromrepresentable uninormsandfromidempotentuninorms,andwewilldevoteasubsectiontoeachofthesecases.4.1. CaseofRU -implications derivedfromuninormsin
U
minIn this subsection, we will deal with RU -implications derived from uninorms in
U
min, that is, uninorms U0≡
T0,
e0,
S0min withneutral element e0∈]
0,
1[
and underlyingt-norm andt-conorm T0 and S0, respectively. Recall that forthiskindofuninorms,RU -implicationsaregivenbythefollowingstructure.Proposition4.1.(Theorem5.4.7in[3])LetU
≡
TU,
e,
SUminbeauninorminU
minandIU itsresidualimplication.ThenIU
(
x,
y) =
⎧ ⎪
⎪ ⎪
⎪ ⎨
⎪ ⎪
⎪ ⎪
⎩
1 if x
≤
y<
e,
eITU
(
ex,
ey)
if y<
x≤
e,
e+ (
1−
e)
ISU(
x1−−ee,
1y−−ee)
if e≤
x≤
y,
e if e
≤
y<
x,
y otherwise
.
(9)
Forthiskindof RU -implicationswe againgetthat the U -Modus Tollenscan besatisfied onlywithnegations N with
α
N=
0 andconsequently,withnon-continuousnegations.Moreover,forthiskindofRU -implicationswehavethefollowing result.Proposition4.2.LetIU0 beafuzzyimplicationderivedfromU0
≡
T0,
e0,
S0min,N afuzzynegation,andU≡
TU,
e,
SUacon- junctiveuninorm.IfIU0,
N satisfy theU -ModusTollenswithrespecttoU ,thenthefollowingpropertieshold:1. U
(
N(
y),
y) =
0 forally≤
e0. 2. U(
N(
y),
1) =
N(
y)
forally<
e0. 3.α
N=
0 (thatis,N(
x) <
e forallx>
0).4. Ife
≤
e0N(
x) =
0 forallx≥
e.5. Ife0
<
e,TUisacontinuoust-normandU(
e0,
e0) =
e0,thenN(
x) <
e0forallx>
0 andN(
x) =
0 forallx≥
e0.Proof. 1. FollowsdirectlyfromEquation(6) byputtingx
=
1 andtakingintoaccountthatIU0(
1,
y) =
y forall y≤
e0. 2. Foranyx<
e0,wehaveIU0(
x,
x) =
1 andifwetakex=
y inEquation(6),wehaveU
(
N(
y),
IU0(
y,
y)) =
U(
N(
y),
1) ≤
N(
y).
Theresultfollowsfromthefactthat U
(
N(
y),
1) ≥
N(
y)
holdsalways.3. ItisadirectconsequenceofProposition3.3,becauseitis IU0
(
1,
y) >
0 forall y>
0.4. Ifwetake y
=
e inProperty1,wehaveU(
N(
e),
e) =
N(
e) =
0 andbydecreasingness,N(
x) =
0 forallx≥
e.5. First,letusseethat N
(
x) <
e0 forall0<
x<
e0.Indeed,since TU iscontinuous ande0<
e isan idempotentelement, ifwehavethat N(
x) ≥
e0withe0>
x>
0,thenU
(
e0,
x) =
x for all 0≤
x≤
e0 (10)andthen,applyingProperty1weget
0
=
U(
N(
x),
x) ≥
U(
e0,
x) =
xleadingtoacontradiction.Now,wehavethatN
(
x) <
e0forallx>
0 bydecreasingness,andweonlyneedtoprovethat N(
e0) =
0 toconcludetheproof.ButthisisclearbecauseN(
e0) <
e0andthen0
=
U(
N(
e0),
e0) =
N(
e0),
wherethefirstequalityisduetoProperty1andthesecondisduetoEquation(10).
Inordertocharacterizethesolutionsinthiscase,wewilldistinguishthreedifferentpossibilitiesaccordingtotheorder oftheneutralelementse ande0.Webeginbythemostsimplecasewhenbothelementscoincide.
Theorem4.1.LetIU0betheRU -implicationderivedfromU0
≡
T0,
e0,
S0min,N afuzzynegation,andU≡
TU,
e,
SUaconjunc- tiveuninormwithneutralelemente=
e0.ThenIU0andN satisfytheU -ModusTollenswithrespecttoU ,ifandonlyifthefollowing propertieshold1. U
(
N(
y),
y) =
0 forally≤
e,andU(
N(
y),
1) =
N(
y)
forally<
e.2. N
(
x) <
e forallx>
0,andN(
x) =
0 forallx≥
e.3. IT0andNsatisfytheModusTollenswithrespecttothet-normTUforally