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Contents lists available atScienceDirect

International Journal of Approximate Reasoning

www.elsevier.com/locate/ijar

Modus tollens with respect to uninorms: U -Modus Tollens

Isabel Aguiló

a

,

b

, Juan Vicente Riera

a

,

b

,∗ , Jaume Suñer

a

,

b

, Joan Torrens

a

,

b

aSoftComputing,ImageProcessingandAggregation(SCOPIA)ResearchGroup,Dept.ofMathematicsandComputerScience,Universityof the BalearicIslands,Ctra.deValldemossa,Km.7.5,07122Palma,Spain

bBalearicIslandsHealthResearchInstitute(IdISBa),07010Palma,Spain

a r t i c l e i n f o a b s t r a c t

Articlehistory:

Received16January2020

Receivedinrevisedform6October2020 Accepted8October2020

Availableonline19October2020

Keywords:

ModusTollens Uninorm

Implicationfunction RU -implication

Infuzzylogicandapproximatereasoning theinferencerulegivenbytheModusTollens usually derives into an inequality involving three logical operators: a conjunction, an implicationfunctionandanegation.Untilnow,inthisscenariotheconjunctionhasbeen commonly modeled by a t-norm, but recently the possibility of using a more general conjunctionhasbeenpointedout.Inthiswork,wewanttogeneralizetheModusTollens inequality byusingaconjunctiveuninorm insteadofat-norm,leading tothe so-called U -ModusTollens.First,wegiveastudyofthisnewpropertyforimplicationfunctionsin generalandthenwespeciallyfocusonresidualimplicationsderivedfromuninorms.Inall cases,weprovethatthere arealotofsolutionsofthe U -ModusTollensand wegivea characterizationofallthesolutionsinsomeparticularcases.

©2020TheAuthors.PublishedbyElsevierInc.ThisisanopenaccessarticleundertheCC BY-NC-NDlicense(http://creativecommons.org/licenses/by-nc-nd/4.0/).

1. Introduction

Implicationfunctionsarecommonlyusednotonlytomodelfuzzyconditionals, butalsotocarry outall inferencepro- cessesinanyfuzzyrulebasedsystem.Thus,theimportanceofimplicationfunctionsmainlyliesintheirapplications,which cover awide rangeof differentfields,inparticular, all thosewhere fuzzycontrol andapproximatereasoningcan be ap- plied(seeforinstance[3,5,18]).Thisisalsothemainreasonforwhichitisimportanttohaveawiderangeofimplication functionstobeusedindifferentcontexts(see[29]).

Fromthetheoreticalpointofview,oneofthemaininterestingtopicsonimplicationfunctionsisthestudyandthechar- acterization ofthoseimplicationsthatsatisfycertainadditionalpropertiesthatusuallyarisefromtheconcreteapplications.

Therearemanyoftheseproperties,butwecanhighlightamongthemthosederivedfromthebasicinferencerules:Modus PonensandModusTollens(see [9,10,12]).Intheframeworkoffuzzylogic,theseinferencerulesareguaranteedwhenthe involvedlogicaloperatorssatisfythefollowingfunctionalinequalities,respectively:

T

(

x

,

I

(

x

,

y

))

y for all x

,

y

∈ [

0

,

1

],

(1)

and

T

(

N

(

y

),

I

(

x

,

y

))

N

(

x

)

for all x

,

y

∈ [

0

,

1

],

(2)

*

Correspondingauthorat:SoftComputing,ImageProcessingandAggregation(SCOPIA)ResearchGroup,Dept.ofMathematicsandComputerScience, Universityofthe BalearicIslands,Ctra.deValldemossa,Km.7.5,07122Palma,Spain.

E-mailaddresses:[email protected](I. Aguiló),[email protected](J.V. Riera),[email protected](J. Torrens).

https://doi.org/10.1016/j.ijar.2020.10.003

0888-613X/©2020TheAuthors.PublishedbyElsevierInc.ThisisanopenaccessarticleundertheCCBY-NC-NDlicense (http://creativecommons.org/licenses/by-nc-nd/4.0/).

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whereT isat-norm, I isanimplicationfunctionandN isanegation.

When implicationfunctionshaveto be usedin managing inferenceprocesses, one ofthesetwo propertiesorboth of them are essential.Thus, dueto their significance,both inequalities havebeenlargely studied inthe literature formany authors(seeforinstance[2,3,16,18,26–28,30]).Firststudieswerecarriedoutforimplicationfunctionsderivedfromt-norms andt-conorms.Specifically,residuatedimplicationfunctionsand

(

S

,

N

)

-implicationswerestudiedin[2,26,27],whereasthe caseof Q L and D-implicationswas studiedin[28].Asageneralizationoftheseclassesofimplications,theircounterparts derived from more general kinds ofaggregation functions havebeen introduced, specially those derived fromuninorms like RU -implicationsand

(

U

,

N

)

-implications(seeforinstance[1,4,6,17,22–24]).Recently,boththeModusPonensandthe Modus Tollens have been studied also for these two kinds of implications derived from uninorms, (see [16] and [15], respectively).

Infact,althoughuninormswereinitiallyintroducedintheframeworkofaggregationfunctions(see[8,31]),theyhavealso beenstudiedandusedaslogicaloperatorsduetothefactthatthey arealwaysconjunctive(theirvalue inthepoint

(

0

,

1

)

is0)ordisjunctive(theirvaluein

(

0

,

1

)

is1).Inparticular,conjunctiveuninormsarecommonlyusedasfuzzyconjunctions.

Thus, the idea of substituting the t-norm T by a conjunctive uninorm U in the Modus Ponensand the Modus Tollens inference rules becomes naturaland it turns out to be an interesting line of research. Note that, in the Modus Ponens case,thisideawasalreadycarriedout in[19] leadingtotheso-calledU -Modus Ponens(orequivalently U -conditionality).

Initial resultsintheseworksprovethat theusualimplications derivedfromt-normsandt-conorms,aswell asgenerated Yager implications, never satisfy U -Modus Ponens, whereas implications derived fromuninorms appear to be the most suitable onesto satisfyit. Inthisdirection, thecaseof RU -implications hasalreadybeensolved in[19], andthe caseof

(

U

,

N

)

-implicationshasbeenrecentlystudiedin[20].

Onthecontrary,asimilarstudyforthecaseoftheModusTollensisstillmissing.Inthispaper,wewanttodealprecisely withthistaskandwewanttostudy thesamegeneralizationoftheModusTollens.Thatis,wewanttostudytheproperty obtained from Equation (2) by substituting the t-norm T by a conjunctive uninorm U , that we will call the U -Modus Tollens:

U

(

N

(

y

),

I

(

x

,

y

))

N

(

x

)

for all x

,

y

∈ [

0

,

1

],

(3)

where U is aconjunctive uninorm, I is an implicationfunction andN is afuzzy negation.We wanttohighlight that in uninorm-basedfuzzylogics(see[14])apropositionP isconsideredtruewhenitsassignedvalueisgreaterthanorequalto e (wheree denotestheneutralelementofuninormU ).Inthiscontext,therulegivenbyEquation(3) couldbeinterpreted asfollows:“IfthevalueofnotQ isgreaterthanorequaltoe andthevalue of P

Q isgreaterthanorequaltoe,then thevalueofnotP isalsogreaterthanorequaltoe”.

Thispaperisorganized asfollows.Afterthisintroduction,Section 2isdevotedtosome preliminariescompilingall the notationsandconceptsnecessarytofollowthearticle.InSection3theU -ModusTollensisintroducedanditisanalyzedfor generalimplicationfunctions.Section4isdevotedtothecaseofRU -implicationsderivedfromthethreemostusualclasses ofconjunctiveuninorms:uninormsin

U

min,representableuninorms andidempotentuninorms.Finally,Section 5includes someconclusionsandsomefutureworkproposals.

2. Preliminaries

Werecallsomeconceptsthatwewillusealongthepaper.

Definition2.1.([11]) A function N

: [

0

,

1

] → [

0

,

1

]

is said to be a fuzzynegation if it is decreasing with N

(

0

) =

1 and N

(

0

) =

1.AfuzzynegationN issaidtobe

Strict whenitisstrictlydecreasingandcontinuous.

Strong whenitisaninvolution,i.e.,N

(

N

(

x

)) =

x forallx

∈ [

0

,

1

]

.

Definition2.2.([3,7]) AbinaryoperatorI

: [

0

,

1

] × [

0

,

1

] → [

0

,

1

]

issaidtobeanimplicationfunction,oranimplication,ifit satisfies:

(I1) I

(

x

,

z

)

I

(

y

,

z

)

whenx

y,forallz

∈ [

0

,

1

]

. (I2) I

(

x

,

y

)

I

(

x

,

z

)

when y

z,forallx

∈ [

0

,

1

]

. (I3) I

(

0

,

0

) =

I

(

1

,

1

) =

1 andI

(

1

,

0

) =

0.

Notethatitfollowsfromthedefinition,that I

(

0

,

x

) =

1 and I

(

x

,

1

) =

1 forallx

∈ [

0

,

1

]

whereasthesymmetricalvalues I

(

x

,

0

)

andI

(

1

,

x

)

arenotderivedfromthedefinition.

Specialinterestingpropertiesforimplicationfunctionsare:

Theneutralityproperty,

I

(

1

,

y

) =

y for all y

∈ [

0

,

1

].

(N P )

(3)

Theidentityprinciple,

I

(

x

,

x

) =

1 for all x

∈ [

0

,

1

].

(I P )

Thecontrapositiveproperty withrespecttoanegationN

I

(

x

,

y

) =

I

(

N

(

y

),

N

(

x

))

for all x

,

y

∈ [

0

,

1

].

(C P

(

N

)

)

Definition2.3.([3,7]) Let I be a fuzzyimplication function. The function NI givenby NI

(

x

) =

I

(

x

,

0

)

forall x

∈ [

0

,

1

]

is alwaysafuzzynegation,whichiscalledthenaturalnegation of I.

Definition2.4.([8,31]) Auninorm isatwo-placefunctionU

: [

0

,

1

]

2

−→ [

0

,

1

]

whichisassociative,commutative,increasing ineachplace,andsuchthatthereexistssomeelemente

∈ [

0

,

1

]

,calledneutralelement,suchthatU

(

e

,

x

) =

x forallx

∈ [

0

,

1

]

.

Itisclearthatuninormsgeneralizebotht-normsandt-conorms,sincetheyareretrievedfromuninormsjusttakinge

=

1 ande

=

0,respectively.Foranyother valuee

∈]

0

,

1

[

,theoperationworksasat-norminthesquare

[

0

,

e

]

2,asat-conorm in

[

e

,

1

]

2,anditsvaluesarebetweenminimumandmaximuminthesetofpoints A

(

e

)

givenby

A

(

e

) = [

0

,

e

[ × ]

e

,

1

] ∪ ]

e

,

1

] × [

0

,

e

[.

We will usually denote a uninorm with neutralelement e and underlying t-norm T and t-conorm S, by U

T

,

e

,

S

. Moreover, forauninorm U ,itisalways U

(

1

,

0

) ∈ {

0

,

1

}

andU issaid tobe conjunctive whenU

(

1

,

0

) =

0,anddisjunctive whenU

(

1

,

0

) =

1.

Therearemanydifferentkindsofuninorms.Themostcommononescanbefoundin[13].Letusrecallherethestructure ofthethreemost-usedclassesofconjunctiveuninormsthatwillbeusedalongthepaper.

Proposition2.1.([8,13])LetU

: [

0

,

1

]

2

→ [

0

,

1

]

beauninormwithneutralelemente

∈ ]

0

,

1

[

.IfU

(

0

,

1

) =

0,thenthefunction x

U

(

x

,

1

)

iscontinuousexceptforx

=

e ifandonlyifU isgivenby

U

(

x

,

y

) =

⎧ ⎪

⎪ ⎩

eT



x

e

,

ye



if

(

x

,

y

) ∈ [

0

,

e

]

2

,

e

+ (

1

e

)

S



xe 1e

,

1yee

if

(

x

,

y

) ∈ [

e

,

1

]

2

,

min

(

x

,

y

)

if

(

x

,

y

)

A

(

e

),

whereT isat-normandS isat-conorm.

Wewilldenoteby

U

minthefamilyoftheseuninormsandbyU

T

,

e

,

S

mintheuninormin

U

minwithneutralelement e andunderlyingt-norm T andt-conormS.

Idempotentuninormswerecompletelycharacterizedforthegeneralcasein[25] inthefollowingway.

Proposition2.2.([25,13])AbinaryoperatorU

: [

0

,

1

]

2

→ [

0

,

1

]

isanidempotentuninormwithneutralelemente

∈ [

0

,

1

]

ifandonly ifthereexists adecreasingfunctiong

: [

0

,

1

] → [

0

,

1

]

,symmetricwithrespecttothemaindiagonal,withg

(

e

) =

e,suchthat

U

(

x

,

y

) =

⎧ ⎪

⎪ ⎩

min

(

x

,

y

)

if y

<

g

(

x

)

or

(

y

=

g

(

x

)

and x

<

g2

(

x

)),

max

(

x

,

y

)

if y

>

g

(

x

)

or

(

y

=

g

(

x

)

and x

>

g2

(

x

)),

x or y if y

=

g

(

x

)

and x

=

g2

(

x

),

whereg2

(

x

) =

g

(

g

(

x

))

,beingU commutativeinthepoints

(

x

,

y

)

suchthaty

=

g

(

x

)

withx

=

g2

(

x

)

.

AnyidempotentuninormU withneutralelemente andassociatedfunction g willbedenotedbyU

g

,

e

ide,andthe class ofidempotent uninormswillbe denotedby Uide.Obviously,foranyoftheseuninormsthe underlyingt-norm TU is theminimumandtheunderlyingt-conormSU isthemaximum.

Anotherwellknownclassofuninormsistheonegivenbyalluninormsthatcanberepresentedbyunaryfunctions.

Definition2.5.([8,13]) Auninorm U with neutralelement e

]0

,

1[ is said to be representable ifthere exists a strictly increasingandcontinuousfunctionh

: [

0

,

1

] → [−∞, +∞]

withh

(

0

) = −∞

,h

(

e

) =

0 andh

(

1

) = +∞

suchthat U isgiven by

U

(

x

,

y

) =

h1

(

h

(

x

) +

h

(

y

))

if

(

x

,

y

) / ∈ {(

0

,

1

), (

1

,

0

)},

0

(

or 1

)

otherwise

.

(4)

Functionh iscalledanadditivegeneratorofU .Thusitisclearthattherearetwodifferentrepresentableuninormswith thesamegeneratorh,aconjunctiveone(which isthenleft-continuous)andadisjunctiveone(whichisright-continuous).

Any representable uninorm U withneutralelement e andadditive generator h willbe denotedby U

e

,

h

rep, andthe classofrepresentableuninormswillbedenotedbyUrep.Moreover,foranyrepresentableuninormU

e

,

h

repthefunction

Nh

(

x

) =

h1

(

h

(

x

))

for all x

∈ [

0

,

1

]

isalwaysastrongnegationassociatedtotheuninormU .

Ontheother hand,differentclassesofimplications derivedfromuninorms havealsobeenstudied.Amongthem,only RU -implicationswillbeusedalongthepaperandforthisreasontheyarerecalledhere.

Definition2.6.([6]) LetU beauninorm.Theresidualoperation derivedfromU isthebinaryoperationgivenby

IU

(

x

,

y

) =

sup

{

z

∈ [

0

,

1

] |

U

(

x

,

z

)

y

}

(4)

forallx

,

y

∈ [

0

,

1

]

.

Proposition2.3.([6])LetU beauninormandIUitsresidualoperation.ThenIUisanimplication,calledRU -implication,ifandonly ifthefollowingconditionholds

U

(

x

,

0

) =

0 for all x

<

1

.

(5)

Thispropertyincludesallconjunctiveuninormsbutalsomanydisjunctiveones,forinstancetheclassesofrepresentable andidempotentuninormswith g

(

0

) =

1 (see[6] and[22]).However,whenwedealwithleft-continuousuninormsU ,we clearly havethat U satisfiescondition (5) if andonly ifit is conjunctive. There are some properties of RU -implications derived fromuninorm,that canbe deduceddirectlyfromthedefinition,orcan beproved inthe similarwaythat itwas doneforthosederivedfromt-norms.Formoredetailssee[6].

3. Modustollenswithrespecttouninorms:U -ModusTollens

Aswehavealreadymentioned,themainobjectiveofthisworkisthestudy ofthegeneralization oftheModusTollens property obtainedby changingthet-norm T bya uninorm U ,ina similarwayasit was doneforthe ModusPonensin [19].ForobviousreasonswewillrefertothisgeneralizationastheU -ModusTollens.Thus,letusbeginbygivingtheformal definitionintheframeworkoffuzzylogic.

Definition3.1.LetI beafuzzyimplicationfunction,U auninormandN afuzzynegation.ItissaidthatI andN satisfythe U -ModusTollens propertywithrespecttoU when

U

(

N

(

y

),

I

(

x

,

y

))

N

(

x

)

for all x

,

y

∈ [

0

,

1

].

(6)

Note that the definition has been given for a uninorm in generaland not for a conjunctive one.1 This is because this propertyonU isdirectlyderivedfromthedefinitionofU -ModusTollensasitisprovedinthefollowingproposition.

Proposition3.1.LetI beafuzzyimplicationfunctionandN anegationthatsatisfytheU -ModusTollenswithrespecttoauninormU . ThentheuninormU mustnecessarilybeconjunctive.

Proof. If I and N satisfy the U -Modus Tollens with respect to U , just take x

=

1 and y

=

0 in Equation (6) to obtain U

(

N

(

0

),

I

(

1

,

0

))

N

(

1

)

,thatis,U

(

1

,

0

) =

0.



Inviewofthepropositionabove,fromnowon,wewillconsideronlyconjunctiveuninormsintheU -ModusTollensprop- erty. By Definition 3.1,in general, U -Modus Tollensdepends on the uninorm U , the fuzzy implication I,and the fuzzy negation N. Example3.1showsthat,foranyconjunctiveuninorm U ,ifwe requireU -Modus Tollenstobevalidforsome particularnegationN,the admissibleimplicationsI dependonthechoiceofN.

Example3.1.Letusseehowthe U -Modus Tollensbehaves inthecases wheretheextremefuzzynegations are involved, thatis,whenweconsiderthesmallestandlargestfuzzynegations.

1 Recallthatat-normT isusedtomodelaconjunctioninfuzzylogic.Thus,thenormalgeneralizationwouldbetotakeaconjunctiveuninorm.

(5)

i) Letusconsiderthesmallestfuzzynegation N

=

ND1,givenby ND1

(

x

) =

1 if x

=

0

,

0 if x

>

0

.

Note that,if we take anyconjunctiveuninorm U andthe negation ND1,any implicationfunction I trivially satisfies Equation (6) forall y

>

0 (becausethen ND1

(

y

) =

0) andalso when x

=

0 (becausethen ND1

(

x

) =

1). On theother hand,when y

=

0 andx

>

0 Equation(6) holdsifandonlyif

U

(

N

(

0

),

I

(

x

,

0

)) =

U

(

1

,

NI

(

x

))

N

(

x

) =

0

,

which impliesNI

(

x

) =

0 forall x

>

0.Thus, we getthefollowing conclusion:“AnimplicationfunctionI satisfiestheU - ModusTollenswithrespecttoaconjunctiveuninormU andthefuzzynegationND1ifandonlyif NI

=

ND1”.

ii) Letusconsidernowthegreatestfuzzynegation N

=

ND2,givenby ND2

(

x

) =

1 if x

<

1

,

0 if x

=

1

.

Asimilarargumentshowsthefollowingconclusion:“AnimplicationfunctionI fulfills theU -ModusTollenswithrespect toaconjunctiveuninormU andthefuzzynegationND2 ifandonlyifI

(

1

,

y

) =

0 forall y

<

1”.

Similarly tothe caseoft-norms, whenthe uninorm U isleft-continuous, wecan easily derivea generalresultabout U - ModusTollensasfollows.

Proposition3.2.LetU beaconjunctiveleft-continuousuninorm,IU itsresidualimplicationfunctionandN afuzzynegation.Then, animplicationfunctionI satisfiestheU -ModusTollenswithrespecttoU andN ifandonlyif

I

(

x

,

y

)

IU

(

N

(

y

),

N

(

x

))

for all x

,

y

∈ [

0

,

1

],

Proof. JustrecallthatwhenU isleft-continuoustheresiduationpropertyholds(see[6])andthen U

(

N

(

y

),

I

(

x

,

y

))

N

(

x

) ⇐⇒

I

(

x

,

y

)

IU

(

N

(

y

),

N

(

x

)). 

However, the abovecondition doesnot holdwhen U is not left-continuousandmoreover, evenwhen itholds, itcan be difficult to check itin manycases. Thus,we want to deeplystudy the U -Modus Tollenscondition to give more spe- cific results. Afirst analysisof the U -Modus Tollensallows usto give some generalresults that we listin thefollowing proposition.

Proposition3.3.LetI beafuzzyimplicationfunctionandN anegationthatsatisfytheU -ModusTollenswithrespecttoaconjunctive uninormU .Lete betheneutralelementofU ,thenthefollowingpropertiesaresatisfied

1. U

(

N

(

y

),

I

(

1

,

y

)) =

0 forally

∈ [

0

,

1

]

.

2. NI

(

x

)

N

(

x

)

forallx

∈ [

0

,

1

]

.Also,forallx

∈ [

0

,

1

]

suchthatNI

(

x

)

e itmustbeN

(

x

) =

1.

3. Take

α

N

=

sup

{

x

∈ [

0

,

1

] |

N

(

x

)

e

}

.Then a) If

α

N

=

0 thenN

(

x

) <

e forallx

>

0.

b) If

α

N

>

0 thenitmustbeI

(

1

,

y

) =

0 forally

< α

N. 4. IfI satisfies(N P),then

α

N

=

0.

5. IfI satisfies(I P) andN isnonfilling(N

(

x

) <

1 forx

>

0),itmustbe

α

N

=

0.

Proof. Letusprovethemstepbystep.

1. ThisfirstitemisadirectconsequenceoftheU -ModusTollensproperty,justtakingx

=

1 inEquation(6).

2. Consider NI

(

x

) =

I

(

x

,

0

)

,thenwehave

NI

(

x

) =

U

(

e

,

I

(

x

,

0

))

U

(

1

,

I

(

x

,

0

))

N

(

x

),

wherethelastinequalityfollowsbytakingy

=

0 inEquation(6).

Ontheotherhand,ifNI

(

x

)

e,takingagainy

=

0 inEquation(6),weobtain N

(

x

)

U

(

N

(

0

),

I

(

x

,

0

)) =

U

(

1

,

NI

(

x

))

U

(

1

,

e

) =

1

.

3. Letusconsidernow

α

N

=

sup

{

x

∈ [

0

,

1

] |

N

(

x

)

e

}

.

(6)

a) If

α

N

=

0,wedirectlyderivefromthedefinitionof

α

N that N

(

x

) <

e forallx

>

0.

b) If

α

N

>

0 wegetN

(

y

)

e forall y

< α

N andconsequently, I

(

1

,

y

) =

U

(

e

,

I

(

1

,

y

))

U

(

N

(

y

),

I

(

1

,

y

))

N

(

1

) =

0

,

thatis,I

(

1

,

y

) =

0 forall y

< α

N.

4. If

α

N

>

0,wegetI

(

1

,

y

) =

0 forall y

< α

N andconsequentlyI doesnotsatisfy(N P).

5. Suppose inthiscasethat I

(

x

,

x

) =

1 forall x

∈ [

0

,

1

]

andN

(

x

) <

1 for x

>

0.Inthiscase, supposeagainthatthere is somex

>

0 withN

(

x

)

e.Takingx

=

y inExpression(6) wewillget

N

(

x

)

U

(

N

(

x

),

I

(

x

,

x

))

U

(

e

,

1

) =

1

,

whichisacontradiction.Thus,itmustbeagainN

(

x

) <

e forallx

>

0 andconsequently,

α

N

=

0.



Remark3.1.SomeinterestingconsequencescanbederivedfromProposition3.3asfollows.

(i) IfwewanttodealwithcontinuousfuzzynegationsintheU -ModusPonens,thenwewillhave

α

N

>

0.FromItem4in Proposition3.3wegetthat anypossiblesolutionoftheU -ModusPonensfailsto satisfy(N P).Consequently,allusual implicationsderivedfromt-normsandt-conorms(thatis,R,

(

S

,

N

)

,Q L andD-implications),aswellasYagergenerated implications,never satisfy U -ModusTollens(sinceall ofthemsatisfy (N P)).Fortunately, we willseeinnext sections thatmanysolutionscanbefoundamongthoseimplicationsderivedfromuninorms,especiallyamongRU -implications.

(ii) On the other hand, if we want to consider implication functions satisfying (N P), the same argument leads to the necessityofconsideringnegationswith

α

N

=

0,thatis,negations N suchthat N

(

x

) <

e forallx

>

0 andconsequently, non-continuous.

Intherestofthissectionwewilldealwiththecase

α

N

=

0 andalsowhentheinvolvedimplications satisfy(N P).We willcharacterizeinparticularall solutionsinthecasewhenthenegation N isstrictlydecreasingintheinterval

]

0

,

e

[

and U isauninormin

U

min.Westartbyprovingthatforthiskindofuninorms,U-ModusTollensalwaysholdsforallx

y and soitissufficienttoproveitfor

(

x

,

y

)

suchthat y

<

x.

Proposition3.4.LetI beanimplicationfunction,N afuzzynegationwith

α

N

=

0,andU auninormin

U

minwithneutralelement e

∈]

0

,

1

[

.ThenI

,

N satisfytheU -ModusTollenswithrespecttoU ifandonlyif

U

(

N

(

y

),

I

(

x

,

y

))

N

(

x

)

for all y

<

x

.

Proof. WeonlyneedtoprovethattheU -ModusTollensisalwayssatisfiedinpointswherex

y.Sinceitisobviouswhen x

=

0,wedealwithvalues0

<

x

y.InthiscasewehaveN

(

y

)

N

(

x

)

andsince

α

N

=

0,itisN

(

x

) <

e forall x

>

0.Then wehavetwocases:

a) IfI

(

x

,

y

) >

e,then

U

(

N

(

y

),

I

(

x

,

y

))

U

(

N

(

x

),

I

(

x

,

y

)) =

min

{

N

(

x

),

I

(

x

,

y

) } =

N

(

x

).

b) IfI

(

x

,

y

)

e,then

U

(

N

(

y

),

I

(

x

,

y

))

U

(

N

(

x

),

I

(

x

,

y

)) =

eTU

N

(

x

)

e

,

I

(

x

,

y

)

e

e N

(

x

)

e

=

N

(

x

). 

Wenowstudythecaseinwhichtheimplication I satisfies(N P),whichisthecaseofmostoftheimplicationsderived fromt-normsandt-conorms.

Proposition3.5.LetI beanimplicationfunctionthatsatisfies(N P),N afuzzynegation,andU aconjunctiveuninormwithneutral elemente

∈]

0

,

1

[

.IfI

,

N satisfytheU -ModusTollenswithrespecttoU ,then:

1. U

(

N

(

y

),

y

) =

0 forally

∈ [

0

,

1

]

.

2. N

(

x

) =

0 forallx

e andN

(

x

) <

e forallx

>

0.

3. U

(

N

(

y

),

I

(

e

,

y

)) =

0 forally

∈ [

0

,

1

]

.

4. IfN isstrictlydecreasingintheinterval

]

0

,

e

[

,thenI

(

x

,

y

) <

e forally

<

x

<

e.

Proof. Letusproveallitemsonebyone.

1. U

(

N

(

y

),

y

) =

0 forall y

∈ [

0

,

1

]

followsdirectlybytakingx

=

1 inEquation(6) since I satisfies(N P).

(7)

2. AccordingtoProposition3.3weknowthatifI satisfies(N P),then

α

N

=

0 andN

(

x

) <

e forallx

>

0.Moreover,justby putting y

=

e intheprevious condition,we obtain N

(

e

) =

U

(

N

(

e

),

e

) =

0 andconsequently, N

(

x

) =

0 forall x

e,by decreasingness.

3. Now,takingx

=

e inEquation(6) wegetU

(

N

(

y

),

I

(

e

,

y

))

N

(

e

) =

0,andsoU

(

N

(

y

),

I

(

e

,

y

)) =

0 forall y

∈ [

0

,

1

]

. 4. To prove thisitem letusconsider some x

,

y such that y

<

x

<

e and supposethat I

(

x

,

y

) >

e.First, note that y

>

0

becauseI

(

x

,

0

) =

NI

(

x

)

N

(

x

) <

e.Consequently,wehaveN

(

y

) <

e andso,sinceN isstrictlydecreasingin

]

0

,

e

[

,

U

(

N

(

y

),

I

(

x

,

y

))

min

{

N

(

y

),

I

(

x

,

y

) } =

N

(

y

) >

N

(

x

),

leadingtoacontradiction.Thus,weobtainI

(

x

,

y

) <

e forall y

<

x

<

e.



WhenN isanegationstrictlydecreasingintheinterval

]

0

,

e

[

andtheimplicationI satisfies(N P),wecangiveacharac- terizationofthoseuninormsin

U

minthatsatisfytheU -ModusTollens,asfollows.

Theorem3.1.LetI beanimplicationfunctionthatsatisfies(N P),U

TU

,

e

,

SU

minauninormin

U

minwithneutralelemente

∈ ]

0

,

1

[

,andN afuzzynegationstrictlydecreasingin

]

0

,

e

[

.ThenI

,

N satisfytheU -ModusTollenswithrespecttoU ifandonlyifthe followingpropertieshold:

1. U

(

N

(

y

),

I

(

e

,

y

)) =

0 forally

∈ [

0

,

1

]

.

2. N

(

x

) =

0 forallx

e andN

(

x

) <

e forallx

>

0.

3. I

(

x

,

y

) <

e forally

<

x

<

e.

4. IandNverifytheModusTollenswithrespecttoTUforally

<

x,whereIandNaregivenby

I

(

x

,

y

) =

1 if x

y

,

I(ex,ey)

e if y

<

x

.

(7)

N

(

x

) =

1 if x

=

0

,

N(ex)

e otherwise

.

(8)

Proof. Let ussupposefirstthat I and N satisfythe U -Modus Tollenswithrespectto U .Properties 1,2and3holdfrom Proposition3.5andthus,weonlyneedtoprovethat IandN satisfytheModusTollenswithrespectto TU forall y

<

x.

Wewilldistinguishtwocases:

If y

=

0 then,

TU

(

N

(

y

),

I

(

x

,

0

)) =

TU

1

,

I

(

ex

,

0

)

e

=

I

(

ex

,

0

)

e

=

NI

(

ex

)

e

N

(

ex

)

e

=

N

(

x

),

wherethelastinequalityisduetoProposition3.3.

If y

>

0,wehave

TU

(

N

(

y

),

I

(

x

,

y

)) =

TU

N

(

ey

)

e

,

I

(

ex

,

ey

)

e

=

U

(

N

(

ey

),

I

(

ex

,

ey

))

e

N

(

ex

)

e

=

N

(

x

),

wherethelastinequalityholdsbecauseI

,

N satisfyU -ModusTollenswithrespecttoU .

Conversely, supposethat conditions1-4holdandwewill provethat I

,

N satisfy theU -Modus Tollenswithrespectto U . According to Proposition3.4 the U -Modus Tollensneeds to be checkedonly inpoints

(

x

,

y

)

where y

<

x. Thus, we will considerthreecases:

If y

=

0,then

U

(

N

(

y

),

I

(

x

,

y

)) =

U

(

1

,

I

(

x

,

0

)) =

U

(

1

,

NI

(

x

)) =

NI

(

x

),

wherethelastequalityholdsbecauseU

U

min.ThentheresultfollowsfromProposition3.3.

If0

<

y

<

x

<

e thenI

(

x

,

y

) <

e and N

(

y

) <

e byconditions3and2,respectively.Inthiscase, U

(

N

(

y

),

I

(

x

,

y

)) =

e

·

TU

N

(

y

)

e

,

I

(

x

,

y

)

e

=

e

·

TU



N



y e

,

I



x e

,

y

e

e

·

N



x e

=

N

(

x

),

wherethelastinequalityholdsfromcondition4.

(8)

Fig. 1. Plot of the fuzzy negation Ne(left) and structure of the fuzzy implication Ie (right) given in Example3.2.

Ifx

e,thenI

(

x

,

y

)

I

(

e

,

y

)

andhence,

U

(

N

(

y

),

I

(

x

,

y

))

U

(

N

(

y

),

I

(

e

,

y

)) =

0

,

whereinthiscasethelastequalityisduetocondition1.



Remark3.2.Letuspointouttwointerestingfacts.

i) According to the theorem above, the proof that I

,

N satisfy the U -Modus Tollens with respect to a uninorm U

TU

,

e

,

SU

min in

U

min, requires in particular to check that I and N satisfy the Modus Tollens withrespect to TU. However, thisquestion was alreadysolved in[26,27] and consequently, our characterizationtheorem iscomplete. In fact,manyexamplescanbederivedfromconditionsinTheorem3.1(seeExample3.2below).

ii) NotethatinTheorem3.1,thet-conormSU playsnoroleinthesatisfactionoftheU -ModusTollensandso,SU canbe anyt-conorm.Moreover,thesamepropertyholdswhenthevaluesoftheimplicationI areoutoftherectangle

[

0

,

e

[

2, withtheuniqueconditionthatitsatisfies(N P).

Example3.2.Letusconsidertheuninormin

U

min,U

TU

,

e

,

SU

minwhereTU

=

TLK istheŁukasiewiczt-normandSU is anyt-conorm.LetNe bethenegationgivenby

Ne

(

x

) =

⎧ ⎪

⎪ ⎩

1 if x

=

0

,

e

x if 0

<

x

<

e

,

0 if x

e

.

Ontheotherhand,weconsiderthefollowingfuzzyimplication

Ie

(

x

,

y

) =

⎧ ⎪

⎪ ⎩

1 if x

=

0 or y

=

1

,

max

(

e

x

,

y

)

if 0

<

x

e and 0

y

e

,

y otherwise

.

It is easy to seethat these operators satisfy all the conditionsof Theorem 3.1and therefore Ie

,

Ne satisfy the U -Modus TollenswithrespecttotheuninormU (Fig.1).

4. ModusTollensforR U -implications

Inthissection,givenaconjunctiveuninormU andafuzzynegationN,wewillinvestigatewhichRU -implicationssatisfy theU -ModusTollensinequality.WewilldoitforRU -implicationsderivedfromthethreeclassesofuninormsrecalledinthe preliminaries.Notethatintheprevioussectionwehaveseenthat,forfuzzynegationsN with

α

N

>

0 (casethatincludesall continuousnegations),onlyimplications I suchthat I

(

1

,

y

) =

0 forall y

< α

N cansatisfytheU -ModusTollens.Fortunately, thisconditionissatisfiedby RU -implicationsderivedfromrepresentableuninormsandforsomeidempotentsonesandso, inthesecaseswewillseethatcontinuous(evenstrictandstrong)negationscanbeconsidered.

WewillstudytheU -ModusTollens forRU -implicationsderivedfromuninormsintheclassof

U

min,fromrepresentable uninormsandfromidempotentuninorms,andwewilldevoteasubsectiontoeachofthesecases.

(9)

4.1. CaseofRU -implications derivedfromuninormsin

U

min

In this subsection, we will deal with RU -implications derived from uninorms in

U

min, that is, uninorms U0

T0

,

e0

,

S0

min withneutral element e0

∈]

0

,

1

[

and underlyingt-norm andt-conorm T0 and S0, respectively. Recall that forthiskindofuninorms,RU -implicationsaregivenbythefollowingstructure.

Proposition4.1.(Theorem5.4.7in[3])LetU

TU

,

e

,

SU

minbeauninormin

U

minandIU itsresidualimplication.Then

IU

(

x

,

y

) =

⎧ ⎪

⎪ ⎪

⎪ ⎨

⎪ ⎪

⎪ ⎪

1 if x

y

<

e

,

eITU

(

ex

,

ey

)

if y

<

x

e

,

e

+ (

1

e

)

ISU

(

x1ee

,

1yee

)

if e

x

y

,

e if e

y

<

x

,

y otherwise

.

(9)

Forthiskindof RU -implicationswe againgetthat the U -Modus Tollenscan besatisfied onlywithnegations N with

α

N

=

0 andconsequently,withnon-continuousnegations.Moreover,forthiskindofRU -implicationswehavethefollowing result.

Proposition4.2.LetIU0 beafuzzyimplicationderivedfromU0

T0

,

e0

,

S0

min,N afuzzynegation,andU

TU

,

e

,

SU

acon- junctiveuninorm.IfIU0

,

N satisfy theU -ModusTollenswithrespecttoU ,thenthefollowingpropertieshold:

1. U

(

N

(

y

),

y

) =

0 forally

e0. 2. U

(

N

(

y

),

1

) =

N

(

y

)

forally

<

e0. 3.

α

N

=

0 (thatis,N

(

x

) <

e forallx

>

0).

4. Ife

e0N

(

x

) =

0 forallx

e.

5. Ife0

<

e,TUisacontinuoust-normandU

(

e0

,

e0

) =

e0,thenN

(

x

) <

e0forallx

>

0 andN

(

x

) =

0 forallx

e0.

Proof. 1. FollowsdirectlyfromEquation(6) byputtingx

=

1 andtakingintoaccountthatIU0

(

1

,

y

) =

y forall y

e0. 2. Foranyx

<

e0,wehaveIU0

(

x

,

x

) =

1 andifwetakex

=

y inEquation(6),wehave

U

(

N

(

y

),

IU0

(

y

,

y

)) =

U

(

N

(

y

),

1

)

N

(

y

).

Theresultfollowsfromthefactthat U

(

N

(

y

),

1

)

N

(

y

)

holdsalways.

3. ItisadirectconsequenceofProposition3.3,becauseitis IU0

(

1

,

y

) >

0 forall y

>

0.

4. Ifwetake y

=

e inProperty1,wehaveU

(

N

(

e

),

e

) =

N

(

e

) =

0 andbydecreasingness,N

(

x

) =

0 forallx

e.

5. First,letusseethat N

(

x

) <

e0 forall0

<

x

<

e0.Indeed,since TU iscontinuous ande0

<

e isan idempotentelement, ifwehavethat N

(

x

)

e0withe0

>

x

>

0,then

U

(

e0

,

x

) =

x for all 0

x

e0 (10)

andthen,applyingProperty1weget

0

=

U

(

N

(

x

),

x

)

U

(

e0

,

x

) =

x

leadingtoacontradiction.Now,wehavethatN

(

x

) <

e0forallx

>

0 bydecreasingness,andweonlyneedtoprovethat N

(

e0

) =

0 toconcludetheproof.ButthisisclearbecauseN

(

e0

) <

e0andthen

0

=

U

(

N

(

e0

),

e0

) =

N

(

e0

),

wherethefirstequalityisduetoProperty1andthesecondisduetoEquation(10).



Inordertocharacterizethesolutionsinthiscase,wewilldistinguishthreedifferentpossibilitiesaccordingtotheorder oftheneutralelementse ande0.Webeginbythemostsimplecasewhenbothelementscoincide.

Theorem4.1.LetIU0betheRU -implicationderivedfromU0

T0

,

e0

,

S0

min,N afuzzynegation,andU

TU

,

e

,

SU

aconjunc- tiveuninormwithneutralelemente

=

e0.ThenIU0andN satisfytheU -ModusTollenswithrespecttoU ,ifandonlyifthefollowing propertieshold

1. U

(

N

(

y

),

y

) =

0 forally

e,andU

(

N

(

y

),

1

) =

N

(

y

)

forally

<

e.

2. N

(

x

) <

e forallx

>

0,andN

(

x

) =

0 forallx

e.

3. IT0andNsatisfytheModusTollenswithrespecttothet-normTUforally

<

x,whereIT0istheresidualimplicationderivedfrom thet-normT0andNisgivenbyEquation(8).

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