In this paper, we study the global existence and uniqueness of sectorial solutions to the system
∂tui+Aiui = fi(u), ∀t∈(0,∞)
ui(0,x) = u0i(x),
whereAiare sectorial operators in the Banach space(X,k·k),
u0i ∈Xandfi:[0,∞)×Xm →Xa given valued function for alli ∈ J1,mK :={1, ...,m}, whereX
mis the Banach product space doted with the normkukm=∑mi=1kuik.
In the casem = 1, since work (Byszewski and Lakshmikant-ham, 1990), (Byszewski, 1991), (Byszewski, 1993), there has been increasing interest in studying abstract problems in Ba-nach Spaces (cf., e.g., (Aizicovici and Mckibben, 2000) and re-ferences therein). For material intimately related to the present paper, we refer to (Henry, 1981), where is studied the existence of sectorial solutions for the single equations. Also in (Jack-son, 1993), (Liang et al, 2002), nonlocal autonomous parabolic
0≤t≤Tis a family ofm-accretive opera-tors inXgenerating a compact evolution family, and the exis-tence of integral solutions to the associated nonlocal problem is shown. In the casem>1, we refer to (Yangari, 2015) in which is studied the existence and uniqueness of mild solutions of a reaction diffusion system with infinitesimal generators. In order to improve the notation, we consider the system
∂tu+Au = f(t,u), ∀t∈(0,∞)
u(0) = u0,
whereu = (ui)mi=1, f = (fi)mi=1andA= diag(A1, ...,Am). Moreover, we consider the normkukα = ∑mi=1kuikα,i on the
spaceXα=∏m
i Xαi, where the spaceXiαis defined in the next section.
α and f
i
Parabolic Systems Involving Sectorial Operators: Existence
andUniqueness of Global Solutions
Sistemas Parabólicos que Involucran Operadores Sectoriales:
Existencia y Unicidad de Soluciones Globales
Keywords:Reaction diffusion systems, sectorial operators, infinitesimal generators.
[email protected] Received:12/06/2015 Accepted: 23/05/2016 Published: 30/09/2016
Palabras clave:Sistemas de reacción difusión, operadores sectoriales, operadores infinitesimales.
1. INTRODUCTION
1
Miguel Yangari
;
Diego SalazarEscuela Politécnica Nacional, Departamento de Matemática, Ladrón de Guevara E11-253, Quito, Ecuador
1 1
Abstract: The aim of this paper is to study the existence and uniqueness of global solutions in time to systems ofequations, whenthe diffusion terms are given by sectorial generators.
Resumen: El objetivo de este artículo es estudiar la existencia y unicidad de soluciones globales en tiempo
parasistemas deecuaciones, cuando los términos de difusión están dados por operadores sectoriales.
(1)
Throughout this paper, we assume Ω some open set in R× X
precisely, if(t1,x1)∈Ω, there exists a neighborhoodV⊂Ω such that for(t,x)∈V,(s,y)∈V
kfi(t,x)− fi(s,y)k ≤Li(|t−s|θi+kx−ykα
for some constants Li > 0and without loss of generality we assumeθ:=θi >0for alli∈J1,mK. Moreover, a solution of
0,t1
0,t1)−→Xmsuch thatu(t0) =u0and on(t0,t1)we ha-ve(t,u(t)) ∈ Ω,u(t) ∈ D(A),∂u
∂t(t)exists,t7→ f(t,u(t)) is locally Hᅵlder continuous and
Z t0+ρ
t0
kf(t,u(t))kmdt<∞
Takingi ∈ J1,mKfixed throughout this section, we call a li-near operator Ai in a Banach space X, a sectorial operator if it is a closed densely defined operator such that, for some φ∈(0,π/2),M≥1and a realε, the sector
Sε,φ={λ|φ≤ |arg(λ−ε)| ≤π, λ6=ε}
is in the resolvent set ofAiand
(λI−Ai) −1
≤M/|λ−ε| for all λ∈Sε,φ.
Let us note that every bounded linear operator on a Banach space is sectorial. Also, if we define
e−Ait= 1 2iπ
Z
Γ(λI+Ai)
−1eλtdλ
whereΓis a contour in the resolvent of−Ai witharg(λ) → ±θ as |λ| → ∞ for some θ ∈ (π/2,π), we have that −Ai is the infinitesimal generator of the analytic semigroup (e−Ai(t))t≥0, moreover, ifReσ(A
i)>bi, then fort>0
e
−Ait ≤ce
−bit, Aie
−Ait
≤
c te
−bit
It is important to note that, ifB is a bounded linear operator, thene−Btas defined above extends to a group of linear opera-tors and verifies
e−Bte−Bs=e−B(t+s), f or−∞<t,s<∞.
In order to define the fractional power of a sectorial operator
Ai, we assumeReσ(Ai)>0, so, for anyα∈(0, 1)
A−α
i = 1 Γ(α)
Z ∞
0 t
α−1e−Aitdt.
Taking A−α
i defined as above, we have that this operator is a bounded linear operator on X which is one-one and satisfies
A−αi A−βi = A−(α+β)i . Furthermore,Aα
i represents the inverse operator ofA−α
i withD(Aαi) = R(A
−α
i )andA0i is the iden-tity on X. An important result concerning positive powers of sectorial operators is
A
α
ie
−Ait ≤cαt
−αe−bit
withReσ(Ai)>bi>0and ifu∈ D(Aαi)
(e
−Ait−I)u
≤
1 αc1−αt
αkAα
i
also, Aα
iA
β
i = A
β
iAiα = A
α+β
i on D(A
γ
i) with γ = max(α,β,α+β).
Now, we consider the fractional powers ofBi:=Ai+aiIwith
ai ∈Rchosen soReσ(Bi) >0, whereσ(Bi)is the spectrum ofBi. We define the Banach spaceXαi =D(Bαi)with the norm kukα,i =
Biαu
, whereD(Bαi)is the domain of the operator Bα
i. Finally, takingα≥β≥0, thenXiαis a dense subspace of
Xiβwith continuous inclusion, also,X0i =X.
For more information about sectorial operators we refer the reader to (Henry, 1981).
In order to state our first result, since−Ai
−Ai(t))
t≥0
given by
u(t) =P(t−t0)u0+
Z t
t0
with
P(t) =diag(e−A1(t), ...,e−Am(t)).
In what follows, the constantC>0represents different cons-tants.
0,t1
0,t1)intoXα,
Z t0+ρ
t0
kf(s,u(s))kmds<∞
0<t<t1 0,t1
3. MAIN RESULTS
the initial value system (1) on(t )is a continuous function
u:[t
for someρ>0and the differential equation (1) is verified.
is the infinitesimal generator of the analytic semigroup(e
for eachi ∈
J1,mK, we define the weak formulation for the system (1)
).
, thenuis a solution of the system(1)on(t
) (2)
. (3)
f or t>0 (4)
uk (5)
P(t−s)f(s,u(s))ds (6)
Lemma 3.1 Ifuis the solution of the system(1)on(t ),
then equation (6) is satisfied. Inversely, if u is a continuous function of(t
0,t1), taking i ∈ J1,mK fixed, we define the auxiliary fun-ction
gi(t,v) = fi(t,u1, ...,ui−1,v,ui+1, ...,un).
Let see thatgi(t,ui(t))is locally Hᅵlder continuous intand Rt0+ρ
t0 kgi(t,ui(t))kdt < +∞. Indeed, sincegi : (t0,t1)× Xα
i −→Xand
kgi(t,ui(t))−gi(s,ui(t))k
= kfi(t,u(t))−fi(s,u(s))k ≤ kf(t,u(t))− f(s,u(s))km ≤ L|t−s|ν
sincet −→ f(t,u(t))is Hᅵlder continuous with exponent ν∈(0, 1). Furthermore,
Z t0+ρ
t0
kgi(t,ui(t)kXdt =
Z t0+ρ
t0
kfi(t,u(t))kXdt
≤
Z t0+ρ
t0
kf(t,u(t))kmdt
< +∞
that
∂tui+Aiui = gi(t,ui),
ui(0) = u0i.
Therefore by the theorem 3.2.2 in (Henry, 1981), we have that
ui
ui(t) =e−Ai(t−t0)u0i+
Z t
t0
e−Ai(t−s)g
i(s,ui(s))ds.
Repeating the same procedure for alli∈J1,mK, we have
u(t) =P(t−t0)u0+
Z t
t0
P(t−s)f(s,u(s))ds
andu∈ C (t0,t1);Xα. Besides, for eachi∈J1,mK, we have thatui:(t0,t1)−→Xiαis continuous and verifies
ui(t) =e−Ai(t−t0)u0i+
Z t
t0
e−Ai(t−s)g
i(s,ui(s))ds.
First, we will prove thatuiis locally Hᅵlder continuous from (t0,t1)toXαi. Thus, ift,t+h∈[t∗0,t∗1]⊂(t0,t1)withh>0 andδi∈(0, 1−α), we claim that
kui(t+h)−ui(t)kα,i≤Cih δ
for some positive constantCi. Indeed,
ui(t+h)−ui(t) = (e−Aih−I)e−Ai(t−t0)u0i
+
Z t
t0
(e−Aih−I)e−Ai(t−s)g
i(s,ui(s))ds
+
Z t+h
t e
−Ai(t+h−s)g
i(s,ui
Now, for anyz∈X, by Theorem 1.4.3 in (Henry, 1981),
(e
−Aih−I)e−Ai(t−s)z
α,i
≤C(t−s)−(α+δi)hδiebi(t−s)kzk.
Moreover, due to each fi is locally Hᅵlder int and locally Lipschitz inu, we have that
kfi(t,u(t))− fi(t0,u(t0))k ≤Li(|t−t0|θ+ku(t)−u(t0)kα)
or equivalently
kgi(t,ui(t))−gi(t0,ui(t0))k ≤ Li(|t−t0|θ+ku(t)kα
+ku(t0)kα
0,t1)−→ Xαis conti-nuous, then, we have
Cα=ku(t0)kα+t∗max 0≤t≤t∗1
kukα <+∞.
i(t,ui(t))k ≤ L(|t−t0|θ+2Cα) +kgi(t0,u0i)k ≤ L(|t−t0|θ+c).
(e
−Aih−I)e−Ai(t−t0)u0i α,i
≤ C(t∗0−t0)−(α+δi)hδiebi(t1−t0)ku0ik ≤ Chδi,
sincet∈[t∗0,t∗1]⊂(t0,t1
Z t
t0
(e−Aih−I)e−Ai(t−s)g
i(s,ui(s))ds
α,i
≤
Z t
t0
C(t−s)−(α+δi)hδiebi(t−s)kg
i(s,ui(s))kds
≤ Chδi
Z t
t0
(t−s)−(α+δi)ebi(t−s)(L|t−t
0|θ+c)ds
≤ Chδi
Z t
t0
(t−s)−(α+δi)ds Proof.Let assume thatuis the solution of the system (1) on
(t
for someρ>0. Now, sinceuverifies the system (1), we have
namelyusatisfy the equation (6).
Reciprocally, we suppose now thatusatisfy the equation (6)
(7)
is the unique solution of the system (7), which can be writ-ten as
i (8)
(s))ds. (9)
We begin bounding the first term of the equation (9),thus
). Now, let us bound the second term of the equation (9)
). (10) But for hypothesis, we know thatu:(t
Hence, by the inequality (10)
≤ Chδi.
i) > γi > 0andRe(σ(−aiI)) ≥ −(ai+γi
Rt+h
t e−Ai(t+h−s)gi(s,ui(s))ds
α,i
=
Z t+h
t
B
α
ie−Bi(t+h−s)
e
aiI(t+h−s)g
i(s,ui(s))
ds ≤
Z t+h
t Cα
(t+h−s)−αeai(t+h−s)kg
i(s,ui(s))kds
≤
Z t+h
t Cα(t+h−s)
−αeai(t+h−s)(L|s−t
0|θ+c)ds
≤ c
Z t+h
t
(t+h−s)−αeai(t+h−s)ds
≤ c
Z t+h
t (t+h−s)
−αe−γt0e−γt1e−γhds
≤ c
Z t+h
t (t+h−s)
−αds
≤ ch1−α ≤ Chδi
i(t,ui(t)) is locally Hᅵlder continuous on(t0,t1). Indeed,
kgi(t,ui(t))−gi(s,ui(s))k
= kfi(t,ui(t))− fi(s,ui(s))k ≤ Li(|t−s|θ+ku(t)−u(s)kα)
≤ Li(|t−s|θ+ m
∑
i=1
kui(t)−ui(s)kα,i)
≤ Li(|t−s|θ+ m
∑
i=1
Ci|t−s|δi)
≤ C(|t−s|θ+
m
∑
i=1
|t−s|δi).
Also,
Z t0+ρ
t0
kgi(t,ui(t))k ≤
Z t0+ρ
t0
kf(t,u(ti))kmdt<+∞.
Then, by Theorem 3.2.2 in (Henry, 1981),uisolves the equa-tion
∂tui+Aiui = gi(t,ui(t)) = fi(t,u(t))
ui(0) = u0i
Theorem 3.1 If fi
0,u0)∈Ωthere existsT=T(t0,u0
0,t0+T)with initial conditionu(t0) =u0.
V={(t,x)|t0≤t≤t0+τ,kx−u0kα≤δ}
is contained inΩand
kfi(t,x)−fi(t,y)k ≤ Likx−ykα
for any(t,x),(t,y) ∈ V. Moreover, we claim that for alli ∈ J1,mK, there exists a constantMi >0such that
B
α
ie
−Ait ≤Mit
−αeait
for all t > 0. Indeed, taking Re σ(Bi) > γi > 0 and
Re(σ(−aiI))≥ −(ai+γi
B
α
ie−Ait
=
B
α
ie−Aite−aiIteaiIt
=
B α
ie−BiteaiIt
≤
B α
ie−Bit
e
aiIt ≤ Cαt−αe−γit
e
−(−aiI)t ≤ Cαt−αe−γitCe(ai+γi)t ≤ Mit−αeait.
Furthermore, we set
κ= max
[t0,t0+τ]
kfi(t,u0)k, L= max
i∈J1,mK
Li
and
a= max
i∈J1,mK
ai, M= max
i∈J1,mK
Mi.
Hence, we can chooseT∈(0,τ)such that
(e
−Aih−I)u 0i
α,i
≤ δ
2m, f or0≤h≤T
for alli∈J1,mKand
mM(κ+Lδ)
Z T
0 u
−αeaudu≤ δ
2. for alli∈J1,mK.
Now, we are in position to state our main result in which we es-tablish the existence and uniqueness of solutions to the system (1).
)> 0 such that the system (1) has an unique solution u on (t
verifies the hypothesis (2) for each i ∈ J1,mK, then for any(t
), using inequalities (3) and (4), we have
), using inequalities (3) and (4) Proof.By the previous lemma is enough to find a solutionuof the equation (6). We chooseδ>0,τ>0such that the set
for some large enough positive constant C. Hence, inequa-lity (8) is satisfied. Moreover, t 7→ g
Bounding now the third term of the equation (9), taking
Reσ(B
(11)
IfSdenote the set of continuous functionsy : [t0,t0+T] → Xαsuch thatky(t)−u
0kα≤δont0≤t≤t0+T, provided
by the norm
kykT = m
∑
i=1
sup{kyi(t)kα,i, t0≤t≤t0+T}
thenSis a complete metric space since it is the product of com-plete metric spaces with the product norm. So, fory ∈ S, we defineH(y):[t0,t0+T]→Xmgiven by
H(y)(t) =P(t−t0)u0+
Z t
t0
P(t−s)f(s,y(s))ds.
We claim thatH : S → Sis a contraction. Indeed, ifY ∈ S
andt06t6t0+T, we have that
kH(y)(t)−u0kα
≤ k(P(t−t0)−I)u0kα
+
Z t
t0
kP(t−s)f(s,y(s)kαds
= m
∑
i=1 (e
−Ai(t−t0)−I)u 0i
α,i
+ m
∑
i=1
Z t
t0 e
−Ai(t−s)f
i(s,y(s))
α,ids
≤ α
2 + m
∑
i=1
Z t
t0 (Ai)1
αe−Ai(t−s)
kfi(s,y(s)kds
≤ δ
2+mM
Z t
t0
(t−s)−αea(t−s)(Lky(s)−u0kα+κ)ds
≤ δ
2+mM(κ+Lδ)
Z τ 0 u
−αeaudu6 δ.
We prove now thatH(y) : [t0,t0+T] → Xα is continuous. Indeed, without loss of generality, we suppose thatz<t, thus
kH(y)(t)−H(y)(z)kα
= m
∑
i=1
kHi(y)(t)−Hi(y)(z)kα,i
≤ m
∑
i=1
(e
−Ai(t−t0)−e−Ai(z−t0))u 0i
α,i
+ Z z t0
(e−Ai(t−s)−e−Ai(z−s))f
i(s,y(s))ds
α,i
+ Z t z e
−Ai(t−s)f
i(s,y(s))ds
α,i
= m
∑
i=1
(I1+I2+I3).
Lete>0, we need to findδ>0such that|t−z|<δimplies kH(y)(t)−H(y)(z)kα<e. Thus, we bound each term of the last inequality
I1= (e
−Ai(t−t0)−e−Ai(z−t0))u0i α,i
=
B α
ie−Ai(z−t0)(e−Ai(t−z)u0i−u0i)
≤ kBα
ik
e
−Ai(z−t0) e
−Ai(t−z)u 0i−u0i
≤ kBα
ikcie−bi(z−t0)
e
−Ai(t−z)u 0i−u0i
≤ Ci
e
−Ai(t−z)u 0i−u0i
<
e 3m
the last inequality is satisfied if|t−z| <δ1for someδ1 >0. Now, boundingI2
I2=
Rz t0(e
−Ai(t−s)−e−Ai(z−s))f
i(s,y(s))ds
α,i
≤ Z z t0 B α
i(e−Ai(t−s)−e−Ai(z−s))fi(s,y(s))
ds
≤ kBα
ik Z z t0 (e
−Ai(t−z)−I)e−Ai(z−s)f
i(s,y(s))
ds
≤ kBα
ikC
Z z t0 A α
ie−Ai(z−s)fi(s,y(s))
ds(t−z)
≤ C(t−z)
Z z
t0
Cα(z−s)−αe−bi(z−s)ds
≤ e
3m
the last inequality is satisfied if|t−z| <δ2for someδ2 >0. Now, proceeding withI3,
I3=
Rt z e
−Ai(t−s)fi(s,y(s))ds
α,i
≤ kBα
ik Z t z e
−Ai(t−s)
kfi(s,y(s))kds
≤ C
Z t
z e
−bi(t−s)ds
≤ e
3m
with|t−z| < δ3 for someδ3 > 0. Therefore, takingδ = m´ın{δ1,δ2,δ3}we conclude thatH(y)∈ C [t0,t0+T];Xα
and thenH(y)∈S.
We now prove thatHis a contraction. Lety,z∈ Sandt0 ≤ t≤t0+τ
kHi(y)(t)−Hi(z)(t)kα,i
≤ Z t t0 B α
ie−Ai(t−s)
kfi(s,y(s))− fi(s,z(s))kds
≤
Z t
t0
Mi(t−s)−αeai(t−s)Liky(s)−z(s)kα
= ML
Z t
t0
≤ ML
Z T
0 u
−αeaudsky−zkT
therefore, withI = [t0,t0+τ]
sup t∈I
kHi(y)(t)−Hi(z)(t)kα,i≤ ML
Z T
0 u
−αeaudsky−zkT
for alli∈J1,mK. Hence
kH(y)(t)−H(z)(t)kT ≤ mML
Z T
0 u
−αeaudsky−zkT
≤ 1
2ky−zk T.
For the fixed point theorem,Hhas an unique solutionu ∈ S, whereu is a continuous function u : [t0,t0+T] → (xαi)m
isatisfies
kfi(t,u)−fi(t0,u0)k ≤ Li(|t−t0|θ+ku−u0kα)
thus,
kfi(t,u)k ≤ Li(|t−t0|θ+δ) +kfi(t0,u0)k ≤ L(Tθ+δ) +B≤C
and then, for any fixedρ>0
Z t0+ρ
t0
kf(s,u(s))kmds = m
∑
i=1
Z t0+ρ
t0
kfi(s,u(s))kds
≤ mC2ρ<+∞.
0,t0
As a consequence of the previous theorem, we present a result about the behavior of the solution.
Theorem 3.2 If fi
of f(V)is bounded inXm 0 ,t1)andt1
0 ,t2)ift2>t1, then eithert1= +∞or
else there exists a sequencetn →t1− asn → +∞such that (tn,u(tn)) → ∂Ω. IfΩis unbounded, the point at infinity is included in∂Ω.
Proof.Proceeding by contradiction, we suppose thatt1<+∞, but(t,u(t)is not in a neighborhoodNof∂Ωfort≤ t< t1, we can takeNof the formN=Ω\B, whereBis a closed and bounded set ofΩand(t,u(t))∈Bfor allt≤t<t1. We will prove that there exists x1 ∈ Xα such that (t1,x1) ∈ Bwith u(t)→x1inXαwhent→t−1. Even moreu(t1) =x1, which means that the solution could be extended untilt1.
Indeed, letC = sup{kf(t,u)km,(t,u) ∈ B}, soC < +∞
because B is bounded and closed and by hypothesis f(B) is bounded inXm.
Firstly, we can see that ifα≤β<1andt≤t<t1, then
ku(t)kβ = m
∑
i=1
kui(t)kxβ i
≤ m
∑
i=1
e
−Ai(t−t0)u 0i
β,i
+
Z t
t0 e
−Ai(t−s)f
i(s,u(s))
β,i ds
= m
∑
i=1
B
α
iB
β−α
i e
−Ai(t−t0)u 0i
+
Z t
t0 B
β
ie
−Ai(t−s)
kfi(s,u(s))kds
≤ m
∑
i=1 ckBα
ik
B
β−α
i e
−Ai(t−t0) ku0ikα,i
+
Z t
t0 B
β
ie
−Ai(t−s)
kfi(s,u(s))kds
≤ c
m
∑
i=1
Mi(t−t0)−(β−α)eai(t−t0)ku0ikα,i
Z t
t0
Mi(t−s)−βeai(t−s)kfi(s,u(s))kds
≤ c
(t−t0)−(β−α)+
Z t
t0
(t−s)−βds
≤ C.
Thus, ku(t)kβ remains bounded when t → t−1. Now, we suppose thatt≤τ<t<t1, so
u(t)−u(τ) = (P(t−τ)−I)u(τ) +
Z t
τ
P(t−s)f(s,u(s))ds,
then
ku(t)−u(τ)kα,i
≤ m
∑
i=1
c (e
−Ai(t−τ)−I)u i(τ)
β,i
+
Z t
τ e
−Ai(t−s)f
i(s,u(s))
α,ids
≤ m
∑
i=1
ckBα
ik
B
β−α
i (e
−Ai(t−τ)−I)u i(τ)
+
Z t
τ B
α
ie−Ai(t−s)fi(s,u(s))
ds
.
Bounding the first term, lete1 > 0 an arbitrary number. Sin-ceD(Aβ−αi )is dense inX, we takev ∈ D(Aiβ−α)such that kui(τ)−vk<η, thus
+T).
Therefore, for the Lemma 3.1,uis solution of the system (1) on(t
. Thenuis a solution of the system (1)on(t is maximal, i.e., there is no solution of the system(1)on(t
B
β−α
i (e
−Ai(t−τ)−I)ui(τ)
≤
B β−α
i
(e
−Ai(t−τ)−I)u
i(τ)
≤ c
(e
−Ai(t−τ)−I)(u
i(τ)−v) + (e−Ai(t−τ)−I)v
≤ c
e
−Ai(t−τ)(u
i(τ)−v)
+kui(τ)−vk
+ (e
−Ai(t−τ)−I)v
≤ c
e−bi(t−τ)ku
i(τ)−vk+kui(τ)−vk
+ (e
−Ai(t−τ)−I)v
≤ c
e−bit1η+η+ (t−τ)β−α A
β−α
i v
≤ e1+C(t−τ)β−α.
When the last bound is given whenηis small enough such that
c(e−ai(t−τ)η+η)<e
1. Now, bounding the second term
Z t
τ B
α
ie−Ai(t−s)fi(s,u(s))
ds
≤ c
Z t
τ B
α
ie−Ai(t−s)
kfi(s,u(s))kds ≤ cMi
Z t
τ
(t−s)−αeai(t−s)ds
≤ C(t−s)1−α.
Thus, we have
ku(t)−u(τ)kα≤C
e1+ (t−τ)β−α+ (t−τ)1−α
.
Now, we considertn → t−1 and let defineun = u(tn), thus, takinge>0, we have
kun−umkα ≤ C
e1+ (tn−tm)β−α+ (tn−tm)1−α
< e.
ifn,mare large enough. Therefore,(un)is a Cauchy sequen-ce in the complete spasequen-ce Xα, thus, there exists x
1 ∈ Xα such that un → x1, it means (tn,u(tn)) → (t1,x1) and since (tn,u(tn)) ∈ B with B closed, we can conclude that (t1,x1)∈ B.
Also, sinceu:(t0,t1)→Xmis continuous andtn →t−1, we have that(tn,u(tn))→(t1,u(t1))∈ B, thus, we can conclude thatu(t1) =x1.
To finish the proof, using the Theorem 3.1 and considering (t1,x1) ∈ B ⊂ Ω, we can find an unique solution v on
(t1,t1+T(t1)) for someT(t1
1) =x1. Hence, taking
z(t) =
u(t) i f t∈[t0,t1] v(t) i f t∈[t1,t1+T(t1))
we note thatzis continuous in[t0,t1+T(t1
0) = x0 on (t0,t1+T(t1))which contradict the maximality oft1
Finally, we state that under some extra conditions the unique solution is global in time.
Theorem 3.3 Let us suppose that Ω = (τ,+∞)×Xα and
fi
more, there existsk(·)a continuous function on(τ,+∞)that verifies
kf(t,u)km≤k(t)(1+kukα)
for all(t,u)∈ Ω. Ift0 >τ,u0∈ Xα
0) =u0exists for allt>t0.
Proof.Firstly, we can note that hypothesis of the Theorem 3.2 are satisfied. Proceeding by contradiction, we taket0
0,t1)wheret1 is maximal, so, for the last result exists a sequencetn→t−1 such thatku(tn)kα→+∞. Howe-ver, sinceβ < αimpliesXαi < Xβi for alli ∈ J1,mK, taking
t∈(t,t1), by a similar procedure to the previous theorem and sinceK(·)is continuous on(τ,∞), i.e., bounded on[t0,t1], we have
ku(t)kα ≤ C
(t−t0)−(α−β)
+
Z t
t0
(t−s)−αkf(s,u(s))k
mds
≤ c
(t−t0)−(α−β)
+
Z t
t0
(t−s)−αk(s)(1+ku(s)k αds
≤ c
(t−t0)−(α−β)
+
Z t
t0
(t−s)−α(1+ku(s)kαds
≤ c+
Z t
t0
c(t−s)−αku(s)kαds
for the Bellman-Gronwall theorem, we can conclude that
ku(t)kα ≤ Ce
Rt
t0c(t−s)−αds
. ) > 0 of the system (1) with initial conditionv(t
)). So, we conclude that z is a solution of the system (1) with z(t
, the unique solution of the system(1)withu(t
>τand
assume that there exists an unique solution of the system (1) defined in(t
Further-≤ C ∀t∈(t,t1).
Which is a contradiction with the fact thatku(tn)kα → +∞ whentn →t−1
Similarly to the problem with a single equation, using the pro-perties and estimations of sectorial operators, we state a general result concerning the existence and uniqueness of solutions to systems of equations, when the diffusion terms are given by sectorial generators, also, assuming additional hypothesis on the forcing term, a result of global existence in time is pre-sented. The computations stated in the paper are based in the application of the Banach Fixed Point Theorem.
4. CONCLUSIONS
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