Besov and Triebel-Lizorkin Spaces Related to Singular Integrals with Flag Kernels
Dachun Y
ANGSchool of Mathematical Sciences Beijing Normal University
Laboratory of Mathematics and Complex Systems Ministry of Education
Beijing 100875 — People’s Republic of China [email protected]
Received: August 11, 2008 Accepted: January 8, 2009
ABSTRACT
Let s1, s2 ∈ (−1,1) and s = (s1, s2). In this paper, the author introduces the Besov space B˙pqs (R2) with p, q ∈ [1,∞] and the Triebel-Lizorkin space F˙pqs(R2) with p ∈ (1,∞) and q ∈ (1,∞] associated to singular integrals with flag kernels. Some basic properties, including their dual spaces, some equiv- alent norm characterizations via Littlewood-Paley functions, lifting properties and some embedding theorems, on these spaces are given. Moreover, the au- thor obtains the boundedness of flag singular integrals and fractional integrals on these spaces.
Key words: Besov space, Triebel-Lizorkin space, flag singular integral, flag fractional integral, Littlewood-Paley operator, dual space, lifting, embedding.
2000 Mathematics Subject Classification: 42B35, 42B20, 42B25, 46E35.
1. Introduction
In order to study the b-complex on certain quadratic CR submanifolds of Cn, Nagel, Ricci, and Stein [6] introduced the notion of singular integrals with flag kernels onRn. Since the flag singular integral is a special case of product singular integrals, the boundedness of flag singular integrals onLp(Rn) withp∈(1,∞) is a simple corol- lary of the boundedness of the corresponding product singular integrals. Recently,
The author is supported by National Science Foundation for Distinguished Young Scholars (No. 10425106) of China.
Han and Lu in [3] developed a corresponding Hardy space theory for flag singular integrals onRn.
Motivated by [3, 6, 7], letting s1, s2 ∈ (−1,1) and s = (s1, s2), in this paper, we introduce the Besov space ˙Bpqs (R2) with p, q ∈ [1,∞] and the Triebel-Lizorkin space ˙Fpqs(R2) with p∈ (1,∞) andq ∈(1,∞] associated to singular integrals with flag kernels. Some basic properties, including their dual spaces, some equivalent norm characterizations via Littlewood-Paley functions, lifting properties, and some embedding theorems on these spaces are given. Moreover, we obtain the boundedness of flag singular integrals and fractional integrals on these spaces.
For the simplicity of presentation, we work on flag integrals on R2. However, our method works for more general product Euclidean spaces.
It was proved in [5, 6] that flag kernels onR2 are closely connected with product kernels onR2×R. We denote any element ofR2×Rby the 3-tuplex= (x1, x2, x3), where (x1, x2)∈R2andx3∈R. We endowR2with the following dilation that for any δ >0 andx= (x1, x2)∈R2,δx= (δx1, δ2x2) and the norm thatkxk= (x21+|x2|)1/2, which is equivalent to |x1|+|x2|1/2. Obviously, the homogeneous dimension of R2 is 3.
In order to express the cancellation conditions introduced by Nagel, Ricci, and Stein in [6], we introduce the following terminology. Ak-normalized bump func- tion onRnis aCk-function supported on the unit ball withCk-norm bounded by 1. It was proved by Nagel, Ricci, and Stein in [6, Remark 2.1.7] that Definitions 1.1 and 1.2 given below are essentially independent of the choice ofk∈N. Hence we usually speak of normalized bump functions rather thank-normalized bump functions.
In what follows, we denote by C a positive constant which is independent of the main parameters, but it may vary from line to line. Constants with sub- scripts, such as C1, do not change in different occurrences. We also use subscripts to indicate which parameters the constant depends on. Moreover, letN≡ {1,2, . . .} andZ+≡N∪ {0}.
Definition 1.1. A product kernel onR2×R, relative to the given dilations, is a dis- tributionK onR2×Rwhich coincides with aC∞function away from the coordinate subspacexj= 0 for j= 1,2,3 and which satisfies:
(i) (Differential inequalities) For each multi-index α= (α1, α2, α3)∈(Z+)3, there exists a positive constant Cα so that
|∂αx1
1∂αx2
2∂xα3
3K(x1, x2, x3)| ≤Cαk(x1, x2)k−3−α1−2α2|x3|−1−α3 away from the coordinate subspaces, where∂xαii= ∂αi
∂xαii . (ii) (Cancellation conditions)
(a) For each multi-index (α1, α2) ∈ (Z+)2 and any given normalized bump function ϕ on R and any δ > 0, there exists a positive constant Cα1,α2
so that, for all (x1, x2)6= (0,0),
Z
R
∂xα11∂xα22K(x1, x2, x3)ϕ(δx3)dx3
≤Cα1,α2k(x1, x2)k−3−α1−2α2. (b) For each α3 ∈ Z+ and any given normalized bump function ϕ on R2
and anyδ >0, there exists a positive constantCα3 so that, for allx36= 0,
Z
R2
∂xα33K(x1, x2, x3)ϕ(δx1, δ2x2)dx1dx2
≤Cα3|x3|−1−α3. (c) For any given normalized bump functionϕonR2×Rand anyδ1, δ2>0,
there exists a positive constantC so that
Z
R2×R
K(x1, x2, x3)ϕ(δ1x1, δ21x2, δ2x3)dx1dx2dx3
≤C.
The following definition of flag kernels is just a special case of flag kernels in [6].
Definition 1.2. A flag kernel onR2, relative to the given dilations, is a distribution K on R2 which coincides with a C∞ function away from the coordinate subspace x1= 0 and which satisfies:
(i) (Differential inequalities) For eachα= (α1, α2)∈(Z+)2, there exists a positive constant Cα so that, for allx16= 0,
|∂xα11∂αx22K(x1, x2)| ≤Cα|x1|−1−α1k(x1, x2)k−2−2α2. (ii) (Cancellation conditions)
(a) For any given normalized bump functionϕ onR, any α1 ∈ Z+, and any δ >0, there exists a positive constant Cα1 so that, for allx16= 0,
Z
R
∂xα1
1K(x1, x2)ϕ(δx2)dx2
≤Cα1|x1|−1−α1.
(b) For any given normalized bump function ϕ onR, any α2 ∈ Z+, and any δ >0, there exists a positive constant Cα2 so that for allx26= 0,
Z
R
∂xα2
2K(x1, x2)ϕ(δx1)dx1
≤Cα2|x2|−1−α2.
(c) For any given normalized bump functionϕonR2, and anyδ1, δ2>0, there exists a positive constant Cso that
Z
R2
K(x1, x2)ϕ(δ1x1, δ2x2)dx1dx2
≤C.
Remark 1.3. It was pointed by Nagel, Ricci, and Stein in [6] that the single normalized bump function in Definitions 1.1 and 1.2 (ii)-(c) can be replaced by the tensor product of normalized bump functions onR2and R.
The following proposition is completely similar to Proposition 3.2 and Lemma 4.5 in [5], which reveals the relation between the product kernel and the flag kernel.
Proposition 1.4. Let K] be an integrable function on R2×R which is a product kernel as in Definition 1.1. Then, for (x1, x2)∈R2,
K(x1, x2) = Z
R
K](x1, x2−x3, x3)dx3 (1) is a flag singular kernel on R2.
Conversely, given K∈L1(R2)which is a flag kernel as in Definition 1.2, then K](x1, x2, x3) = 1
|x1|2χ x2
|x1|2
K(x1, x2+x3),
where χ is a non-negative smooth function supported on [1/2,1] such that R1
1/2χ(t)dt= 1, is an integrable product kernel on R2×Rsuch that (1)holds.
The organization of this paper is as follows. In section 2, we first establish some Calder´on reproducing formulae (see Lemma 2.3), whose dyadic version (see Lemma 2.4) are essentially included in [3]. However, in this paper, we use a slightly different way from [3] to define the topology of S∞,F(R2); see Definition 2.1 below and Definition 1.6 in [3]. Let s1, s2 ∈ (−1,1) and s = (s1, s2). With a special choice of approximations of the identity associated to flag kernels (see (1.3) of [3]), we then introduce the norms ofk·kB˙spq(R2) andk·kF˙pqs(R2)in Definition 2.5, and using the Calder´on reproducing formulae, we prove in Theorem 2.6 that these norms are independent of the choice of the approximations of the identity associated to flag kernels. Then we introduce the Besov space ˙Bspq(R2) and the Triebel-Lizorkin space F˙pqs(R2) in Definition 2.7. Some basic properties including dual spaces of these spaces are presented in Propositions 2.9, 2.10, and 2.11. In Theorems 2.8, 2.14 and Corol- lary 2.22, we establish some equivalent norm characterizations of these spaces in- cluding various Littlewood-Paley functions. We remark that Corollary 2.22 clearly reveals the difference between ˙Bpqs (R2) and ˙Fpqs(R2) with the classical product Besov and Triebel-Lizorkin spaces in [7].
The boundedness of flag singular integrals on ˙Bpqs (R2) and ˙Fpqs(R2) is given in The- orem 3.1 and the lifting properties of these spaces via Riesz potential operators is presented in Theorem 4.6.
Finally, in Theorems 5.1 and 5.2, we establish some embedding theorems on ˙Bpqs (R2) and ˙Fpqs(R2). The boundedness of flag fractional integrals is given in The- orem 5.4.
2. Besov and Triebel-Lizorkin spaces on R
2We first introduce the Calder´on reproducing formulae. To this end, we need to intro- duce some spaces of distributions; see [3].
Definition 2.1. A Schwartz functionf ∈ S(R2) is said to belong to the space of test functions,S∞,F(R2), related to flag singular integrals, if there exists a Schwartz func- tionf]∈ S(R2×R) such that, for all (x1, x2)∈R2,
f(x1, x2) = Z
R
f](x1, x2−x3, x3)dx3,
wheref] satisfies the following conditions: for allx3∈Rand (α1, α2)∈(Z+)2, Z
R2
f](x1, x2, x3)xα11xα22dx1dx2= 0, and for all (x1, x2)∈R2andα3∈Z+,
Z
R
f](x1, x2, x3)xα33dx3= 0.
We endowS∞,F(R2) with the same topology as S(R2), and we denote its dual space byS∞,F(R2)0.
Remark 2.2. It is easy to see that the spaceS∞,F(R2) is a closed subspace ofS(R2), and iff ∈ S∞,F(R2) then, for allα2∈Z+,
Z
R
f(x1, x2)xα22dx2= 0.
Let Px2(R) be the set of all polynomials on R in variable x2. Then, one can easily see that iff ∈ S∞,F(R2)0, h∈ Px2(R), andg ∈ S∞,F(R2), then hf, gi=hf, g+hi, namely,S∞(R2)0/Px2(R)⊂ S∞,F(R2)0.
We now establish the following Calder´on reproducing formulae by a method es- sentially similar to that of Theorem 3 in the appendix of [2] and a dual argument;
see also [3].
Lemma 2.3. Let ψ(1) ∈ S(R2) with R
R2ψ(1)(x1, x2)dx1dx2 = 0 and ψ(2) ∈ S(R) with R
Rψ(2)(x3)dx3 = 0 satisfy the following admissible conditions: for all (ξ1, ξ2)∈R2 and (ξ1, ξ2)6= 0,
Z ∞ 0
|ψˆ(1)(tξ1, t2ξ2)|2dt t = 1,
and, for all η ∈Rand η6= 0, Z ∞
0
|ψˆ(2)(tη)|2dt t = 1.
For t1, t2>0 and x1, x2∈R, let ψt(1)1 (x1, x2) = 1
t31ψ(1)x1
t1,x2
t21
, ψt(2)2 (x2) = 1
t2ψ(2)x2
t2
,
and
ψt1t2(x1, x2) = Z
R
ψ(1)t
1 (x1, x2−x02)ψt(2)
2 (x02)dx02. Then the identity
f(x1, x2) = Z ∞
0
Z ∞ 0
ψt1t2∗ψt1t2∗f(x1, x2)dt1
t1
dt2
t2
(2) holds in L2(R2),S∞,F(R2), and S∞,F(R2)0.
Proof. From the Plancherel principle and the assumptions of the lemma, it is easy to see that (2) holds inL2(R2). The fact that (2) holds inS∞,F(R2) and a dual argument show that (2) also holds in S∞,F(R2)0. Thus, to finish the proof of Lemma 2.3, we only need to show that (2) holds inS∞,F(R2). To do so, forf ∈ S∞,F(R2),i>0, andδi>0 withi= 1,2 and (x1, x2)∈R2, set
f1,2,δ1,δ2(x1, x2) = Z δ1
1
Z δ1
2
ψt1t2∗ψt1t2∗f(x1, x2)dt1 t1
dt2 t2
.
We only need to show that for any fixed N ∈Z+ and all (x1, x2)∈R2, there exists a positive constantC=Cf,ψ(1),ψ(2),N such that
|f(x1, x2)−f1,2,δ1,δ2(x1, x2)| ≤C 1+ 1
δ1
2+ 1 δ2
(1 +k(x1, x2)k)−N. (3) Obviously, we may assume that 0 < i < 1 < δi for i = 1,2 in (3). To prove (3), we write
f(x1, x2)−f1,2,δ1,δ2(x1, x2) = Z 1
0
Z ∞ 0
ψt1t2∗ψt1t2∗f(x1, x2)dt1
t1 dt2
t2
+ Z δ1
1
Z 2 0
· · · + Z δ1
1
Z ∞ δ2
· · · + Z ∞
δ1
Z ∞ 0
· · ·
=H1+H2+H3.
We only estimate H1. The same technique also works forH2 and H3. To estimate H1, we further decompose it into
H1= Z 1
0
Z 1 0
ψt1t2∗ψt1t2∗f(x1, x2)dt1
t1 dt2
t2 + Z 1
0
Z ∞ 1
· · · =H11+H12.
Letϕ(i)=ψ(i)∗ψ(i) fori= 1,2 andϕt1t2 =ϕ(1)t1 ∗ϕ(2)t2 . Then it is easy to see that ϕt1t2=ψt1t2∗ψt1t2. Sincef ∈ S∞,F(R2), by Definition 2.1, there exists a functionf] as in Definition 2.1 such that, for all (x1, x2)∈R2,
f(x1, x2) = Z
R
f](x1, x2−x3, x3)dx3.
Using this fact, we have ψt1t2∗ψt1t2∗f(x1, x2)
= Z
R
Z
R2
Z
R
ϕ(1)t
1 (x1−y1, x2−y2−z)ϕ(2)t
2 (z−y3)f](y1, y2, y3)dz dy1dy2dy3. By the vanishing moments ofϕ(1) andϕ(2), we further write
ψt1t2∗ψt1t2∗f(x1, x2)
= Z
R
Z
|z−y3|≤|z|/2
Z
k(x1−y1,x2−y2−z)k≤k(x1,x2−z)k/2
ϕ(1)t1 (x1−y1, x2−y2−z)
×ϕ(2)t
2 (z−y3)n
f](y1, y2, y3)−f](x1, x2−z, y3)
−
f](y1, y2, z)−f](x1, x2−z, z)o
dy1dy2dy3dz
+ Z
R
Z
|z−y3|>|z|/2
Z
k(x1−y1,x2−y2−z)k≤k(x1,x2−z)k/2
· · · +
Z
R
Z
|z−y3|≤|z|/2
Z
k(x1−y1,x2−y2−z)k>k(x1,x2−z)k/2
· · · +
Z
R
Z
|z−y3|>|z|/2
Z
k(x1−y1,x2−y2−z)k>k(x1,x2−z)k/2
· · · =I1+I2+I3+I4.
We denote the corresponding terms of H11 to Ii, respectively, by H1,i1 , where i= 1,2,3,4, and by similarity we only estimateH1,11 and H1,21 . By the mean value
theorem, we have
|I1| ≤C Z
R
Z
R
Z
R2
ϕ(1)t
1 (x1−y1, x2−y2−z)
×
|x1−y1|
(1 +k(x1, x2−z)k)N+2 + |x2−y2−z|1/2 (1 +k(x1, x2−z)k)N+2
× ϕ(2)t
2 (z−y3)
|z−y3| 1
(1 +|z|)N dy1dy2dy3dz
≤Ct1t2
Z
R
1
(1 +k(x1, x2−z)k)N+2 1
(1 +|z|)N dz≤Ct1t2
1
(1 +k(x1, x2)k)N. From this, we can easily deduce a desired estimate forH1,11 . Similarly, we have
|I2| ≤Ct1
Z
R
Z
|z−y3|>|z|/2
ϕ(2)t2 (z−y3)
|y3−z|
× 1
(1 +k(x1, x2−z)k)N+2 dy3dz
≤Ct1t2
Z
R
1
(1 +k(x1, x2−z)k)N+2 1 (1 +|z|)N dz
≤Ct1t2
1
(1 +k(x1, x2)k)N, which gives a desired estimate of H1,21 .
In what follows, we denote bybacthe integer no more thana∈R. To estimateH12, by the vanishing moments ofϕ(1) andf], we write
ψt1t2∗ψt1t2∗f(x1, x2)
= Z
R
Z
|y3|≤|z|/2
Z
k(x1−y1,x2−y2−z)k≤k(x1,x2−z)k/2
ϕ(1)t1 (x1−y1, x2−y2−z)
×
ϕ(2)t
2 (z−y3)−
bN/2c
X
γ=0
(−y3)γdγ dzγϕ(2)t
2 (z)
×[f](y1, y2, y3)−f](x1, x2−z, y3)]dy1dy2dy3dz +
Z
R
Z
|y3|>|z|/2
Z
k(x1−y1,x2−y2−z)k≤k(x1,x2−z)k/2
· · · +
Z
R
Z
|y3|≤|z|/2
Z
k(x1−y1,x2−y2−z)k>k(x1,x2−z)k/2
· · · +
Z
R
Z
|y3|>|z|/2
Z
k(x1−y1,x2−y2−z)k>k(x1,x2−z)k/2
· · · =J1+J2+J3+J4,
and we also denote the corresponding terms ofH12to Ji, respectively, byH1,i2 , where i = 1,2,3,4. By similarity, we only estimate H1,12 . The Taylor expansion theorem yields
|J1| ≤C Z
R
t1
(1 +k(x1, x2−z)k)N+2 1 t2
1
(t2+|z|)bN/2c+1dz
≤C t1
(1 +k(x1, x2)k)N+2 1 tbN/2c+12
+C t1
(1 +|x1|)N 1 t2
1
(t2+|x2|)bN/2c+1, which yields a desired estimate forH1,12 . This finishes the proof of Lemma 2.3.
Similarly, we have a ‘discrete’ version of Lemma 2.3 and we omit the details of its proof; see [3].
Lemma 2.4. Let ψ(1) ∈ S(R2) with R
R2ψ(1)(x1, x2)dx1dx2 = 0 and ψ(2) ∈ S(R) with R
Rψ(2)(x3)dx3 = 0 satisfy the following admissible conditions that for all (ξ1, ξ2)∈R2 and (ξ1, ξ2)6= 0,
∞
X
k1=−∞
|ψˆ(1)(2−k1ξ1,2−2k1ξ2)|2 = 1,
and for all η ∈ R and η 6= 0, P∞
k2=−∞|ψˆ(2)(2−k2η)|2 = 1. For all k1, k2 ∈ Z and x1, x2∈R, let ψk(1)
1(x1, x2) = 23k1ψ(1)(2k1x1,22k1x2),ψk(2)
2(x2) = 2k2ψ(2)(2k2x2), and ψk1k2(x1, x2) =
Z
R
ψ(1)k
1(x1, x2−x02)ψk(2)
2(x02)dx02. Then the identity
f(x1, x2) =
∞
X
k1=−∞
∞
X
k2=−∞
ψk1k2∗ψk1k2∗f(x1, x2) (4)
holds in L2(R2),S∞,F(R2), and S∞,F(R2)0.
We now introduce the normsk·kB˙spq(R2)andk·kF˙pqs(R2)forf ∈ S∞,F(R2)0and using Lemma 2.3, we prove that they are independent of choices ofψ(1) andψ(2).
Definition 2.5. Let ψt1t2 be the same as in Lemma 2.3 and s1, s2 ∈ R. For f ∈ S∞,F(R2)0, define
kfkB˙pqs (R2)= Z ∞
0
Z ∞ 0
t−s1 1qt−s2 2qkψt1t2∗fkqLp(R2)
dt1
t1 dt2
t2 1/q
forp, q∈[1,∞], and kfkF˙pqs(R2)=
Z ∞ 0
Z ∞ 0
t−s1 1qt−s2 2q|ψt1t2∗f|q dt1
t1
dt2
t2
1/q Lp(
R2)
forp∈(1,∞) andq∈(1,∞], where the usual modifications are made when p=∞ orq=∞.
We recall the definition of the strong maximal function: for anyf ∈L1loc(R2) and all (x1, x2)∈R2,
Ms(f)(x1, x2) = sup
(x1,x2)∈R Rrectangle
1
|R|
Z
R
|f(y1, y2)|dy1dy2.
Theorem 2.6. Let s1, s2 ∈ (−1,1) and s = (s1, s2). The norm k·kB˙spq(R2) with p, q∈[1,∞]and the norm k·kF˙pqs(R2) with p∈(1,∞) and q∈(1,∞] are independent of the choices of ψ(i) for i= 1,2.
Proof. Let ˜ψ(i) be some other functions satisfying the same conditions as ψ(i) for i = 1,2. We denote the corresponding norms, respectively, by k·k
0B˙spq(R2)
and k·k
0F˙pqs(R2) and now prove that there exists a positive constant C such that, for allf ∈ S∞,F(R2)0,
kfk
0B˙pqs (R2)≤CkfkB˙spq(R2) (5) and
kfk
0F˙pqs(R2)≤CkfkF˙pqs(R2). (6) To prove (5) and (6), by Lemma 2.3, we first need to establish a desired estimate for ˜ψu1u2∗ψt1t2. By its definition, it is easy to show that, for all (x1, x2)∈R2,
ψ˜u1u2∗ψt1t2(x1, x2) = ψ˜(1)u1 ∗ψt(1)1
∗2 ψ˜u(2)2 ∗ψ(2)t2
(x1, x2),
where, and in what follows, ∗2 denotes the convolution in the second variable. We also seta∧b= min{a, b}anda∨b= max{a, b} fora, b∈R. We claim that
(i) for allt1, u1>0 and all (x1, x2)∈R2,
ψ˜u(1)1 ∗ψ(1)t1
(x1, x2)
≤Cu1
t1 ∧ t1
u1
u1∨t1
(u1∨t1+k(x1, x2)k)4; (7) (ii) for allt2, u2>0 and allz∈R,
ψ˜(2)u2 ∗ψt(2)2 (z)
≤Cu2
t2
∧ t2
u2
u2∨t2
(u2∨t2+|z|)2. (8)
By similarity, we only show (7). To this end, by the mean value theorem and some trivial computation, we can easily prove that, for allu1>0 and (x1, x2)∈R2,
ψ˜u(1)
1(x1, x2)
≤C u1
(u1+k(x1, x2)k)4, (9) and, for allu1>0 and (x1, x2), (y1, y2)∈R2 withk(y1, y2)k ≤(u1+k(x1, x2)k)/2,
ψ˜u(1)
1(x1+y1, x2+y2)−ψ˜u(1)
1(x1, x2)
≤C k(y1, y2)k u1+k(x1, x2)k
u1
(u1+k(x1, x2)k)4. (10) The estimates (9) and (10), with ˜ψ(1)u1 and u1 replaced respectively by ψ(1)t1 and t1, also hold. We now prove (7) in the caseu1≥t1. In this case, as
Z
R2
ψt(1)
1 (y1, y2)dy1dy2= 0, we can write
ψ˜(1)u1 ∗ψt(1)1 (x1, x2)
= Z
k(y1,y2)k≤(u1+k(x1,x2)k)/2
ψ˜u(1)
1(x1−y1, x2−y2)−ψ˜u(1)
1(x1, x2)
×ψt(1)
1 (y1, y2)dy1dy2 +
Z
k(y1,y2)k>(u1+k(x1,x2)k)/2
· · ·
=D1+D2. The estimate (10) yields that
|D1| ≤C t1
(u1+k(x1, x2)k)4 Z
R2
y1 t1
,y2 t21
ψt(1)
1 (y1, y2) dy1dy2
≤C t1
(u1+k(x1, x2)k)4, and the estimates (9) for ˜ψu(1)1 andψ(1)t
1 imply that
|D2| ≤C Z
k(y1,y2)k>(u1+k(x1,x2)k)/2
ψ˜(1)u1(x1−y1, x2−y2)
t1
k(y1, y2)k4dy1dy2
+C u1
(u1+k(x1, x2)k)4 Z
k(y1,y2)k>u1/2
t1
k(y1, y2)k4dy1dy2
≤C t1
(u1+k(x1, x2)k)4,
which proves (7).
Lett, s >0 and (x1, x2)∈R2. We now estimate Z
R
t
(t+k(x1, x2)−(0, y)k)4 s (s+|y|)2dy
≤ Z
|y|≤|x2|/2
t
(t2+|x1|2+|x2−y|)2 s (s+|y|)2dy +
Z
|x2|/2<|y|≤2|x2|
· · ·+ Z
|y|>2|x2|
· · ·=E1+E2+E3. ForE1, in this case, we have that|x2−y| ≥ |x2|/2 and
E1≤ t
(t2+|x1|2+|x2|/2)2 Z
R
s
(s+|y|)2dy≤C t
(t+k(x1, x2)k)4; forE3, by the fact that
t2+|x1|2+|x2−y| ≥t2+|x1|2+|x2| ≥(t+k(x1, x2)k)2/2, we also obtain an estimate similar toE1. ForE2, we have
E2≤C t t2+|x1|2
s (s+|x2|)2
Z
R
1
(1 +|y|)2dy≤C t (t+|x1|)2
s (s+|x2|)2. Thus, for allt, s >0 and (x1, x2)∈R2,
Z
R
t
(t+k(x1, x2)−(0, y)k)4 s (s+|y|)2dy
≤C
t
(t+k(x1, x2)k)4 + t (t+|x1|)2
s (s+|x2|)2
. (11) Let M denote the Hardy-Littlewood maximal funnction on R2. Now, the esti- mates (7), (8), and (11) and Lemma 2.3 yield that
ψ˜u1u2∗f(x1, x2)
≤C Z ∞
0
Z ∞ 0
u1
t1
∧ t1
u1
u2
t2
∧ t2
u2
× Z
R2
u1∨t1
(u1∨t1+k(z1, z2)k)4 + u1∨t1
(u1∨t1+|z1|)2
u2∨t2
(u2∨t2+|z2|)2
× |ψt1t2∗f(x1−z1, x2−z2)|dz1dz2dt1 t1
dt2 t2
≤C Z ∞
0
Z ∞ 0
u1 t1
∧ t1 u1
u2 t2
∧ t2 u2
× {M(ψt1t2∗f)(x1, x2) +Ms(ψt1t2∗f)(x1, x2)}dt1
t1 dt2
t2 , (12)
which together with the Minkowski inequality and the Lp(R2)-boundedness of M andMsyields that, forp∈(1,∞),
ψ˜u1u2∗f Lp(
R2)
≤C Z ∞
0
Z ∞ 0
u1 t1
∧ t1 u1
u2 t2
∧ t2 u2
kψt1t2∗fkLp(R2)
dt1 t1
dt2 t2
. (13) The estimate (13) combined with the Minkowski inequality shows that
kfk
0B˙spq(R2)
≤C Z ∞
0
Z ∞ 0
Z u1
0
Z u2
0
t1 u1
s1+1t2 u2
s2+1
×t−s1 1t−s2 2kψt1t2∗fkLp(R2)
dt1 t1
dt2 t2
q
du1 u1
du2 u2
1/q
+C Z ∞
0
Z ∞ 0
Z u1
0
Z ∞ u2
t1 u1
s1+1t2 u2
s2−1
· · · dt1 t1
dt2 t2
q
du1 u1
du2 u2
1/q
+C Z ∞
0
Z ∞ 0
Z ∞ u1
Z u2
0
t1 u1
s1−1t2 u2
s2+1
· · · dt1 t1
dt2 t2
q du1 u1
du2 u2
1/q
+C Z ∞
0
Z ∞ 0
Z ∞ u1
Z ∞ u2
t1
u1
s1−1t2
u2 s2−1
· · · dt1
t1 dt2
t2 q du1
u1 du2
u2 1/q
=F1+F2+F3+F4.
The H¨older inequality and the assumption that si > −1 for i = 1,2 further imply that
F1≤C Z ∞
0
Z ∞ 0
t−s1 1qt−s2 2q
ψt1t2∗f
q
Lp(R2)
× Z ∞
t1
Z ∞ t2
t1 u1
s1+1t2 u2
s2+1
du1 u1
du2 u2
dt1 t1
dt2 t2
1/q
≤C Z ∞
0
Z ∞ 0
t−s1 1qt−s2 2q
ψt1t2∗f
q
Lp(R2)
dt1 t1
dt2 t2
1/q
=CkfkB˙spq(R2), where, and in what follows, we denote by q0 the conjugate index of q, namely, 1/q+ 1/q0= 1.
The same argument as for F1 also yields the desired estimates for Fi with i = 2,3,4. This proves (5) and hence, by symmetry, the independence of the normk·kB˙pqs (R2)with respect to the choice ofψ(i), fori= 1,2.
We now turn to the proof of (6). From the estimate (12), it follows that, for all u1, u2>0 and (x1, x2)∈R2,
u−s1 1u−s2 2
ψ˜u1u2∗f(x1, x2)
≤C Z ∞
0
Z ∞ 0
u1
t1 ∧ t1
u1 u2
t2 ∧ t2
u2 t1
u1
s1t2
u2 s2
×
M
t−s1 1t−s2 2ψt1t2∗f
(x1, x2) +Ms
t−s1 1t−s2 2ψt1t2∗f
(x1, x2) q dt1
t1 dt2
t2 1/q
,
which combined with Lemma 2.3 and (10) yields that kfk
0F˙pqs(R2)≤C
Z ∞ 0
Z ∞ 0
M
t−s1 1t−s2 2ψt1t2∗f
+Ms
t−s1 1t−s2 2ψt1t2∗f
qdt1 t1
dt2 t2
1/q Lp(
R2)
≤C
Z ∞ 0
Z ∞ 0
t−s1 1qt−s2 2q|ψt1t2∗f|q dt1
t1
dt2
t2
1/q Lp(
R2)
=CkfkF˙pqs(R2),
where we have used the vector-valued inequality of Fefferman-Stein in [1]. This proves (6) and, by symmetry, the independence of the norm k·kF˙pqs(R2) with respect to the choice ofψ(i)fori= 1,2 . This finishes the proof of Theorem 2.6.
Based on Theorem 2.6, we now introduce the Besov space ˙Bspq(R2) and the Triebel- Lizorkin space ˙Fpqs(R2) as follows.
Definition 2.7. Lets1, s2∈(−1,1) ands= (s1, s2). The Besov space ˙Bpqs (R2) with p, q∈[1,∞] is defined by
B˙pqs (R2) ={f ∈ S∞,F(R2)0:kfkB˙pqs (R2)<∞ };
and the Triebel-Lizorkin space ˙Fpqs(R2) withp∈(1,∞) andq∈(1,∞] is defined by F˙pqs(R2) ={f ∈ S∞,F(R2)0 :kfkF˙pqs(R2)<∞ }.
Theorem 2.6 shows that the definitions of the spaces ˙Bpqs (R2) and ˙Fpqs(R2) are independent of the choices ofψ(i)withi= 1,2.
From Lemma 2.3 and Lemma 2.4, we deduce the ‘discrete’ characterization of Besov spaces ˙Bpqs (R2) and Triebel-Lizorkin spaces ˙Fpqs(R2) as below.