Exercises on Gravitational Collapse and Black Holes
(Ph.D course by A. del Rio at the University of Valencia, 29.09.2020 - 29.10.2020)
Conventions:
We follow Wald’s book conventions. Namely, the metric signature is (−,+,+,+), the Riemann tensor is defined by [∇a,∇b]vc=:Rabcdvd, the Ricci tensor isRab:=Rcacb, and the scalar curvature isR:=gabRab.
Problems:
1. (Compactness parameter)
Given a distribution of massM and characteristic scaleR, define an adimensional quantity that allows you to decide whether general relativistic effects must be taken into account to properly describe the dynamics of the system. Then, apply this criterium to explain why GR effects are important for Neutron stars (M ∼ 1,5M, R ∼10 km), while they can be safely neglected for both the Sun (M = 1M, R∼7×105 km) and White Dwarfs (M ∼0,6M,R∼7000 km).
2. (Chandrasekhar mass limit, rigurous derivation)
(a) To obtain the equation of state of a degenerate, relativistic electron gas, recall from kinetic theory that the distribution functionf(~x, ~p) is defined so that (2πg
~)3f(~x, ~p)d3xd3pis the number of particles in a phase-space cell of volume d3xd3p. In the ideal gas approximationf is given by the Fermi–Dirac distribution, that forT = 0 (dead stars) isf = Θ(pF− |~p|), withpF the Fermi momentum. Show that
ne:= 2 (2π~)3
Z
f(~x, ~p)d3p= x3
3π2λ3e, (1)
P :=1 3
2 (2π~)3
Z
|~p|vf(~x, ~p)d3p= mec2
3π2λ3eφ(x), (2)
where x:=pF/(mec),λe=~/(mec), and φ(x) :=
Z x 0
y4dy p1 +y2 =3
8
x 2
3x2−1 p
1 +x2+ ln x+p
1 +x2
. (3)
The energy density is given byρ=µemHne, wheremHis the atomic mass unit, and the mean molecular weight µe is defined byµ−1e :=P
iZiXi/Ai in which Zi is the atomic number of an ion of typei, Xi is the mass fraction of this ion, and Ai is its atomic mass number. The equation of stateP =P(ρ) is determined in this parametric form.
(b) Introducing the parameters:
p0:= mec2
3π2λ3e, ρ0:= µemH
3π2λ3e, r02:= 1 fc2
p0
4πGρ20, m0:= 4πfc3ρ0r30, (4) and using the above results, show that the Newtonian equations of hydrostatic equilibrium, dpdr =
−ρGmr2 , dmdr = 4πr2ρ , are transformed to dxdξ = −fc
√1+x2 x
µ
ξ2, dµdξ = f13
cξ2x3, where ξ :=r/r0 and µ:=m/m0. Finally, define a new variableθ by 1 +fcθ:=√
1 +x2and get dθ
dξ =−µ
ξ2, dµ
dξ =ξ2θ3/2(θ+ 2/fc)3/2 . (5)
Argue that these ODEs must be solved with boundary conditionsθ(ξ= 0) = 1,µ(ξ= 0) = 0 and are integrated untilξ1, whereθ(ξ=ξ1) = 0. This value determines the radius of the star byR=ξ1r0, and the mass by M =µ1m0 withµ1:=µ(ξ=ξ1).
(c) Simplify the above equations in the extreme relativistic regime, fc>>1. Then, solve them nume- rically to get ξ1 = 6,897,µ1 = 2,018. Together with the approximation, fc ≈xc= (ρc/ρ0)1/3, deduce the Chandrasekhar mass:M = 1,46µ42
2
M, which is independent of the central energy density.
3. (General form of the metric in any spherically symmetric spacetime)
(i) Consider the usual metric on the round 2-sphere, h =dθ2+ sin2θdφ2, and let ξ =F(θ, φ)∂θ∂ + G(θ, φ)∂φ∂ a vector field on it. Show that the Killing equation (Lξh)ab= 0 gives
∂θF = 0, F+ tanθ∂φG= 0, ∂φF+ sin2θ∂θG= 0, (6) and that by integrating these equations the general solution is
ξ=asin(φ+b) ∂
∂θ+ [c+acos(φ+b) cotθ] ∂
∂φ (7)
where a, b, c∈R. Thus, a basis for the Lie algebra of KVF on the 2-sphere is ξ1= ∂
∂φ, ξ2= cosφ∂
∂θ −cotθsinφ ∂
∂φ, ξ3= sinφ∂
∂θ+ cotθcosφ ∂
∂φ (8)
(ii) Consider now a spacetime metric gab(x), and a set of coordinates{t, r, θ, φ}, such that the three vector fields above are Killing vector fields. Show that the Killing equation for ξ1 implies that all metric componentsgab(x) are independent ofφ, and then show that the Killing equation forξ2implies:
gtθ =gtφ=grθ =grφ =gθφ = 0, gφφ =gθθsin2θ, and gtt,gtr,grr, gθθ independent of θ. Thus, (the Killing equation forξ3does not give extra information)
ds2=gtt(t, r)dt2+ 2gtr(t, r)dtdr+grr(t, r)dr2+gθθ(t, r)(dθ2+ sin2θdφ2) (9) Now, find suitable coordinate transformations such that the metric above takes the final form
ds2=−e−2Φ(t,r)dt2+e2Λ(t,r)dr2+r2(dθ2+ sin2θdφ2) (10) This is the general form of the metric in any spherically symmetric spacetime.
4. (TOV equations).
The metric of any spherically symmetric spacetime can always be written in the form (10), with Φ = Φ(t, r), Λ = Λ(t, r) arbitrary functions. Introduce the so-called relativistic mass-energy function m(t, r) defined by
e−2Λ=: 1−2Gm(t, r)
r ≡f(t, r) (11)
Assume a body in hydrostatic equilibrium (i.e.m=m(r), Φ = Φ(r)), and that the body is described by a perfect fluid, with energy-momentum tensor
Tab= (ρ+p)uaub+pgab (12)
where ρ,p,ua are the proper energy density, pressure and 4-velocity field of the fluid, respectively. In the coordinates above the normalized vector isu=√1
−g00
∂
∂t.
(i) Show that the ttcomponent of Einstein’s equationGab= 8πGTab leads to dm
dr = 4πr2ρ (13)
(ii) Show that the rrcomponent of Einstein’s equationGab= 8πGTab leads to dΦ
dr =− G
r2f(r)(m(r) + 4πr3p(r)) (14)
(iii) Show that ther component of the stress-energy conservation equation∇aTab= 0, together with the above results, leads to
dp
dr =−G(ρ(r) +p(r))
r2f(r) (m(r) + 4πr3p(r)) (15)
These are the Tolman-Oppenheimer-Volkoff equations. They describe the hydrostatic equilibrium of static, spherically symmetric bodies.
5. (Maximum mass for neutron star in the incompressible fluid approximation)
(a) The Tolman-Oppenheimer-Volkoff (TOV) equations describe the hydrostatic equilibrium of static, spherically symmetric relativistic bodies. Given an equation of stateP=P(ρ), they must typically be integrated numerically. The case of an incompressible fluid (ρ =ρ0 constant) is illustrative and can be solved analytically. Solve TOV equations with boundary conditions p(r= 0) =pc,p(r=R0) = 0, m(r= 0) = 0,m(r=R0) =M, and show that
p(r) =ρ0c2
p1−Rr2/R30−p
1−R/R0 3p
1−R/R0−p
1−Rr2/R30, (16)
where R = 2GM/c2. The central pressure is then pc = 1−
√1−R/R0
3√
1−R/R0−1. Using this formula show that there is a critical massMcthat cannot be exceeded if the body is to remain in hydrostatic equilibrium, and is given by
Mc = r 3
4πρ0
4c2 9G
3/2
= 5,7M
4×1017kg/m3 ρ0
1/2
. (17)
What is the value of this bound (in solar mass units) for typical neutron star densities (∼1017kg/m3∼ 10−13M/m3)? You can use the useful relation Gc2M= 1500 m.
(b) Solve TOV equations in the Newtonian limit, still in the case of an incompressible fluid, and find p(r) =−2πG
3 ρ20(r2−R20). (18)
Does the Newtonian result predict the existence of an upper mass limit? Justify your answer.
6. (Buchdahl’s theorem)
The existence of upper mass limits in GR is not an artifact of having restricted consideration to stars of uniform density. Buchdahl’s theorem states that any reasonable (ρ(r)≥0,dρ/dr≤0) static, spherically symmetric interior solution must haveM ≤4R9G in order to remain in equilibrium.
Using the spherically symmetric metric (10) and (11), it can be shown that the equation Grr = 8πG p e2Λ= Grθθ2 e2Λ leads to
d dr
q
1−2mGr r
d dre−Φ
= e−Φ q
1−2mGr d dr
Gm(r)
r3 (19)
(i) Imposing dρdr ≤0, and using the fact that the interior solution of the star must join smoothly to the Schwarzschild solution, show that this formula implies
q
1−2mGr r
d
dre−Φ≥ M G
R3 (20)
where M andRare the mass and the radius of the star.
(ii) Integrate from 0 toR to find e−Φ(0)≤
r
1−2M G R −M G
R3 Z R
0
rdr q
1−2mGr
(21)
(iii) Argue that dρdr ≤0 impliesm(r)≥ M GrR33.
(iv) Show then that e−Φ(0)≤
r
1−2M G R − M
R3 Z R
0
rdr q
1−2M GrR3 2
=3 2
r
1−2M G R −1
2 (22)
and conclude that necessarily M ≤ 4R9G. 7. (Well definite causal character of geodesics)
Show that if a geodesic is timelike, null, spacelike, at a given point of spacetime, then it is timelike, null, spacelike at any other point in the curve.
8. (Maximally symmetric spacetimes)
(a) Let ζ be a Killing vector field. Prove that the set of all Killing vector fields on a spacetime form a vector space on the real numbers. Prove then that ∇a∇bζc=Rcbadζd, whereRabcd is the Riemann tensor. A corollary of the latter result is that a Killing vector fieldζa is completely determined by the values of ζa and Lab := ∇aζb at any particular point. Argue then that on a spacetime of dimension n there can be at most n(n+1)2 linearly independent Killing vector fields (and thereby at most an
n(n+1)
2 parameter group of isometries). An-dimensional spacetime that has n(n+1)2 isometries is called maximally symmetric.
(b) Prove that the Riemann tensor of a maximally-symmetric,n-dimensional spacetime satisfiesRabcd=
R
n(n−1)[gacgbd−gbcgad], where R is the scalar curvature. First, use the previous result and the Ricci identity to write∇[a∇b]∇cξd in terms of the Riemann tensor and to find
(Rabceδdg+Rabdgδce−Rdcbgδae+Rdcagδbe)∇eξg= (∇aRdcbe− ∇bRdcae)ξe . (23) Now, if the space is maximally symmetric one can always find, at any point, a basis whose Killing vectors vanish but their derivative does not. This impliesRabc[eδg]d+Rabd[gδe]c−Rdcb[gδe]a+Rdca[gδbe] = 0.
Contracting indices and using properties of the Riemann tensor one gets the desired result.
9. (Symmetries and conserved quantities)
SupposeVa is a Killing vector field andTabis any stress-energy tensor.
(i) Show thatJa:=TabVb is a conserved current. InterpretJa whenV is timelike.
(ii) Given a spacelike hypersurface Σ, ifTab has compact spatial support (i.e. that vanishes outside a closed and bounded set in any spacelike hypersurface), show that the integral
QV :=
Z
Σ
TabVbnadΣ (24)
where na is a unit timelike vector normal to Σ, is independent of the choice of spacelike hypersurface Σ. Thus,QV is “conserved in time”.
10. (Birkhoff’s theorem)
The non-vanishing components of the Einstein tensorGabassociated to the metric (10) of any spheri- cally symmetric spacetime are given by
Gtt = 2e−2(Λ+Φ)Λ,r
r +e−2Φ1−e−2Λ(t,r)
r2 (25)
Gtr = 2Λ,t
r (26)
Grr = −2Φ,r
r +1−e2Λ(t,r)
r2 (27)
Gθθ = Gφφ
sin2θ =−r2e−2Λ(Φ,rr−Φ2,r−Φ,rΛ,r+Φ,r+ Λ,r
r )−r2e2Φ(Λ,tt+ Λ2,t+ Φ,tΛ,t) (28) Show that any vacuum spherically symmetric spacetime is locally isometric to Schwarzschild solution.
11. (Geodesics of Schwarzschild solution)
Consider a test particle that orbits a Schwarzschild black hole of mass M with non-zero angular mo- mentum per unit massL. Without loss of generality, (due to spherical symmetry and parity invariance) we can restrict attention to study equatorial geodesics. Consider k with values k = 0 and k = 1 for massless (null) and massive (timelike) test particles, respectively.
(i) Show that the orbits satisfies:
1
2r˙2+V(r) = 1
2E2 (29)
where E is a constant, V(r) = 12(1−2Mr )(Lr22 +k). This equation shows that the radial motion of a geodesic is the same as that of a unit mass particle of energy E2/2 in an ordinary one-dimensional effective potential V(r). [Hint: no need to use the geodesic equation, make use of the constants of motion]
(ii) Show that the orbits further satisfies d2u
dφ2 +u= M k
L2 + 3M u2 (30)
where u= 1/randφis the azimutal angle.
(iii) Show that unstable circular geodesics of photons exist at radius R= 3M (this is called the ”light ring”)
(iv) Show that no stable timelike circular geodesics exists forR <6M (R= 6M is called the innermost stable circular orbit (ISCO)).
12. (Light escaping to infinity)
A photon is emitted outward from a pointP outside a Schwarzschild black hole with radial coordinate r in the range 2M < r < 3M. Show that if the photon is to reach infinity the angle ψ its initial direction makes with the radial direction (as determined by a stationary observer atP) cannot exceed
sinψ= s
27M2 r2
1−2M
r
(31) [Hint: find a local orthonormal basis at each point, {eai(x)}i=t,r,θ,φ, that satisfies gab = ηijeiaejb with ηij= diag(−1,1,1,1) such thateat is the observer’s 4-velocity (this is called a “4-bein”); ifua denotes the tangent vector of the light geodesic, calculate first tanψ= uuaaeeφar
a
and then use it to obtain sinψ]
13. (Geodesic incompleteness of Schwarzschild black hole)
Show that in region II of the Kruskal manifold one may regard ras a time coordinate and introduce a new spatial coordinatexsuch that
ds2=− 1
2m
r −1dr2+ 2m
r −1
dx2+r2(dθ2+ sin2θdφ2) (32) Hence show that every timelike curve in region II intersects the singularity atr= 0 within a proper time no greater than πM. For what curves is this bound attained?
14. (Vaidya spacetime)
Take Schwarzschild metric in outgoing Eddington-Finkelstein coordinates, and letM be now a function of retarded time, M =M(u). Show that this metric is a solution of non-vacuum Einstein’s equations, and find the correspondingTab. Give a physical interpretation.
15. (Gravitational Redshift formula)
Consider two static observers in Schwarzschild geometry (i.e. observers whose 4-velocity is tangent to the static Killing fieldk= ∂t∂)O1, O2 whose 4-velocities areu1,u2, respectively. SupposeO1 emits a light signal at eventP1which is received byO2 at eventP2. The light signal travels on a null geodesic, with tangent vector ξa. The frequency of emission is ω1 =−ξaua1|P1 while the frequency of reception isω2=−ξaua2|P2. Show that
ω1 ω2
= s
1−2M/r2 1−2M/r1
(33) Given the maximum value Rmax=9M4 found in a previous exercise for a static spherically symmetric body in equilibrium, show that the maximum redshift of light emitted from the surface of a star is
z= ω1
ω2
max
−1 = 2. (34)
This rules out the possibility that observed redshifts greater than 2 (as commonly found for quasars) could arise solely from the gravitational redshift, indicating that the corresponding sources are located at cosmological distances.
16. (Conformal Killing field)
A vector field ξis said to be a conformal Killing vector if
(Lξg)ab= Λ2gab (35)
for some non vanishing function Λ. It is said that ξ is the generator of conformal transformations of the metric.
(a) If ξ is a Killing vector of gab, (Lξg)ab = 0, show that ξ is then a conformal Killing vector of the conformally transformed metric Λ2gab for any non-vanishing conformal factor Λ.
(b) Show that the action for amasslesstest particle S[x, e] = 1
2 Z
dλe−1(λ)gab(x(λ)) ˙xa(λ) ˙xb(λ) (36) is invariant, to first order in the constantα, under the transformation
xa→xa+αξa, e→e+α
4egab(Lξg)ab (37)
if and only if ξis a conformal Killing vector. Would the action of a massive test particle be invariant under the same transformation?
(c) In view of the above result, explain why Carter-Penrose diagrams provide accurate descriptions of the causal structure of the spacetime.
17. An observer (not necessarily freely-falling) orbits a Kerr black hole in the equatorial plane (θ=π2).
(a) Let his orbit be at constant r. Define Ω = dφdt to be his angular velocity relative to a distant stationary observer. In terms of Ω,r,M, a, find the (normalized) observer’s 4-velocityua andua. (b) Suppose that the circular orbit lies in the ergosphere. Show that the observer cannot remain at rest with respect to the distant observer. That is, show that Ω must be nonzero.
(c) If the observer is in the regionr−< r < r+, show that he cannot remain at constant radius.
18. (Kepler law for Kerr spacetime)
Show that the generalized Kepler law for circular, equatorial orbits around a Kerr black hole of mass M and angular momentum per unit massais
Ω2± :=
dφ dt
2
= M
(±r3/2+aM1/2)2 (38)
[Hint: focus on thercomponent of the geodesic equation] What are the two signs physically indicating?
19. (Geodesic equation in Kerr)
The equations governing geodesic motion in the Kerr spacetime were given without justification. Here we provide a derivation, which is valid both for timelike and null geodesics.
(a) By definition, a Killing tensor fieldξabis one which satisfies the equationξ(ab;c)= 0. Show that if ξab is a Killing tensor and ua satisfies the geodesic equationuaub;a = 0, thenξabuaub is a constant of the motion.
(b) Verify that ξαβ = ∆k(αlβ)+r2gαβ is a Killing tensor field of the Kerr spacetime. Here l =
r2+a2
∆ ∂t−∂r+∆a∂φ andk= r2+a∆ 2∂t+∂r+∆a∂φ are the null vectors that were introduced to derive the Kerr metric in Kerr coordinates.
(c) Write the equations E = −taua, L = −φaua explicitly in terms of ua = ( ˙t,r,˙ θ,˙ φ). Then invert˙ these relations to obtain the equations for ˙t, ˙φ. [Hint: Make sure to involve the inverse metric.]
(d) The Carter constantQis defined byξabuaub=Q+ (L−aE)2. By working out the left-hand side, derive the equation for ˙r. [Hint: Expresska andla in terms of the Killing vectors, and thenξabuaub in terms ofE ,L, and ˙r2. ]
(e) Finally, use the normalization condition gabξaξb = −a, (where a = 1 for timelike geodesics and a= 0 for null geodesics) to obtain the equation for ˙θ.
20. (Killing horizons and surface gravity of a Kerr BH).
The Kerr metric can be expressed as ds2=−
1−2M r ρ2
dv2+ 2dvdr−2asin2θdrdψ−4M arsin2θ
ρ2 dvdψ+ Σ
ρ2sin2θdψ2+ρ2dθ2, (39) whereρ2=r2+a2cos2θ, and Σ = r2+a22
−a2∆ sin2θwith ∆ =r2+a2−2M r. In these coordinates {v, r, θ, ψ}, called “ingoing”, the metric is well behaved on the Future Event Horizon r =r+ [where r+=M+√
M2−a2is one of the two roots of ∆(r) = 0].
(a) Show that ξ = ξa ∂∂xa = ∂v∂ + ΩH ∂
∂ψ, where ΩH = a2+ra +2, is a Killing Vector Field of the Kerr metric [no need of any explicit calculation!]. Then show that, on r = r+, we have ξa = gabξb = (1−aΩHsin2θ)∇arandξaξa = 0. Justify, in light of these results, that the Event Horizon is a Killing Horizon ofξ.
(b) To every Killing Horizon we can associate a quantity called surface gravityκ, defined byξb∇bξa= κξa. Show that this equation is equivalent to ∇a(−ξbξb) = 2κξa.
(c) Use this alternative expression to derive the surface gravity of the Kerr BH:
κ=r+−M r2++a2 =
√M2−a2
r2++a2 . (40)
You may take the following steps. First, find the expression:
gabξaξb=gψψ
ΩH+ gψv
gψψ
2
+gvvgψψ−g2vψ gψψ
=Σ sin2θ ρ2
ΩH−2M ar Σ
2
−ρ2∆
Σ . (41)
Second, prove the identities ∆(r+) = 0 and ΩH= 2M arΣ(r +
+), and use them to deduce:
−ξbξb
;a|r=r+= ρ2
Σ∆,a. (42)
Finally, use the result of section (b). A few lines of algebra will carry you to the desired result forκ.
21. (Smarr’s Formula)
Check the algebraic relation
M = 2ΩHJ+κA
2π (43)
where ΩH,M,J,A,κare the angular velocity of horizon, mass, angular momentum, area, and surface gravity of the Kerr black hole. This is known as the Smarr’s formula, and it can be shown to generalize to any Black Hole spacetime.
22. (1st Law of BH mechanics)
Suppose that a Kerr black hole of massM and angular momentumJ is perturbed momentarily so that it ends in another Kerr black hole of parameters becomeM +δM J+δJ. Prove that
κ
8πδA=δM−ΩHδJ . (44)
This is known as the 1st Law of Black hole mechanics, and it can be shown to generalize to any Black Hole spacetime.