2.2 DISEÑO MECÁNICO
2.1.3 ANÁLISIS DE ESFUERZOS EN SOLIDWORKS DE LAS PIEZAS
In this section we will explicitly compute the local parameters of the local lift from GSO(X, Fv) to GSp(2, Fv) for the unramified case as we did in Chapter 5. As
in Chapter 5, the groups GSO(X, Fv),GSp(n, Fv), etc are all denoted simply by
is finite. Also “Ind ” always means unnormalized induction, and whenever we use normalized induction, we use the notation “n-Ind ”. Thus, for example, if π is the principal series representation of G = GL(4) fully induced from the standard parabolic P by the four unramified characters χ1, χ2, χ3, χ4, then we have π ∼=
n-IndGP(χ1χ2χ3χ4) = IndGP( ˜χ1χ˜2χ˜3χ˜4) , where ˜χ1 = | · |3/2χ1, ˜χ2 =| · |1/2χ1, ˜χ3 =
| · |−1/2χ
2, and ˜χ4 =| · |−3/2χ4.
First we need the following, which seems to be well-known by now.
Lemma B.4.1. Letτ be the character on the standard parabolicP2 of GSp(2)which
is trivial on the unipotent radical and sends diag (α1, α2, γα−11, γα
−1
2 )7→τ0(γ)τ1(α1)τ2(α2)
for unramified characters τ0, τ1, and τ2. If Π is the unramified subquotient of the
representation of GSp(2) give by n-IndGSpP (2)
2 τ, then the Langlands parameter of Π
is
diag (χ0($), χ0χ1($), χ0χ1χ2($), χ1χ2($))∈GSp(2,C) = LGSp(2)◦, where $ is the uniformizer of F.
By using this together with the techniques from Chapter 5, we prove
Proposition B.4.2. Assume π is an unramified representation of GL(4) with a unitary central character which is fully induced from four unramified characters
χ1, χ2, χ3, χ4, i.e. π ∼= n-Ind
GL(4)
P χ1χ2χ3χ4, and the central character ofπ isχ2, i.e.
χ1χ2χ3χ4 =χ2. Leteπ be the unramified representation of GSO(X)that corresponds
to πby Proposition B.2.3. If πecorresponds to an unramified Π∈Irr(GSp(2)) under theta correspondence, then the Langlands parameter of Π is
diag (χ1($), χ3($), χ2($), χ4($))∈GSp(2,C).
Proof. Let eπ∼= IndQGSO(3 X)µ whereµ acts onMQ3 by
diag (β1, β2, β3, λβ3−1, λβ
−1 2 , λβ
−1
1 )7→µ0(λ)µ1(β1)µ2(β2)µ3(β3),
withQ3the parabolic subgroup preserving the flaghx12i ⊂ hx12, x13i ⊂ hx12, x13, x14i,
and xij’s as in Section B.2. Then we have µ0 = χ | · |3/2χ 1 , µ1 = | · |2χ 1χ2 χ , µ2 = | · |χ1χ3 χ , µ3 = χ1χ4 χ .
There is a non-zero R-homomorphism
ωX,2 −→Π⊗Ind
GSO(X)
Q3 µ= Ind
GSp(2)×GSO(X)
Since there is a natural injection IndGSp(2)GSp(2)××GSO(Q X)
3 Π⊗µ ,→Ind
R
R∩(GSp(2)×Q3)Π⊗µ
(see Lemma 5.1.4), we have a non-zero R-homomorphism
ωX,2 −→IndRR∩(GSp(2)×Q3)Π⊗µ.
Let Qbe the parabolic subgroup preserving the flag hx12, x13, x14i. Then by induc-
tion in stages, we have a non-zero R-homomorphism
ωX,2 −→IndRSQInd
MQ
SQ3Π⊗µ, where SQ and SQ3 are as in Proposition 5.1.1.
Now if we take the Jacquet module of ωX,2 with respect to NQ, the Frobenius
reciprocity and Proposition 5.1.1 give non-zero R-homomorphisms 0⊂J(2) ⊂J(1) ⊂J(0) −−−−→ϕ IndMQ
SQ3Π⊗µ.
First assume that kerϕ⊇J(1). Then there is a non-zero M
Q-homomorphism I(0) =J(0)/J(1) −→IndMQ
SQ3Π⊗µ.
Then if we take the Jacquet module of I(0) with respect to N
Q3, the Frobenius
reciprocity and Proposition 5.1.1 give a non-zero MQ3-homomorphism
IndMQ3
SP0,Q3σ0,3 ∼
=σ0,3 −→Π⊗µ,
whereσ0,3is as in Proposition 5.1.1. Then on the element of the form ((1), β1, β2, β3)∈
MQ3 acts σ0,3 by the character
((1), β1, β2, β3)7→ |β1|2|β2|2|β3|2.
On the other hand, it acts on Π⊗µby the character
((1), β1, β2, β3)7→µ1(β1)µ2(β2)µ3(β3).
Therefore we must have µ3 = | · |2. But this is impossible, because µ3 = χ1χ4/χ
and so |µ3|<| · |. Thus kerϕ+J(1).
Then by restricting ϕto J(1), we have non-zero M
Q-homomorphisms
0⊂J(2) ⊂J(1) ϕ
0
−−−−→IndMQ
SQ3Π⊗µ.
Then if kerϕ0 ⊇J(2), we have a non-zero M
Q-homomorphism I(1) =J(1)/J(2) −→IndMQ
Then by exactly the same argument as above, this leads to a contradiction. There- fore kerϕ0 +J(2).
Then by restricting ϕ0 toJ(2), we have a non-zero M
Q-homomorphism J(2)(= I(2))−→IndMQ
SQ3Π⊗µ. If we take the Jacquet module of I(2) with respect toN
Q2, the Frobenius reciprocity
and Proposition 5.1.1 give a non-zero MQ3-homomorphism
IndMQ3
SP2,Q3σ2,3
ϕ00
−−−−−→Π⊗µ.
Then the element of the form ((1), β1, β2, β3) ∈ MQ3 acts on Ind
MQ3
SP2,Q3σ2,3 by the
character
((1), β1, β2, β3)7→ |β1|2τ2(β2)τ3(β3),
and on Π⊗µby the character
((1), β1, β2, β3)7→µ1(β1)µ2(β2)µ3(β3).
Thus we have
µ1 =| · |2, µ2 =τ2, µ3 =τ3.
Moreover, since µ1 =| · |2χ1χ2/χand χ1χ2χ3χ4 =χ2, we have
χ=χ1χ2 =χ3χ4.
Next notice that MQ3 ∼= GSp(2)×G
3 m. Then by restricting ϕ 00 to the elements of the form ((g),1,1,1) ∈ GSp(2) × G3 m ∼= MQ3, we have a non-zero GSp(2)- homomorphism IndGSp(2)P 2 σ 0 2,3 −→Π⊗µ −1 0 ,
where σ20,3 is the character on P2 given by
σ02,3( α1 ∗ ∗ ∗ 0 α2 ∗ ∗ 0 0 λα−11 ∗ 0 0 0 λα2−1 = (| · |2τ3−1)(α1)(| · |2τ2−1)(α2)(| · |−1τ2τ3)(λ),
and Π⊗µ−01 is the twist of Π by µ0 through the multiplier character ν, i.e. (Π⊗
µ0)(g) =µ0(g)Π(g). Hence we have a non-zero GSp(2)-homomorphism
(IndGSp(2)P
2 σ
0
2,3)⊗µ0 −→Π,
where the twisting is again via ν. It is easy to see that (IndGSp(2)P 2 σ 0 2,3)⊗µ0 ∼= Ind GSp(2) P2 τ,
where τ is the character onP2 given by τ( α1 ∗ ∗ ∗ 0 α2 ∗ ∗ 0 0 λα−11 ∗ 0 0 0 λα−21 ) = (| · |2µ−1 3 )(α1)(| · |2µ−21)(α2)(| · |−1µ0µ2µ3)(λ) = (| · |2χχ−11χ4−1)(α1)(| · |χχ−11χ −1 3 )(α2)(| · |−3/2χχ−21)(λ) = (| · |2χ3χ−11)(α1)(| · |χ4χ1−1)(α2)(| · |−3/2χ1)(λ).
Thus Π is an unramified quotient of n-IndGSp(2)P
2 τ 0, where τ0 is given by τ0( α1 ∗ ∗ ∗ 0 α2 ∗ ∗ 0 0 λα−11 ∗ 0 0 0 λα−21 ) = (χ3χ−11)(α1)(χ4χ−11)(α2)(χ1)(λ).
Thus by Lemma B.4.1, the Langlands parameter of Π is
diag (χ1($), χ3($), χ2($), χ4($))∈GSp(2,C).