SOBRE LA APLICACIÓN DE LOS PRINCIPIOS DE SUBSIDIARIEDAD Y PROPORCIONALIDAD

This section describes the steps required to perform the NPUSCH format 1 UE procedure. In Figure 5.3, each step is enumerated inside a circle.

Figure 5.3: Overall NPUSCH format 1 UE procedure.

1. The first step consists on the detection of a NPDCCH by the UE, which after parsing supplies the DCI format N0, that includes relevant parameters to send a transport block on the NPUSCH. Besides the DCI format N0 values, this transmisison gives the UE the Radio Network Temporary Identifier (RNTI). When the NPDCCH is codified, in the CRC addition step, the RNTI parameter is used to scramble the obtained CRC bits. DCI format N0 is composed of 23 bits ordered according to Figure 5.4. Starting with the MSb, the following information is received [3GP17a]:

• 1 bit corresponding to the DCI format flag: – ’0’ for format N0.

– ’1’ for format N1 (section 5.5).

• 6 bits corresponding to the subcarrier indication field (Isc).

• 3 bits corresponding to the resource assignment indication field (IRU). • 2 bits corresponding to the scheduling delay indication field (I_Delay).

• 4 bits corresponding to the modulation and coding scheme indication field (IM CS). This value, combined with IRU allows the TBS calculation.

• 3 bits corresponding to the repetition number indication field (I_Rep). • 1 bit corresponding to the new data flag.

• 2 bits corresponding to the DCI subframe repetition number.

Figure 5.4: Contents of DCI format N0 [DT17].

2. The second step consists in sending the corresponding NPUSCH format 1 in NRep × NRU × N_slotsU L consecutive slots. The value of N_slotsU L is the number of slots in the selected resource unit given in Table 2.2. The NRU is determined by the resource assignment field in the corresponding DCI, according to Table 5.1.

The number of subcarriers allocated to NPUSCH (nsc) is given by the Isc present in the DCI format N0, determined according to Table 5.2.

Table 5.1: NRU obtained accord- ing to IRU value. IRU NRU 0 1 1 2 2 3 3 4 4 5 5 6 6 8 7 10

Table 5.2: Values of allocated subcarriers nsc depending on the sub- carrier indicator Isc. Subcarrier spacing (∆f ) Isc nsc 3.75kHz 0-47 Isc 48-63 Reserved 15kHz 0-11 Isc 12-15 3(Isc− 12) + 0, 1, 2 16-17 6(Isc− 16) + 0, 1, 2, 3, 4, 5 18 {0,1,2,3,4,5,6,7,8,9,10,11} 19-63 Reserved

When ∆f is 3.75kHz, a range of values from 0-47 assigns the subcarrier to be used. An example is shown on Figure 5.5a. If ∆f is 15kHz, a range of values from 0-18 assigns the subcarriers to be used. If Iscis bigger then 11, several subcarriers are utilized. 12, 13, 14 and 15 indicates three subcarriers are used, corresponding to one of four quarters of the resource block. 16 and 17 indicate either the top or bottom half of the resource block is selected. 18 indicates all the subcarriers are chosen. This arrangement is depicted in Figure 5.5b.

The modulation order (Qm) and the transport block size indication field (IT BS) is determined using the the IM CS, according to Table 5.3.

The total number of repetitions (NRep) is determined by the IRep present in the DCI format N0, according to Table 5.4. One transport block can be repeated several times.

(a) Allocated subcarriers as indicated by nsc when ∆f = 3.75kHz.

(b) Allocated subcarriers as indicated by nscwhen ∆f = 15kHz.

Figure 5.5: Allocated subcarriers as indicated by nsc [DT17].

Table 5.3: Qm and IT BS obtained according to the IM CS value. Number of subcarrier (N_scRU) IM CS Qm IT BS 3/6/12 subcarriers 0-12 2 IM CS 1 subcarrier 0 1 0 1 1 2 2 2 1 3 2 3 4 2 4 5 2 5 6 2 6 7 2 7 8 2 8 9 2 9 10 2 10

Table 5.4: NRep ob- tained according to the IRep value. IRep NRep 0 1 1 2 2 4 3 8 4 16 5 32 6 64 7 128

The arrangement of the repetitions depends on number of consecutive subcarriers in a resource unit (N_scRU), the subcarrier spacing (∆f ) and the total number of repetitions (NRep). This is exemplified in Figure 5.6.

The description of Figure 5.6 goes as follows:

(a) Let’s consider ∆f is 15kHz and a transport block is transmitted on two RUs, named T and W .

(b) Each RU has eight slots and, consequently, three subcarriers - Table 2.2. T1 corre- sponds to the first slot of the first RU and W1 corresponds to the first slot of the second RU, and so forth.

(c) Let’s assume a total number of eight repetitions is applied (NRep = 8) First, slots T1 and T2 are transmitted. This pair is repeated three more times. Therefore, four transmissions of these slots occur. This procedure is continued until the slots W7 and W8 are pairwise transmitted four times. Finally, the transmission sequence is repeated once again, reaching the eight repetitions.

When ∆f is 15kHz, the first repetition of two slots is always done - number of grouped slots (Nslots) = 2. When ∆f is 3.75kHz, it is done for every slot separately - number of grouped slots (Nslots) = 1. If the RU has more than one subcarrier (NscRU > 1), the number of repetitions of grouped slots (MN P U SCH

identical ) is half the number of NRep, with an upper limit of four. Otherwise, if the RU has only one subcarrier, this value is one. For instance, in Figure 5.6, if there would be 64 repetitions, the M_identicalN P U SCH number would be the same. However, the total sequence would be repeated 15 additional times - scheduled number of repetitions of a NPUSCH transmission (MN P U SCH

Rep ) = 16 [Roh16].

Figure 5.6: Example of an arrangement for NPUSCH transmission with 8 repetitions. For the case of no repetitions, the slot sequence shown in (b) would be transmitted [Roh16].

The IT BS, used in combination with the IRU, determines the TBS according to Table 5.5 [3GP17b].

Table 5.5: TBS obtained according to IT BS and IRU values. IT BS IRU 0 1 2 3 4 5 6 7 0 16 32 56 88 120 152 208 256 1 24 56 88 144 176 208 256 344 2 32 72 144 176 208 256 328 424 3 40 104 176 208 256 328 440 568 4 56 120 208 256 328 408 552 680 5 72 144 224 328 424 504 680 872 6 88 176 256 392 504 600 808 1000 7 104 224 328 472 584 712 1000 - 8 120 256 392 536 680 808 - - 9 136 296 456 616 776 936 - - 10 144 328 504 680 872 1000 - - 11 176 376 584 776 1000 - - - 12 208 440 680 1000 - - - -

rvidxis determined by the resource assignment field in the corresponding DCI according to equation 5.1.

rvidx= 2 × mod(rvdci, 2) (5.1)

Coding and modulation of the NPUSCH format 1 physical channel is done according to section 3.1.