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2. GESTIÓN Y FINANCIACIÓN PRIVADA DE INFRAESTRUCTURAS DE TRANSPORTE

2.5 D ESARROLLO EN EL ÁMBITO MUNDIAL DEL SISTEMA CONCESIONAL

This section is similar to Gertler and Karadi (2011) (hereby GK2011). Having

one more financing instrument makes up for few differences.In this Appendix I will:

(a) set up a one-to-one relationship between leverage and excess return on assets for any fixed moral hazard parameterΘB,

(b) derive expression for these excess returns, and

(c) show that banks’ choice on leverage and excess returns does not depend on bank sepcific factors, therefore allowing for aggregation.

The value of the bank is homogenous to degree one in net worth and given the linear relationship in the balance sheet equation 3.40, then VB

i,t should be homogenous of degree one inBi,t, ABi,t as well asLi,t andSi,t.

ViB,t(Li,t,Bi,t,Si,t) =νLi,tLi,t+νsi,tQtSi,t−νBi,tBi,t (B.59)

where QtSi,t =κAi,t and Li,t = (1−κ)ABi,t. νLt, νst and νBt are the marginal values of respective asset as of end of period. Using balance sheet equation

3.38 the value function is:

ViB,t(Li,t,Ni,t,Si,t) =µLi,tLi,t+µsi,tQtSi,t+νBi,tNBi,t (B.60)

- the incentive constraint eq. 3.42: VB

i,t>ΘAi,t - equationB.60: VB

i,t =µLi,tLi,t+µsi,tQtSi,t+νBi,tNBi,t The Lagrangean`=ViB,t+λBt(ViB,t−ΘB(ABi,t))becomes:

`=µLi,tφBi,t(1−κ) +µsi,tφBi,tκ+νBi,t(1+λBi,t) −λBi,tΘBφBi,t (B.61)

λBi,t > 0if the constraint (IC) binds, orλBi,t=0if it does not.

First order conditions with respect (φi,t, κ and λi,t KT1 and KT2) when IC constraint binds are:

foc1. φB i,t: 0= (1+λBi,t)(µLi,t(1−κ) + (µLi,tκ)) −λBi,tΘB (B.62) foc2. λi,t: 0=µLi,tφBi,t(1−κ) +µsi,tφBi,tκ+νBi,t−ΘBφBi,t (B.63) KT 2: λBt>0 (B.64)

My interest is when the IC binds λBi,t > 0, the KT1 condition B.63 leads to

an expression relating leverage to bank premium:

φBi,t= ν B i,t

ΘB−µLi,t(1−κ) −κµsi,t

where φBi,t = A B i,t

NBi,t. For non-binding IC, i.e. λ B

i,t = 0, then the 1−st FOC implies µLi,t=0. Hence, (1−κ)µLi,t=max " 0,ΘB− νBi,t φBi,t −κµ s i,t # (B.66)

Now I need to relate the µLi,t and µSi,t to respective returns of Li,t and Si,t financing instruments. In terms of leverage equationB.60is:

ViB,t =µLi,t(1−κ)φBi,t+κµis,tφBi,tiB,tNBi,t (B.67)

whereµLi,t=νLi,t−νBi,t is the excess value of all loans over cost of depositsRt+1

µsi,t=νsi,t−νBi,tis the excess value of S-type financing above risk free return Rt+1.

Rewrite equation 3.41:

ViB,t=Et

P

τ=1(1−σB)στB−1Λt,t+τNBi,t+τ

in recursive form (shown in subsection B.1.7)

ViB,t=EtΛt,t+1

(1−σB)NBi,t+1+σBViB,t+1

(B.68)

whereNBi,t+1 is defined as in the income statement equation3.40.

Plug equationB.67shifted att+1into equationB.68to get:

ViB,t=EtΛt,t+1Ωi,t+1NBi,t+1 (B.69)

where,

Ωi,t+1= (1−σB) +σB

is the shadow value of a unit of net worth and can be re-written making use of equation (B.65) (when IC binds):

Ωi,t+1= (1−σB) +σBΘBφBi,t+1 (B.70) or equivalently : ViB,t=EtΛt,t+1 h (1−σB) +σB (1−κ)µLi,t+1φiB,t+1+κµsi,t+1φBi,t+1+νBi,t+1iNBi,t+1 Plug equation3.40: NB i,t+1 = (RLt+1−Rt+1)Li,t+ (Rst+1−Rt+1)QtSi,t+ Rt+1NBi,t into equationB.69above yields:

ViB,t=EtΛt,t+1Ωi,t+1 h RLt+1−Rt+1 Li,t+ Rst+1−Rt+1 QtSi,t+Rt+1NBi,t i (B.71)

Finally, plugging Equation B.60; (VB

i,t=µLi,tLi,t+µsi,tQtSi,t+νiB,tNBi,t)

into equation (B.71) leads to three expressions forµL

i,t,µsi,tand νBi,t: µLi,t= (νLi,t−νBi,t) =EtΛt,t+1Ωi,t+1 RLt+1−Rt+1 (B.72) µsi,t= (νsi,t−νBi,t) =EtΛt,t+1Ωi,t+1 Rst+1−Rt+1 (B.73) νBi,t=EtΛt,t+1Ωi,t+1Rt+1 (B.74)

EquationsB.65and B.72, B.73, B.74 complete the banker’s solution and de-

termineφBi,t and µLi,t,µsi,t, νBi,tas a function of ΘB, RBt+1−Rt+1, Rst+1−Rt+1 and Rt+1, which do not depend on bank specific factors. They are either exogenous

to banks or depend on economy wide variables. Therefore, they are common across all banks.

Since all banks chose the same leverage ratio and observe the same excess returns on their assets φBt and µLt, µst, νBt, the bank balance sheet and leverage can be aggregated across banks.

NBt +Bt =ABt =Lt+QtSt (B.75) φBt = At NBt = QtKt−NEt NBt (B. 76)

where NEt is firms’ net worth and QtKt total project cost. Aggregate bank net worth NBt evolves as the sum of:

- net worth of old banks surviving from last period,NBo,t+1 =σBNBt+1,

- and the net worth of new onesNBnew,t+1=ξBABtRBt+1, since on aggregate new banks receive a transfer of ξB

1−σB from absconding ones

4

.

Aggregate net worth of banks is:

NBt+1 =NBnew,t+1+NBo,t+1

whereσBis the probability of the bank not absconding (surviving) next period. Evolution of net worth of banks not absconding at time ’t+1’ is obtained using equationB.88:

NBo,t+1=σB RLt+1Lt+Rst+1QtSt−Rt+1Bt

In addition a transfer ξb

1−σb of those 1−σb absconding transfer some net worth to new banks:

4

NBnew,t+1=ξBRBt+1ABt

Then aggregate net worth is:

NBt+1 =σB

RLt+1Lt+Rts+1QtSt−Rt+1Bt

+ξBRBt+1ABt (B.77)

Intuitively, aggregate consumption of exiting banks is5

:

ΠBt+1 = (1−σB)(RBt+1ABt −Rt+1Bt) −ξBRtB+1ABt (B.78)

For the sake of reference, the average return on securities Rst+1 is defined as: RSt+1QtSt =EtRkt+1QtKt 1−Γψ t+1 Xeqt (B.79)

For the sake of reference I define the average return RBt+1 on total bank assetsABt as: RBt+1=RLt+1Lt ABt +R s t+1 QtSt ABt (B. 80) 5 Since 1ξσ

B portion of net worth is transferred by a fraction1−σB of exiting bankers to new

ones, then1−1ξσ