EVALUACION FORMATIVA Y DE PROCESOS
17. Diseño de un plan o estrategias.
j̸=i
∑ s
k j(y) = 1 − ∑ y
l−s
k
i
(y)
. (17)jai lEN
Combining (16) and (17), we obtain
∑x
i+ s
i i(x)
1 −
jaiy
j− ∑ [p
k(1 − ∑y
l− s
ki(y))] = y
i+∑p
ks
ki(y)
. kEN lEN kEN Hence:(
)
(
])
∑
∑ [
V
(x
i+ s
i i(x)) = u
i(x
i+ s
ii(x))
iy
i+
p
ks
k i(y)
i(1 −
i) y
i+
ip
ky
i+ s
k i(x)
i kEN kEN∑
(1 −
i) u
i(y
i) +
i kEN(
)
p
ku
iy
i+ s
k i(x) = V
i(y)
.This shows that proposing
∆
n_1 is not a profitable deviation for playeri
, and completes the proof of Claim 3.Combining Claims 1-3, we obtain Theorem 4(i).
Part (ii)
Denote our game with an evolving default by e, and the game with a constant default of
x
°= (0, . . . , 0)
by c. To prove the second part of the theorem, we first show that, for every SMPE of e, we can construct a stationary strategy profile c in c that generates the same payoffs as in e. We then show that c is a stationary SPE of c. Uniqueness of SMPE payoffs in e then follows from uniqueness of stationary SPE in c (Observation 2).Let
= (
i)
iEN be an SMPE of e, and let i(x)
be the proposal made by playeri
when the ongoing default is somex
outside ∆n_1. (Recall that proposers do notrandomize at such a default: cf. the paragraph immediately after the proof of Theorem 3.) Hence, player
i
's expected payoff as evaluated after rejection of a proposal in the first period is given by:U
(x
°) = (1 −
i) u
i(x
°) +
i∑ p
( (x
°))
ju
i j i jEN(recall that, by Theorem 3, must be no-delay).
Now define the stationary strategy profile c
= (
ci)
iEN in game c as follows. At the proposal stage of every periodt
, each player makes proposal i Moreover, by equation (12),voting stage of each period, player
i
accepts the proposal just made, sayy
, if and only ifui(y) > V
(x°)
.i
As is no-delay, proposal i
(x
°)
,i E N
, must be accepted with probability 1 at defaultx°
inF
e. By sequential rationality and unanimity rule, this implies that IT (
i (x°))
=
uj
j ( x°) ) > V ( x°)
i s- ( xj °)
f o r a l lj E N
, w h i c h i n t u r n i m p l i e s t h a t p r o p o s a li
also accepted with probability 1 in any period of
F
c. Two immediate consequences of this observation are that: (i) playeri
's expected payoff as evaluated after rejection of a proposalin the first period of
F
c is fromV
i (x
°)
; and (ii) playeri E N
has no profitable deviation the voting behavior prescribed by ci.To complete the proof of the result, therefore, it remains to show that no player
i E N
can profitably deviate from c in a proposal stage of
F
c. Consider the proposal of an arbitrary playeri
when the default isx
°. As is an SMPE ofF
e, playeri
cannot profitably deviate by (successfully) proposing a policyy E X\
i (x
°)
or by making an unsuccessful proposal at defaultx
°. Hence,where the second inequality follows from Lemma 2(ii). Now consider a deviation from
i
(x°)
inF
c. Ifi
proposed some policyy
then her expected payoff would beui(y)
if her proposal were successful, andV
thati (x°)
otherwise. Hence, the inequality above impli esi
cannot improve upon proposingi (x°)
and, therefore, cannot profitably deviate from ci inproposal stages.
The theorem then follows from Observation 2, which says that Baron and Ferejohn's (1989) model has unique stationary SPE payoffs when
q = n
.T h eo rem 5 . S up p ose that
q = n.
(i) If
i ≠
j
, for some i, j E N, then every DE is ex post Pareto inefficient.(ii)Any (Pareto efficient) policy sequence that allocates the entire pie to the same player in every period can be supported by an SPE.
P r o o f :
V
°))
=
ui
i (x°))
>max
V
( x ° ), (1 −
i) ui(y) +
i
E i
j
EN
(
)
pjui j i (y)
> ui(y)
( i ) E x p o s t P a r e t o i n e f f i c i e n c y o f D E s
We begin with a lemma which shows that, in a DE, the pie is never entirely allocated to a single player; so that transfers among players are always feasible. This will then allow us to prove that any realization of a DE policy sequence can be Pareto-improved using transfers across periods.
Lemma 5. Let
q = n
. If{
˜x
t}
is the stochastic sequence of policies on some DE path then, for every realization{x
t}
of{
˜x
t}
, we havex
ti(0, 1)
for all and allN
.Proof: Let
{x
t}
be an arbitrary realization of the sequence{
˜x
t}
engendered by some DE . Suppose that, contrary to the statement above,x
j= 0
for some and someN
. Theorem 3 then implies that, in the first period, playerj
accepted a proposalx
such thatx
j= x
tj= 0
for allN
. Playerj
's payoff under is thereforeu
j(0) = 0
.To prove the lemma, we will now show that
j
could profitably deviate — i.e. obtain a payoff strictly greater thanu
j(0)
— by rejectingx
. To this end, suppose thatx
is rejectedin period 1 and that
j
is selected to propose at the start of period 2. Defineh
0 xo asthe implementation history that would be induced by a rejection of