• No se han encontrado resultados

EL ORDEN PÚBLICO EN LA CRISIS DEL PARADIGMA NORMATIVO DEL DIPr

In document UNIVERSIDAD COMPLUTENSE DE MADRID (página 84-95)

ORDEN PÚBLICO Y NORMAS MATERIALES IMPERATIVAS EN EL MARCO ARBITRAL

II. Orden público y normas materiales imperativas en el DIPr. Admisibilidad en las distintas fases del proceso arbitral

3. EL ORDEN PÚBLICO EN LA CRISIS DEL PARADIGMA NORMATIVO DEL DIPr

The basic flexural design value, multiplied by all appli-cable adjustment factors except CL, is

Fb¼ FbCMCFCD

The beam stability factor is given by NDS Sec. 3.3.3 as

CL¼1:0 þ F

The allowable flexural design value for the load applied to the narrow face is

F0b1¼ FbCMCFCDCL The actual edgewise bending stress is

fb1¼W L

The critical buckling design value in the plane of bend-ing for load applied to the narrow face is

FcE1¼0:822E0min

The moment magnification factor for axial compression and flexure with load applied to the narrow face is

Cm3¼ 1:0  fc

The interaction equation for bending load applied to the narrow face of the member and concentric axial com-pression load is given in NDS Sec. 3.9.2 as

fc F0c

 2

þ fb1

F0b1Cm3 1:0 The left-hand side of the expression is

404 lbf

< 1:0 ½satisfactory

The post is adequate.

4. DESIGN FOR TENSION Nomenclature

A area of cross section

CD load duration factor

CF size factor for sawn lumber

Ci incising factor

Cm wet service factor

Ct temperature factor

E reference modulus of elasticity lbf/in2 E0 allowable modulus of elasticity lbf/in2 ft actual tension stress parallel to grain lbf/in2

F ratio of FbEto Fb

Fb reference bending design value multiplied by all applicable

adjustment factors except CL lbf/in2 Fb reference bending design value

multiplied by all applicable

adjustment factors except CV lbf/in2 FbE critical buckling design value for

bending members

Ft reference tension design value parallel

to grain lbf/in2

F0t allowable tension design value parallel

to grain lbf/in2

le effective length of compression member ft lu laterally unsupported length of beam ft RB slenderness ratio of bending member

T tensile force on member lbf

D E S I G N O F W O O D S T R U C T U R E S

5-15

Wood

Axial Tension

The reference design values for tension parallel to the grain are tabulated in the NDS Supplements. Allowable design values are obtained by multiplying basic values by the applicable adjustment factors. As specified in NDS Sec. 3.8.2, tension perpendicular to the grain is to be avoided.

Example 5.10

The select structural 2 8 Douglas Fir-Larch bottom chord of a truss is axially loaded in tension as shown in the illustration. The governing load combination con-sists of dead load plus live load plus snow load, and the moisture content exceeds 19%. The self-weight of the chord may be neglected. At the end connections, the net area is Anet= 9.3 in2. Determine whether the member is adequate.

(not to scale) 4 ft

T  8000 lbf T 4 ft

d2 1.5 in

d1 7.25 in

Solution

The reference design value for tension, tabulated in NDS Supp. Table 4A, is

Ft ¼ 1000 lbf in2

The size factor for tensile load is obtained from NDS Supp. Table 4A as

CF ¼ 1:20

The load duration factor is obtained from NDS Table 2.3.2 as

CD¼ 1:5 ½snow load

The wet service factor for tensile load is obtained from NDS Supp. Table 4A as

CM ¼ 1:00

The allowable tension design value parallel to grain is F0t¼ FtCMCFCD

¼ 1000 lbf in2

 

ð1:0Þð1:2Þð1:15Þ

¼ 1380 lbf=in2

The actual tension stress on the net area of the chord is ft;net¼ T

Anet

¼8000 lbf 9:3 in2

¼ 860 lbf in2

< F0t ½satisfactory

The member is adequate.

Combined Axial Tension and Flexure

Members subjected to combined tension and flexural stresses caused by axial and transverse loading must satisfy the two expressions given in NDS Sec. 3.9.1 as

ft F0tþfb

Fb  1:0 ½NDS 3:9-1

fb ft

Fb  1:0 ½NDS 3:9-2

Example 5.11

The select structural 2 8 Douglas Fir-Larch bottom chord of a truss is loaded as shown in the illustration.

The governing load combination consists of dead load plus live load plus snow load, and the moisture content exceeds 19%. The chord is laterally braced at midlength about the weak axis, and the self-weight of the chord and bracing members may be neglected. Determine whether the member is adequate.

(not to scale) d2 4 ft

1.5 in

d1 7.25 in

W 

400 lbf 4 ft

T

T  8000 lbf

Solution

The relevant details from Ex. 5.10 follow. The allowable tension design value parallel to the grain is

F0t¼ 1380 lbf in2

Wood

The actual tension stress on the gross area of the

The reference design values for bending and the modu-lus of elasticity for stability calculations, tabulated in NDS Supp. Table 4A, are

Fb¼ 1500 lbf in2 Emin¼ 0:69  106 lbf

in2

The applicable adjustment factors for the modulus of elasticity are the following. The wet service factor is

CM ¼ 0:9 ½NDS Supp: Table 4A

The temperature factor is

Ct ¼ 1:0 ½NDS Table 2:3:3

The incising factor is

Ci¼ 1:0 ½NDS Table 4:3:8

The adjusted modulus of elasticity for stability calcula-tions is

For a concentrated load with lateral restraint, both at midspan, the effective length is obtained from Fig. 5.1 as

le¼ 1:11lu

¼ ð1:11Þð4 ftÞ 12 in ft

 

¼ 53:28 in

The slenderness ratio is given by NDS Sec. 3.3.3 as

RB¼ ð53:28 inÞð7:25 inÞ

ð1:5 inÞ2 s

¼ 13:10

< 50 ½satisfies criteria of NDS Sec: 3:3:3

The critical buckling design value is FbE¼1:20E0min

The applicable adjustment factors for bending are the following. The wet service factor is

CM ¼ 0:85 ½NDS Supp: Table 4A

The size factor is

CF ¼ 1:2 ½NDS Supp: Table 4A

The load duration factor is

CD¼ 1:15 ½NDS Table 2:3:2

The reference flexural design value, multiplied by all applicable adjustment factors except CL, is

Fb¼ FbCMCFCD

The beam stability factor is given by NDS Sec. 3.3.3 as CL¼1:0 þ F

The reference flexural design value, multiplied by all applicable adjustment factors except CV, is

Fb ¼ FbCMCFCDCL

...

The actual edgewise bending stress is fb1¼W L

4S

¼ð400 lbfÞð8 ftÞ 12 in ft

 

ð4Þð13:14 in3Þ

¼ 731 lbf=in2

Substituting in the two expressions given in NDS Sec. 3.9.1 gives

ft F0tþfb1

Fb¼ 735 lbf in2 1380 lbf

in2

þ 731 lbf in2 1760 lbf

in2

¼ 0:533 þ 0:415

¼ 0:948

< 1:0 ½satisfactory

fb1 ft

Fb ¼731 lbf

in2 735 lbf in2 1707 lbf

in2

¼ 0:002

< 1:0 ½satisfactory

The chord is adequate.

5. DESIGN FOR SHEAR

In document UNIVERSIDAD COMPLUTENSE DE MADRID (página 84-95)