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Paso a paso: Cómo solicitar una decisión de cobertura

In document Evidencia de Cobertura: (página 197-200)

ApodeiknÔetai apì ta axi¸mata twn pragmatik¸n arijm¸n ìti to sÔnolo R èqei thn epiplèon idiìthta

16. Eˆn x < y tìte upˆrqei pragmatikìc arijmìc z tètoioc ¸ste x < z kai z < y.

Eˆn x < z kai z < y grˆfoume x < z < y. H idiìthta 16 ekfrˆzei thn puknìthta twn pragmatik¸n arijm¸n. To apotèlesma autì odhgeÐ sto na jewroÔme touc pragmatikoÔc arijmoÔc san ta shmeÐa mÐac eujeÐac. Eˆn jewr soume ta sÔmbola −∞ kai +∞, antÐstoiqa, meÐon ˆpeiro (minus infinity) kai sÔn ˆpeiro (plus infinity), tètoia ¸ste −∞ < x < +∞, gia kˆje pragmatikì arijmì x, mporoÔme na grˆfoume R = (−∞, +∞).

Eˆn x kai y eÐnai pragmatikoÐ arijmoÐ me x < y, tìte me ta diast mata (x, y), [x, y), (x, y], [x, y]

sumbolÐzoume anÐstoiqa to sÔnolo twn pragmatik¸n arijm¸n z pou ikanopoioÔn tic sqèseic

x < z < y, x ≤ z < y, x < z ≤ y, x ≤ z ≤ y.

'Omoia eˆn x eÐnai ènac pragmatikìc arijmìc me ta hmiˆpeira diast mata (−∞, x), (−∞, x], (x, +∞), [x, +∞)

sumbolÐzoume anÐstoiqa to sÔnolo twn pragmatik¸n arijm¸n z pou ikanopoioÔn tic sqèseic

z < x, ≤ x, z > x, z ≥ x.

Parˆdeigma 5.1. Eˆn S = (1, 2), tìte to 2 kaj¸c kai kˆje pragmatikìc arijmìc x ≥ 2 eÐnai èna ˆnw frˆgma tou S. 'Omoia eˆn S = (1, 2], tìte kˆje x ≥ 2 eÐnai èna ˆnw frˆgma tou

S. ParathroÔme ìti eˆn S = (1, 2), tìte sup S = 2 kai sup S /∈ S, en¸ an S = (1, 2], tìte sup S = 2 kai sup S ∈ S, dhlad  to elˆqisto ˆnw frˆgma sunìlou mporeÐ na an kei   na mhn an kei sto sÔnolo. ParathroÔme ìti to sup(1, +∞) den upˆrqei (giati?).

A, τότε

'Ena sÔnolo S ⊂ R lègetai kˆtw fragmèno (bounded below) eˆn upˆrqei pragmatikìc arijmìc x tètoioc ¸ste gia kˆje y ∈ S na isqÔei y ≥ x. To x lègetai èna kˆtw frˆgma (lower bound) tou S. Eˆn s eÐnai ènac pragmatikìc arijmìc tètoioc ¸ste s ≥ x gia kˆje kˆtw frˆgma x tou S, tìte o s lègetai mègisto kˆtw frˆgma (greatest lower bound)   infimum tou S kai sumbolÐzetai me inf S.

SÔmfwna me ton orismì tou megÐstou kˆtw frˆgmatoc blèpoume ìti inf(1, 2) = 1, inf[1, 2) = 1, en¸ to inf(−∞, 2) den upˆrqei. MporeÐ na apodeiqjeÐ h akìloujh prìtash. Gia thn apìdeixh blèpe tic ask seic.

Prìtash 5.1. Kˆje kˆtw fragmèno sÔnolo pragmatik¸n arijm¸n èqei elˆqisto kˆtw frˆg- ma.

Anafèroume, gia plhrìthta, ta parakˆtw apotelèsmata. H Prìtash 5.2 eÐnai apìrrroia tou axi¸matoc 15, en¸ h Prìtash 5.3 eÐnai sunèpeia twn Protˆsewn 5.1 kai 5.2. Gia thn apìdeixh parapèmpoume sto sÔggramma [2].

Prìtash 5.2 (AxÐwma tou Arqim dh). Eˆn x kai y eÐnai jetikoÐ pragmatikoÐ arijmoÐ, tìte upˆrqei fusikìc arijmìc n tètoioc ¸ste y < nx.

Prìtash 5.3. Eˆn x kai y eÐnai pragmatikoÐ arijmoÐ me x < y, tìte upˆrqei rhtìc arijmìc

r tètoioc ¸ste x < r < y.

KleÐnontac thn parˆgrafo anafèroume ìti kˆpoioc xekin¸ntac me thn paradoq  ìti upˆrqei èna sÔnolo pou ikanopoieÐ ta axi¸mata 1 15 mporeÐ na apodeÐxei th monadikìthta tou, me thn ènnoia tou isomorfismoÔ, kai sth sunèqeia na kataskeuˆsei pr¸ta touc fusikoÔc arijmoÔc kai metˆ touc akeraÐouc kai touc rhtoÔc. Gia th prosèggish aut  parapèmpoume sta suggrˆmmata [1] kai [8].

Ask seic

5.2.1 [8] Na apodeiqjoÔn oi parakˆtw idiìthtec thc ˆlgebrac twn pragmatik¸n arijm¸n: (aþ) Eˆn x + y = x, tìte y = 0.

(bþ) 0x = 0. Upìdeixh: 0 = 0 + 0. (gþ) −0 = 0.

(dþ) −(−x) = x. Upìdeixh: O −(−x) eÐnai o antÐjetoc tou −x. (eþ) x(−y) = −(xy) = (−x)y.

(þ) (−1)x = −x.

(zþ) x(y − z) = xy − xz.

(hþ) −(x + y) = −x − y, −(x − y) = −x + y. (jþ) Eˆn x 6= 0 kai xy = 1, tìte y = 1.

(iþ) Eˆn x 6= 0, tìte x/x = 1. (iaþ) x/1 = x.

(ibþ) Eˆn x 6= 0 kai y 6= 0, tìte xy 6= 0.

(igþ) (1/x)(1/y) = 1/(xy), eˆn x 6= 0 kai y 6= 0. (idþ) (w/x)(y/z) = (wy)/(xz), eˆn x 6= 0 kai z 6= 0.

(ieþ) (w/x) + (y/z) = (wz + yx)/(xz), eˆn x 6= 0 kai z 6= 0. (iþ) Eˆn x 6= 0, tìte 1/x 6= 0.

(izþ) Eˆn x 6= 0, tìte (x−1)−1 = x.

(ihþ) 1/(x/y) = y/x, eˆn x 6= 0 kai y 6= 0.

(ijþ) (w/x)/(y/z) = (wz)/(xy), eˆn x 6= 0, y 6= 0 kai z 6= 0. (kþ) (xy)/z = x(y/z), eˆn z 6= 0.

(kaþ) (−x)/y = x/(−y) = −(x/y), eˆn y 6= 0.

5.2.2 [8] Na apodeiqjoÔn oi parakˆtw idiìthtec twn anisot twn pragmatik¸n arijm¸n: (aþ) Eˆn w ≤ x kai y ≤ z, tìte w + y ≤ x + z.

(bþ) Eˆn x ≤ y kai z ≥ 0, tìte zx ≤ zy. (gþ) x ≤ 0 eˆn kai mìnon eˆn −x ≥ 0. (dþ) x ≤ y eˆn kai mìnon eˆn −x ≥ y. (eþ) Eˆn x ≤ y kai z ≤ 0, tìte zx ≥ zy. (þ) Eˆn x 6= 0, tìte x2 > 0, ìpou x2 = xx.

(zþ) −1 < 0 < 1.

(hþ) Eˆn xy > 0, tìte oi x kai y eÐnai kai oi dÔo jetikoÐ   kai oi dÔo arnhtikoÐ. (jþ) Eˆn x > 0, tìte 1/x > 0.

(iþ) Eˆn 0 < x ≤ y, tìte 1/y ≤ 1/x. (iaþ) Eˆn x < y, tìte x < (x + y)/2 < y.

5.2.3 Na brejoÔn ìloi oi pragmatikoÐ arijmoÐ gia touc opoÐouc isqÔei (aþ) (x − 1)(x − 2) > 0. (bþ) x2+ x + 1 > 2. (gþ) 1 x + x−11 > 0. (dþ) x−1 x+1 > 0.

5.2.4 Na apodeiqjoÔn oi parakˆtw idiìthtec thc apìluthc tim c: (aþ) |x| ≥ 0 kai |x| = 0, eˆn kai mìnon eˆn x = 0.

(bþ) |xy| = |x||y|. (gþ) |x| = | − x|

(dþ) |x + y| ≤ |x| + |y|. (eþ) ||x| − |y|| ≤ |x − y|.

5.2.5 Na brejoÔn ìloi oi pragmatikoÐ arijmoÐ gia touc opoÐouc isqÔei (aþ) |x − 2| > 8. (bþ) |x − 2| < 8. (gþ) |x − 1| + |x − 2| > 1. (dþ) |x − 1| + |x + 1| < 2. (eþ) |x − 1||x + 2| = 0. (þ) |x − 1||x + 2| = 3.

5.2.6 Eˆn S ⊂ R, tìte orÐzoume −S = {−x : x ∈ S}, dhlad  −[1, 2) = (−2, −1]. Na apodeiqjoÔn oi isqurismoÐ:

(aþ) 'Ena sÔnolo S ⊂ R eÐnai ˆnw fragmèno eˆn kai mìnon eˆn to −S eÐnai kˆtw frag- mèno.

(bþ) 'Ena sÔnolo S ⊂ R eÐnai kˆtw fragmèno eˆn kai mìnon eˆn to −S eÐnai ˆnw frag- mèno. Upìdeixh: −(−S) = S.

(gþ) sup S = − inf(−S) kai inf S = − sup(−S).

5.2.7 Na brejoÔn, eˆn autˆ upˆrqoun ta inf S kai sup S, ìpou (aþ) S = ½ 1 n : n ∈ N ¾ . (bþ) S = ½ (−1)n+ 1 n : n ∈ N ¾ .

5.2.8 'Estw ìti A eÐnai èna tuqaÐo sÔnolo efodiasmèno me dÔo eswterikèc prˆxeic ⊕ kai ¯ tètoiec ¸ste na ikanopoioÔntai oi idiìthtec/axi¸mata

1. x ⊕ y = y ⊕ x, gia kˆje x, y ∈ A.

2. (x ⊕ y) ⊕ z = x ⊕ (y ⊕ z), gia kˆje x, y, z ∈ A.

3. Upˆrqei stoiqeÐo 0 ∈ A, ètsi ¸ste x ⊕ 0 = x, gia kˆje x ∈ A. 4. Gia kˆje x ∈ A upˆrqei stoiqeÐo x0 ∈ A, ètsi ¸ste x ⊕ x0 = 0.

5. (x ¯ y) ¯ z = x ¯ (y ¯ z), gia kˆje x, y, z ∈ A. 6. x ¯ (y ⊕ z) = x ¯ y ⊕ x ¯ z kai

H triˆda (A, ⊕, ¯) lègetai daktÔlioc (ring). Na deiqjeÐ ìti to sÔnolo twn akeraÐwn efodiasmèno me tic prˆxeic thc prìsjeshc kai tou pollaplasiasmoÔ, (Z, +, ·), apoteleÐ daktÔlio.

Kefˆlaio 6

Oi migadikoÐ arijmoÐ

6.1 To s¸ma twn migadik¸n arijm¸n

Eˆn x ∈ R tìte x2 ≥ 0, opìte h exÐswsh x2 + 1 = 0 den èqei lÔsh stouc pragmatikoÔc

arijmoÔc. Diatup¸netai loipìn to er¸thma katˆ pìson upˆrqei èna sÔsthma arijm¸n pou katˆ kˆpoia ènnoia epekteÐnei touc pragmatikoÔc arijmoÔc kai eÐnai tètoio ¸ste h exÐswsh

x2+ 1 = 0 na èqei lÔsh. ApodeiknÔetai ìti èna tètoio sÔsthma upˆrqei.

Kataskeu . Sto sÔnolo R × R orÐzoume touc nìmouc thc prìsjeshc kai pollaplasiasmoÔ me tic sqèseic (x1, y1) + (x2, y2) = (x1+ x2, y1+ y2) (6.1) (x1, y1)(x2, y2) = (x1x2− y1y2, x1y2+ x2y1). (6.2) ParathroÔme ìti (x1, y1) + (0, 0) = (x1, y1) (6.3) (x1, y1) + (−x1, −y1) = (0, 0) (6.4) (x1, y1)(1, 0) = (x1, y1), (6.5)

dhlad  to (0, 0) eÐnai to oudètero stoiqeÐo thc prìsjeshc, to (−x1, −y1) eÐnai to antÐjeto

tou (x1, y1), en¸ to (1, 0) eÐnai oudètero stoiqeÐo tou pollaplasiasmoÔ. Eˆn (x, y) 6= (0, 0)

kai (a, b) eÐnai to antÐstrofo stoiqeÐo tou (x, y), eˆn autì upˆrqei, tìte ja prèpei (x, y)(a, b) = (xa − yb, xb + ya) = (1, 0).

UpenjumÐzoume ìti (x1, y1) = (x2, y2) eˆn kai mìnon eˆn x1 = x2 kai y1 = y2, tìte apì thn

parapˆnw isìthta prokÔptoun oi sqèseic xa − yb = 1 kai xb + ya = 0. LÔnontac to sÔsthma brÐskoume a = x x2+ y2, b = −y x2+ y2. 53

Oi arijmoÐ a kai b upˆrqoun, kajìson x2+ y2 > 0 opoted pote (x, y) 6= (0, 0). Epomènwc to

antÐstrofo tou (x, y) to opoÐo sumbolÐzoume me (x, y)−1 eÐnai to

(6.6) (x, y)−1 = µ x x2 + y2, −y x2+ y2 ¶ .

EÐnai plèon eÔkolo na apodeiqjeÐ ìti to R×R efodiasmèno me touc nìmouc (6.1) kai (6.2) eÐnai s¸ma, blèpe Parat rhsh 5.2. OrÐzoume to s¸ma twn migadik¸n (complex) arijm¸n C na eÐnai to sÔnolo twn shmeÐwn z = (x, y) ∈ R × R efodiasmèno me touc nìmouc (6.1) kai (6.2).

Apìrroia twn prˆxewn (6.1) kai (6.2) eÐnai ìti (x, y) = (x, 0)+(0, y) kai (0, 1)(y, 0) = (0, y), ètsi kˆje migadikìc arijmìc mporeÐ na grafeÐ sth morf 

(6.7) (x, y) = (x, 0) + (0, 1)(y, 0).

Eˆn x eÐnai ènac pragmatikìc arijmìc, shmeÐo thc eujeÐac, mporeÐ na tautopoihjeÐ me to (x, 0), shmeÐo tou epipèdou. Epiplèon parathroÔme ìti

(x1, 0) + (x2, 0) = (x1 + x2, 0), (x1, 0)(x2, 0) = (x1x2, 0),

dhlad  to s¸ma twn migadik¸n arijm¸n epekteÐnei katˆ fusiologikì trìpo to s¸ma twn prag- matik¸n arijm¸n, kai upì to prÐsma thc tautopoÐhshc x ≡ (x, 0) mporoÔme na jewroÔme ìti R ⊂ C. Jètontac i = (0, 1)i = (0, 1)i = (0, 1) sÔmfwna me thn parapˆnw tautopoÐhsh h (6.7) grˆfetai

(6.8) (x, y) = x + iy.

O migadikìc arijmìc i lègetai fantastik  monˆda (imaginary unit). Eˆn z = (x, y) eÐnai ènac migadikìc arijmìc apì ed¸ kai sto ex c ja grˆfoume z = x + iy. Eˆn z1 = x1+ iy1 kai

z2 = x2 + iy2 eÐnai migadikoÐ arijmoÐ tìte to ˆjroisma z1 + z2 kai to ginìmeno z1z2 dÐnontai,

mèsw twn (6.1) kai (6.2), apì tic sqèseic

z1+ z2 = (x1+ iy1) + (x2+ iy2) = (x1 + x2) + i(y1+ y2)

(6.9)

z1z2 = (x1+ iy1)(x2+ iy2) = (x1x2− y1y2) + i(x1y2+ x2y1).

(6.10)

'Estw o migadikìc arijmìc z = x + iy, tìte apì ton orismì tou C èqoume ìti x ∈ R kai y ∈ R. O x lègetai pragmatikì mèroc (real part) tou z kai grˆfoume x = Re z, kai o y lègetai fantastikì mèroc (imaginary part) tou z kai grˆfoume y = Im z. 'Et- si eˆn z ∈ R tìte Re z = z kai Im z = 0, en¸ eˆn z = iy, me y ∈ R, tìte Re z = 0 kai Im z = y.

•Oi migadikoÐ arijmoÐ z1 = x1+ iy1 kai z2 = x2+ iy2 eÐnai Ðsoi kai grˆfoume z1 = z2, eˆn kai

mìnon eˆn x1 = x2 kai y1 = y2, isodÔnama Re z1 = Re z2 kai Im z1 = Im z2.

'Opwc kai stouc pragmatikoÔc arijmoÔc, epagwgikˆ orÐzoume z1 = z, z2 = zz, z3 = z2z,

zn+1 = znz gia kˆje fusikì arijmì n. ParathroÔme ìti i2 = (0, 1)(0, 1) = (−1, 0)   i2 = −1.

kai (−i)2+ 1 = 0.

DeÐxame loipìn ìti to s¸ma twn migadik¸n arijm¸n C apoteleÐ mÐa fusiologik  epèktash twn pragmatik¸n arijm¸n, ìpou sto sÔsthma autì h exÐswsh z2+ 1 = 0 èqei lÔsh.

KleÐnoume aut  th parˆgrafo me mÐa parat rhsh. Den upˆrqei sto C mÐa diˆtaxh pou na

eÐnai sumbibast  me tic prˆxeic thc prìsjeshc kai tou pollaplasiasmoÔ kai na epekteÐnei th gnwst  diˆtaxh tou R. An upojèsoume ìti mÐa tètoia upˆrqei kai an th sumbolÐsoume me ≤, tìte ja prèpei na isqÔei 0 ≤ 1, epeid  autì isqÔei kai stouc pragmatikoÔc arijmoÔc. EpÐshc èna apì ta dÔo eÐnai alhjèc: eÐte 0 ≤ i, eÐte 0 ≥ i. Eˆn 0 ≤ i, tìte ja eÐnai 0i ≤ i2,  

isodÔnama 0 ≤ −1,   isodÔnama 0 ≥ 1 pou eÐnai ˆtopo. 'Omoia eˆn 0 ≥ i tìte ja eÐqame 0i ≤ i2,   isodÔnama 0 ≤ −1,   isodÔnama 0 ≥ 1 pou eÐnai ˆtopo.

6.2 'Algebra twn migadik¸n arijm¸n

To sÔnolo twn migadik¸n arijm¸n efodiasmèno me tic prˆxeic thc prìsjeshc kai tou pol- laplasiasmoÔ ìpwc autèc orÐzontai stic sqèseic (6.1) kai (6.2)   (6.9) kai (6.10) eÐnai s¸ma dhlad  isqÔoun oi nìmoi

1. z1+ z2 = z2+ z1, gia kˆje z1, z2 sto C.

2. (z1+ z2) + z3 = z1+ (z2+ z3), gia kˆje z1, z2, z3 sto C.

3. Upˆrqei o monadikìc migadikìc arijmìc 0 = (0, 0) = 0 + i0, ètsi ¸ste z + 0 = z, gia kˆje z ∈ C.

4. Gia kˆje migadikì arijmì z upˆrqei monadikìc migadikìc arijmìc −z, ètsi ¸ste z + (−z) = 0.

5. z1z2 = z2z1, gia kˆje z1, z2 sto C.

6. (z1z2)z3 = z1(z2z3), gia kˆje z1, z2, z3 sto C.

7. Upˆrqei o monadikìc migadikìc arijmìc 1 = (1, 0) = 1 + i0, ètsi ¸ste z · 1 = z, gia kˆje

z ∈ C.

8. Gia kˆje migadikì arijmì z 6= 0 upˆrqei monadikìc migadikìc arijmìc z−1 ètsi ¸ste z · z−1 = 1.

9. z1(z2+ z3) = z1z2+ z1z3, gia kˆje z1, z2, z3 sto C.

Parat rhsh 6.1. Ac jewr soume ton migadikì arijmì z = x+iy. Apì ton antimetajetikì nìmo (nìmoc 5) èqoume iy = yi opìte o mporoÔme na grˆfoume

Epeid  i(−y) = (−y)i = (−1)yi = (−1)iy kai i(−y) + iy = i(−y + y) = i0 = 0, sunduˆzontac ta dÔo apotelèsmata sumperaÐnoume ìti

i(−y) = (−1)iy = −iy.

'Etsi apì tic (6.8), (6.4) kai (6.6) èpetai ìti oi −z kai z−1, efìson z 6= 0, dÐnontai antÐstoiqa

apì tic sqèseic

−z = −x + i(−y) = −x − iy (6.11) z−1 = x x2+ y2 + i −y x2+ y2 = x x2+ y2 − i y x2+ y2 (6.12)

Parat rhsh 6.2. 'Estw z1 = x1+ iy1 kai z2 = x2+ iy2, tìte kˆnontac qr sh tou nìmou

9 (epimeristik  idiìthta tou pollaplasiasmoÔ wc proc thn prìsjesh) upologÐzoume

z1z2 = (x1+ iy1)(x2+ iy2) = x1(x2+ iy2) + iy1(x2 + iy2) (nìmoc 9) = x1x2+ x1iy2+ iy1x2+ iy1iy2 (nìmoc 9) = x1x2+ ix1y2+ iy1x2+ i2y1y2 (nìmoc 5) = x1x2+ ix1y2+ iy1x2− y1y2 (i2 = −1) = (x1x2− y1y2) + i(x1y2+ x2y1) (nìmoc 9)

pou eÐnai h (6.10). O pollaplasiasmìc dhlad , migadik¸n arijm¸n mporeÐ na ektelesjeÐ me qr sh thc oikeÐac, apì touc pragmatikoÔc arijmoÔc, epimeristik c idiìthtac.

Parat rhsh 6.3. Eˆn z1 = x1+ iy1 kai z2 = x2+ iy2, eÐnai migadikoÐ arijmoÐ, ìpwc stouc

pragmatikoÔc arijmoÔc, h afaÐresh kai to phlÐko orÐzontai, antÐstoiqa, me tic sqèseic

z1− z2 = z1+ (−z2) = (x1 + iy1) + (−x2+ i(−y2)) = (x1− x2) + i(y1− y2) (6.13) z1 z2 = z1z2−1 = (x1+ iy1) µ x2 x2 2+ y22 + i −y2 x2 2+ y22 ¶ = x1x2 + y1y2 x2 2+ y22 + i−x1y2+ x2y1 x2 2+ y22 . (6.14)

ParathroÔme ìti gia z1 = 1 = 1 + i0 kai z2 = z = x + iy apì thn teleutaÐa sqèsh èpetai

(6.15) 1z = x

x2+ y2 + i

−y x2 + y2 = z

−1.

Epakìloujo thc teleutaÐac aut c sqèshc eÐnai h

(6.16) zz1 2 = z1 1 z2 .

Ask seic

(aþ) (−3 + i)(1 − i2) (bþ) 9 + i21 .

(gþ) (√7 + i√3)(√7 − i√3). (dþ) 3 + i57 − i.

(eþ) (3 + i2)2.

6.2.2 Na deiqjeÐ ìti oi arijmoÐ 1 ± i ikanopoioÔn thn exÐswsh z2− 2z + 2 = 0.

6.2.3 Eˆn z ∈ C kai w ∈ C na deiqjeÐ ìti: (i) z2 + 1 = (z + i)(z − i) kai (ii) z2 + w2 =

(z + iw)(z − iw).

6.2.4 Eˆn x kai y eÐnai pragmatikoÐ arijmoÐ na brejoÔn oi timèc touc se kˆje mÐa apì tic efrˆseic:

(aþ) 5x + i6 = −8 + i2y

(bþ) i(2x − 4y) = 4x + 2 + i3y. (gþ) (3x + i)2 = 8 + iy.

6.2.5 Na brejoÔn oi lÔseic thc exÐswshc z2+z +1 = 0. Upìdeixh: Jètoume z = x+iy sthn

exÐswsh kai afoÔ kˆnoume prˆxeic koitˆzoume xeqwristˆ to pragmatikì kai fantastikì mèroc.

6.2.6 Na deiqjeÐ ìti o arijmìc a eÐnai pragmatikìc eˆn kai mìnon eˆn Re a = a. 6.2.7 Eˆn z ∈ C na deiqjeÐ ìti: (i) Re(iz) = − Im z kai (ii) Im(iz) = Re z.

6.2.8 Na upologisjoÔn oi dunˆmeic in, gia kˆje fusikì arijmì n. Upìdeixh: i1 = i, i2 = −1,

i3 = i2i = −i.

6.2.9 Na deiqjeÐ ìti (1 + z)2 = 1 + 2z + z2.

6.2.10 Me qr sh thc majhmatik c epagwg c na deiqjeÐ ìti (1 + z)n= 1 + µ n 1 ¶ z + µ n 2 ¶ z2+ · · · + µ n kzk+ · · · + µ n n − 1zn−1+ zn.

6.2.11 Eˆn z, w, v kai u eÐnai migadikoÐ arijmoÐ na apodeiqjoÔn oi isìthtec: (aþ) zw1 = 1 z 1 w. (bþ) z + wv = z v + w v, v 6= 0. (gþ) zwvu = z v w u, v 6= 0 kai u 6= 0. (dþ) zwzv = w v, z 6= 0 kai v 6= 0.

In document Evidencia de Cobertura: (página 197-200)

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