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19,Sí 21,05X Fuente; Cuadro nS 7 del Tomo II

=

. / .

. / . V

CalculatethepercentvoltagedroptothesecondaryoftransformerT3�

Usethesecondaryvoltagereferredtothehighside:

 V

V V

drop= 1 V T3 = =

1

100 2400 2326 11

2400 . 100 3 0789. %



2.4.2.2  Load Allocation Based upon Transformer Ratings

Whenonlytheratingsofthedistributiontransformersareknown,thefeeder

canbeallocatedbaseduponthemetereddemandandthetransformerkVA

ratings� This method was discussed in Section 2�3�3� Example 2�4 demon-stratesthismethod�

Example 2.4

ForthesystemofExample2�1,assumethevoltageatN1is2400V,and

compute the secondary voltages on the three transformers, allocating

theloadsbaseduponthetransformerratings�Assumethatthemetered

kWdemandatN1is92�9kW�

Theimpedancesofthelinesegmentsandtransformersarethesame

asinExample2�3�

Assume the load power factor is 0�9 lagging, and compute the kVA

demandatN1fromthemetereddemand:

 S12 92 9 1 j

0 9 0 9 92 9 45 0 103 2 25 84

= . = + =

. /cos ( . ) . . . / . kVA

CalculatetheAF:

 AF=

+ + =

103 2 25 84

25 37 5 50. / . 0 9175 25 84

. . / .

Allocatetheloadstoeachtransformer:

ST1=AF kVA T1=( .0 9175 25 84 25 20 6/ . ) = . +j10 0. kVA

 ST2=AF kVA T2=( .0 9175 25 84 37 5 31 0/ . ) . = . +j15 0. kVA ST3=AF kVA T3=( .0 9175 25 84 50 41 3/ . ) = . +j20 0. kVA

Calculatethelineflows:

 S12=ST1+ST2+ST3=92 9. +j45 0. kVA

 S23=ST2+ST3=72 3. +j35kVA

 S34=ST3=41 3. +j20 0. kVA

Usingthesevaluesoflineflowsandflowsintotransformers,theproce-dure for computing the transformer secondary voltages is exactly the

sameasinExample2�3�Whenthisprocedureisfollowed,thenodeand

secondarytransformervoltagesare

 V2=2378 1 0 4. / . V VlowT1=234 0 0 6. / . V

 V3=2376 4 0 4. / . V VlowT2=233 7 0 8. / . V

 V4=2374 9 0 5. / . V VlowT3=233 5 0 9. / . V Thepercentvoltagedropforthiscaseis



V V V

drop V T

=

= =

1 3

1

100 2400 2334 8

2400 . 100 2 7179. %



2.5 Summary

Thischapterhasdemonstratedthenatureoftheloadsonadistributionfeeder�

Thereisagreatdiversitybetweenindividualcustomerdemands,butasthe

demandismonitoredonlinesegmentsworkingbacktowardthesubstation,

theeffectofthediversitybetweendemandsbecomesveryslight�Itwasshown

that the effect of diversity between customer demands must be taken into

account when the demand on a distribution transformer is computed� The

effectofdiversityforshortlateralscanbetakenintoaccountindetermining

themaximumflowonthelateral�FortheDFsofTable2�2,itwasshownthat

whenthenumberofcustomersexceeds70,theeffectofdiversityhaspretty

much disappeared� This is evidenced by the fact that the DF has become

almostconstantasthenumberofcustomersapproached70�Itmustbeunder-stoodthatthenumber70willapplyonlytotheDFsofTable2�2�Ifautilityis

goingtouseDFs,thenthatutilitymustperformacomprehensiveloadsurvey

inordertodevelopthetableofDFsthatapplytothatparticularsystem�

Examples2�3and2�4showthatthefinalnodeandtransformervoltages

areapproximatelythesame�Thereisverylittledifferencebetweenthevolt-ageswhentheloadswereallocatedusingtheDFsandwhentheloadswere

allocatedbaseduponthetransformerkVAratings�

Problems

2.1 Showninthefollowingtablearethe15minkWdemandsforfourcus-tomers between the hours of 17:00 and 21:00� A 25kVA single-phase

transformerservesthefourcustomers�

Time

Customer #1 (kW)

Customer #2 (kW)

Customer #3 (kW)

Customer #4 (kW)

17:00 8�81 4�96 11�04 1�44

17:15 2�12 3�16 7�04 1�62

17:30 9�48 7�08 7�68 2�46

17:45 7�16 5�08 6�08 0�84

18:00 6�04 3�12 4�32 1�12

18:15 9�88 6�56 5�12 2�24

18:30 4�68 6�88 6�56 1�12

18:45 5�12 3�84 8�48 2�24

19:00 10�44 4�44 4�12 1�12

19:15 3�72 8�52 3�68 0�96

19:30 8�72 4�52 0�32 2�56

19:45 10�84 2�92 3�04 1�28

20:00 6�96 2�08 2�72 1�92

20:15 6�62 1�48 3�24 1�12

20:30 7�04 2�33 4�16 1�76

20:45 6�69 1�89 4�96 2�72

21:00 1�88 1�64 4�32 2�41

 a� Foreachofthecustomersdeterminethefollowing:

 1� Maximum15minkWdemand

 2� Average15minkWdemand

 3� TotalkWhusageinthetimeperiod

 4� Loadfactor

 b� Forthe25kVAtransformerdeterminethefollowing:

 1� Maximum15mindiversifieddemand

 2� Maximum15minnoncoincidentdemand

 3� Utilizationfactor(assumeunitypowerfactor)

 4� Diversityfactor

 5� Loaddiversity

 c� Plottheloaddurationcurveforthetransformer�

2.2 TwotransformerseachservingfourcustomersareshowninFigure 2�13�

ThefollowingtablegivesthetimeintervalandkVAdemandofthe

fourcustomerdemandsduringthepeakloadperiodoftheyear�Assume

apowerfactorof0�9lagging�

Time #1 #2 #3 #4 #5 #6 #7 #8

3:00–3:30 10 0 10 5 15 10 50 30

3:30–4:00 20 25 15 20 25 20 30 40

4:00–4:30 5 30 30 15 10 30 10 10

4:30–5:00 0 10 20 10 13 40 25 50

5:00–5:30 15 5 5 25 30 30 15 5

5:30–6:00 15 15 10 10 5 20 30 25

6:00–6:30 5 25 25 15 10 10 30 25

6:30–7:00 10 50 15 30 15 5 10 30

 a� Foreachtransformerdeterminethefollowing:

 1� 30minmaximumkVAdemand

 2� NoncoincidentmaximumkVAdemand

 3� Loadfactor

 4� Diversityfactor

 5� Suggestedtransformerrating(50,75,100,167)

 6� Utilizationfactor

 7� Energy(kWh)duringthe4hperiod

 b� Determine the maximum diversified 30min kVA demand at

the “tap�”

2.3 Two single-phase transformers serving 12 customers are shown in

Figure2�14�

The15minkWdemandsforthe12customersbetweenthehoursof

5:00p�m�and9:00p�m�aregivenattheendofthisproblem�Assume

a load power factor of 0�95 lagging� The impedance of the lines are

z = 0�306 +j0�6272Ω/mile�ThevoltageatnodeN1is2500/0V�

#3 #4

#1 #2 #5 #6 #7 #8

Tap

FIGURE 2.13

SystemforProblem2�2�

Transformerratings:

T1: 25kVA 2400–240V Zpu=0�018/40 T2: 37�5kVA 2400–240V Zpu=0�020/50

 a� DeterminethemaximumkWdemandforeachcustomer�

 b� DeterminetheaveragekWdemandforeachcustomer�

 c� DeterminethekWhconsumedbyeachcustomerinthistimeperiod�

 d� Determinetheloadfactorforeachcustomer�

 e� Determinethemaximumdiversifieddemandforeachtransformer�

 f� Determine the maximum noncoincident demand for each

transformer�

 g� Determinetheutilizationfactor(assume1�0powerfactor)foreach

transformer�

 h� DeterminetheDFoftheloadforeachtransformer�

 i� DeterminethemaximumdiversifieddemandatnodeN1�

 j� Computethesecondaryvoltageforeachtransformertakingdiversity

intoaccount�

Transformer#1:25kVA

Time #1 (kW) #2 (kW) #3 (kW) #4 (kW) #5 (kW)

05:00 2�13 0�19 4�11 8�68 0�39

05:15 2�09 0�52 4�11 9�26 0�36

05:30 2�15 0�24 4�24 8�55 0�43

05:45 2�52 1�80 4�04 9�09 0�33

06:00 3�25 0�69 4�22 9�34 0�46

06:15 3�26 0�24 4�27 8�22 0�34

T1 T2

N1 N2 N3

1 2 3 4 5 6 7 8 9 10 11 12

2500 ft 5000 ft

FIGURE 2.14

CircuitforProblem2�3�

(continued)

Time #1 (kW) #2 (kW) #3 (kW) #4 (kW) #5 (kW)

06:30 3�22 0�54 4�29 9�57 0�44

06:45 2�27 5�34 4�93 8�45 0�36

07:00 2�24 5�81 3�72 10�29 0�38

07:15 2�20 5�22 3�64 11�26 0�39

07:30 2�08 2�12 3�35 9�25 5�66

07:45 2�13 0�86 2�89 10�21 6�37

08:00 2�12 0�39 2�55 10�41 4�17

08:15 2�08 0�29 3�00 8�31 0�85

08:30 2�10 2�57 2�76 9�09 1�67

08:45 3�81 0�37 2�53 9�58 1�30

09:00 2�04 0�21 2�40 7�88 2�70

Transformer#2:37�5kVA

Time #6 (kW) #7 (kW) #8 (kW) #9 (kW) #10 (kW) #11 (kW) #12 (kW)

05:00 0�87 2�75 0�63 8�73 0�48 9�62 2�55

05:15 0�91 5�35 1�62 0�19 0�40 7�98 1�72

05:30 1�56 13�39 0�19 5�72 0�70 8�72 2�25

05:45 0�97 13�38 0�05 3�28 0�42 8�82 2�38

06:00 0�76 13�23 1�51 1�26 3�01 7�47 1�73

06:15 1�10 13�48 0�05 7�99 4�92 11�60 2�42

06:30 0�79 2�94 0�66 0�22 3�58 11�78 2�24

06:45 0�60 2�78 0�52 8�97 6�58 8�83 1�74

07:00 0�60 2�89 1�80 0�11 7�96 9�21 2�18

07:15 0�87 2�75 0�07 7�93 6�80 7�65 1�98

07:30 0�47 2�60 0�16 1�07 7�42 7�78 2�19

07:45 0�72 2�71 0�12 1�35 8�99 6�27 2�63

08:00 1�00 3�04 1�39 6�51 8�98 10�92 1�59

08:15 0�47 1�65 0�46 0�18 7�99 5�60 1�81

08:30 0�44 2�16 0�53 2�24 8�01 7�74 2�13

08:45 0�95 0�88 0�56 0�11 7�75 11�72 1�63

09:00 0�79 1�58 1�36 0�95 8�19 12�23 1�68

2.4 Onadifferentday,themetered15minkWdemandatnodeN1forthe

systemofProblem2�3is72�43kW�Assumeapowerfactorof0�95lagging�

Allocatethemetereddemandtoeachtransformerbaseduponthetrans-formerkVArating�Assumetheloadsareconstantcurrentandcompute

thesecondaryvoltageforeachtransformer�

2.5 Asingle-phaselateralservesfourtransformersasshowninFigure 2�15�

Assumethateachcustomer’smaximumdemandis15�5kW+j7�5kvar�

Theimpedanceofthesingle-phaselateralisz=0�4421+j0�3213Ω/1000ft�

Thefourtransformersareratedas

T1andT2:37�5kVA,2400–240V,Z=0�01+j0�03perunit T3andT4:50kVA,2400–240V,Z=0�015+j0�035perunit UsetheDFsfoundinTable2�2anddeterminethefollowing:

 a� The 15min maximum diversified kW and kvar demands on each

transformer�

 b� The15minmaximumdiversifiedkWandkvardemandsforeachline

section�

 c� Ifthevoltageatnode1is2600/0V,determinethevoltageatnodes

2through9�Incalculatingthevoltages,takeintoaccountdiversity

usingtheanswersfrom(a)and(b)�

 d� Usethe15minmaximumdiversifieddemandsatthelateraltap(sec- tions1–2)frompart(b)�Dividethesemaximumdemandsby18(num-berofcustomers)andassignthatasthe“instantaneousload”foreach

customer�Nowcalculatethevoltagesatallofthenodeslistedinpart

(c)usingtheinstantaneousloads�

 e� Repeatpart(d)exceptassumetheloadsare“constantcurrent�”Todo

this,takethecurrentflowingfromnode1tonode2frompart(d)and

divideby18(numberofcustomers)andassignthatasthe“instanta-neousconstantcurrentload”foreachcustomer�Again,calculateall

ofthevoltages�

 f� Takethemaximumdiversifieddemandfromnode1tonode2and

“allocate” that to each of the four transformers based upon their

kVAratings�Todothis,takethemaximumdiversifieddemandand

divideby175(totalkVAofthefourtransformers)�Nowmultiplyeach

transformerkVAratingbythatnumbertogivehowmuchofthetotal

diversifieddemandisbeingservedbyeachtransformer�Again,cal-culateallofthevoltages�

 g� Computethepercentdifferencesinthevoltagesforparts(d)through

(f)ateachofthenodesusingpart(c)answerasthebase�

1 2 4 6 8

7 5

3 9

380 ft 470 ft 750 ft 820 ft

T1 T2 T3 T4

FIGURE 2.15

SystemforProblem2�5�

39

3