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1. INTRODUCCIÓN

2.3. Recurso Educativo TIC

2.3.2. Las Tecnologías de la Información y la Comunicación (TIC)

Proof Let S. By Lemma 2.47 there exist Weber strings in(S) as well as (N\S), say (R

i)iSand (Rj)jN\S, respectively. Then (Ri)iNis a Weber string in where

Ri=

Ri for iS

{i} ∪(N\Ri) for i/S

Clearly if iS, Ri; furthermore, iRi =Riand for i such that Ri=Ri= {i} there is a player jS with Ri\ {i} =Ri \ {i} =Rj =Rj. Now if i/ S either Ri = {i} ∪N\Ri =N\(Ri \ {i})=N\Rj for a player j/S, or Ri =N\∅=N and, since ()=for every lattice, we conclude that Ri.

Furthermore, iRiand

if Ri =N\S, then Ri\ {i} =N\Ri =S=Rj=Rjfor some jS;

if Ri =N\S then there is a player k/ S with Ri=Rk\ {k}. Hence, Ri\ {i} = N\Ri =N\(Rk\ {k})= {k} ∪N\Rk =Rk.

We conclude that for all players iN we have Riand if Ri = {i}there is a

player j such that Ri\ {i} =Rj.

Corollary 2.49 Let S1,. . ., SK be elements insuch that S1 ⊂ S2 ⊂ · · · ⊂ SK. Then there exists a Weber string inof which S1,. . ., SKare members.

Proof of 2.41(a)

Sinceis discerning by Lemma 2.39 there exists at least one Weber string in. Now suppose to the contrary that there exists a Core allocation xC(, v) such that x/ W(, v)+. By Theorem 2.34 the set W(, v)+ is polyhedral and since is discerning/non-degenerate, it does not contain a nontrivial linear subspace. Thus x is an extreme point of

Conv [{x} ∪(W(, v)+)] .

The normals of all supporting hyperplanes in an extreme point of a polyhedral set are well known to form a full dimensional cone. Therefore, there exists a normal vector, say p∈RN, with non-equal coefficients such that for each yW(, v) and y:

p·x<p·(y+y).

Now by Theorem 2.34 for every iN, j∂iand M 0 it holds that for every yW(, v):

p·x<p·y+M p·(ejei)=p·y+M (pjpi) (2.36) implying that for every iN and j∂i: pjpi. Now label the players in N such that p1> p2 >· · · >pn. Consider for every kN the coalition Sk = {1,. . ., k}. If iSk, then pi pk, in turn implying that pj pi pkfor all j∂i. Hence, ∂iSkfor all iSkimplying that

Sk =( iSk

∂i.

Hence, (Sk)kNdetermines a Weber string in. The corresponding marginal vector y for v now belongs toW(, v). Thus,

p·x<p·y= kN % v(Sk)−v(Sk−1)& =v(N) pn+ kN v(Sk) (pkpk+1).

Since xC(, v) and Sk(kN), we conclude that x(N)=v(N) and x(Sk) v(Sk), k=n. Furthermore, pkpk+1 0 for k =n. Therefore, the above may be rewritten as

p·x<v(N) pn+ kN v(Sk) (pkpk+1) x(N) pn+ n−1 k=1 k j=1 xj(pkpk+1) = n k=1 k j=1 xjpkn k=2 k−1 j=1 xjpk =x1p1+ n k=2 pkxk=p·x. This constitutes a contradiction, proving the desired inclusion. Proof of 2.41(b)

Only if:

Suppose that vGN. Given the already established facts, we only have to show that every Weber allocation xW(, v) belongs to C(, v). So, let xW(, v) correspond to some Weber string (Ri)iNwith for every iN

xi=v(Ri)−v(Ri\ {i}). Since v is convex onfor every iSwe have that

v(Ri)+v(S(Ri\ {i}))v(SRi)+v(Ri\ {i}). Thus, for every iS:

xiv(SRi)−v(SRi\ {i}).

Without loss of generality we may assume that N is labelled such that the players in S are labelled first and{1,. . ., k} ⊂Rkfor all kS. Then

iS xi |S| k=1 xk |S| k=1 v(SRk)−v(SRk\ {k}) = |S| k=1 v({1,. . ., k})− |S|−1 k=1 v({1,. . ., k}) =v({1,. . .,|S|})=v(S).

If:

Suppose that C(, v)=W(, v)+. Take S, T. Sinceis discerning by Corollary 2.49 there exists a Weber string in, say (Ri)iN, such that it contains the coalitions ST and ST.

Let xW(, v) be the corresponding Weber allocation—or marginal payoff vector. It is evident that x(ST) =v(ST) as well as x(ST) =v(ST). By hypothesis xC(, v), which leads to the conclusion that

v(S)+v(T)x(S)+x(T)= =x(ST)+x(ST)= =v(ST)+v(ST). This proves the convexity of v.

2.5 Problems

Problem 2.1 Let N = {1, 2, 3}and consider the game vGNgiven by the following table:

S ∅ 1 2 3 12 13 23 123

v(S) 0 0 5 6 15 0 10 20

(a) Give the (0, 1)-normalization vof this game v.

(b) Compute the Core C(v)I(v) of the game v and of its (0, 1)-normalization v. Show that these two Cores are essentially identical. Formulate this identity precisely.

(c) Draw the Core C(v) of the (0, 1)-normalization v of the game v in the two- dimensional simplexS2.

Problem 2.2 Consider the so-called bridge game, introduced by Kaneko and Wood- ers (1982, Example 2.3). Let N = {1,. . ., n}and define vGNby

v(S)=

1 if|S| =4 0 otherwise. In the bridge game only quartets can generate benefits.

Show that C(v)=∅if and only if n=4m for some m∈N.

Problem 2.3 Construct a non-essential three player game that has an empty Core.