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Terrorismo en Gran Bretaña

In document EL TERRORISMO EN LA EUROPA DEL BIENESTAR (página 108-118)

(ii) ThO2, (iii) alc.KOH,

(R)(i) HOBr/H

+

(ii) ThO2, (iii) alc.KOH,

(S)

(A) Br

;

(C) Br

;

(B) Br

;

(D) Br ;

5.3 End product D of the following reaction will be Cl

A B C D

H O2 ZnCl HCl2 Mg/ether D O2

D

(A) (B) OD (C) D (D) D

OD

5.4 consider the following reactions

H C5 2 C2H5 H

C2H5 H

C = C

H C5 2 H H C = C

C2H5 CH2 C H C5 2

O

2CH3 CH2 COOH R1 R2

R3 R4 H C —C 5 2 C—C H2 5

The correct set of reagents for these reactions is

Alkenes & Alkynes

5

R

(A) H /Lindlar catalyst (B) H /Lindlar catalyst (C) (i) O , (ii) H O H /Lindlar catalyst

2 H /Lindlar catalyst Na / Iiq.NH

5.5 The major product of the following reaction is :

Br Cl (1)

5.6 Themost ap0propriatew major product of the followning sequence of reactions would be.

CH CH3 2

5.7 Compound'P' of the following reaction swequence can be

(P) O O [C H O ]8 6 3

5.8 The alkene limonene has the following structure,

Which product resutls from the reaction of limonene and 1 molar equivalent chlorine water?

OH

5.9 The end product 'W' in the follownign sequence of reactions is : CH CH2 3

5.10 Which of the following corrently represents tthe rate of acid-catalysed hydration of followning alkenes.

5.12 The most stable conformation of the product of followning reaction

C CH

5.13 In the given reaction,

CH3

(X)

B H , THF2 6 H2O2, NaOH TSCl t–BuO K– + (Y)

The product 'Y' is

(A) A positional isomer of X (B) Identical to X

(C) Chain isomer of X (D) An oxidation product of X.

5.14 Which of the following compouinds would liberate two moles of methane when treated with methyl magnesium bromide?

CH – CH – CH – C CH3 2 (A)

OH

CH – C – CH – C CH33 (C)

O CH3

O

(B)

(D)

CH – C – CH – 3 2 CH OH2 O

OH

COOC H2 5

5.15 The best yiest of product 'X' ca be obtained byt using which one of the foloowing sequence of reagents and reactants

X = CH – C C – CH – CH (CH )3 3 2 OH

(A) CH – C CH3 NaNH2 (CH ) CHCHO3 2 H3O+ (A) CH – C CH3 NaNH2 (CH ) CHCHO3 2 H3O+

( ) CHB ( 3) CH2 – C CH – C – H NaNH2 CH3I ( ) CHC 3 – C – H CC C – H –2 CH3 NaNH2 CH3I

OH

OH

( ) CHD ( 3) CH2 – C CH – C – H CH3MgI CH3I OH

5.16

H3C – C – CH – CH2 3 CH3

H3C – CH2 – CH – 2 N H3C – C – CH3

CH3

CH3 – C – Cl O

X, X is AlCl3

(i) CH3I (ii) AgOH,

In the above reaction the product will be–

(A) CH – CH – CH – Cl3 2 COCH3

( ) CH – CH – CH – CB 3 2 – CH3

Cl O

( ) CH – CH –C 3 C – CH – 2 CH3 Cl

( ) CH – CH – CH – CB 3 2 – CH3

Cl O

O

CH3

5.17 Fastest rate of electrophilic addition will take place in

(A) HO CH = CH2

(C) CH3O CH = CH2

(B)ON CH = CH2

(D) CH = CH2

5.18 Which of the following will be the correct product (P) for the given reaction ?

OH

Conc. H PO3 4 (P)

OH (A)

OH

(B) (C) (D)

5.19 CH2 HBr X (major) R O2 2

aq NaOH

Y (major) H2SO4/

Z (major) Identify the correct option

BrCH3

BrCH3

OHCH3

OHCH3 CH3 CH3

CH2 OH

CH3 Br

CH3

OH

CH2 CH3

Br CH3

X Y Z

(A)

(B)

(C)

(D*)

5.20 X HOOC – C – CH – CH – CH – CH – COOH2 2 2 2

Product; Product is :

D C C H

5.22 The final product of the following reaction is

Me

SECTION - II : MULTIPLE CORRECT ANSWER TYPE

5.23 Which statement is correct about the end product of the following reaction series, C CH HOCI (excess)

(1) (2)

conc. NaOH,

(A) It is optically inctive hydroxy detone (B) It is a resolvable hydroxy acid

(C) It is a nonresolvable aldehyde (D) It is an optically inactive hydroxy acid 5.24 The following synthesis can not be carried out be:

CH = CH2 CH = CH2

(C)

Compound C of the above reaction can not be :

(A)

SECTION - III : ASSERTION AND REASON TYPE

5.27 Statement-1 :

major at low temp major at of high temp CH3

CH2 Br

(A) Statement-1 is True, Statement-2 is True; Statement-2 is acorrect explanation for Statement-1.

(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.

(C) Satement-1 is True, Statement-2 is False.

(D) Statement-1 is False, Statement-2 is True.

5.28 Statement-1 : Me

Me NBS

Me Me Br

+

Me Me Br

Statement-2 : Me Me

Br.

–HBr

Me Me

Me Me

Br2 Br

Br2 Me Br Me

Me Me

(A) Statement-1 is True, Statement-2 is True; Statement-2 is acorrect explanation for Statement-1.

(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.

(C) Satement-1 is True, Statement-2 is False.

(D) Statement-1 is False, Statement-2 is True.

5.29 Statement-1 : Reduction of but-2-yne by Na/liq. NH3 given 'trans' but-2-ene.

Statement-2 : It is an example of 'anti' addition.

(A) Statement-1 is True, Statement-2 is True; Statement-2 is acorrect explanation for Statement-1.

(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.

(C) Satement-1 is True, Statement-2 is False.

(D) Statement-1 is False, Statement-2 is True.

5.30 Statement-1 : But-1-ene gives 2-Bromobutane with HBr/Preroxide

Statement-2 : The reaction involves formation of more stable free radical and in that respect the addition is Markovnikof although the product obtained appears as anti Markovbnidof product.

(A) Statement-1 is True, Statement-2 is True; Statement-2 is acorrect explanation for Statement-1.

(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.

(C) Satement-1 is True, Statement-2 is False.

(D) Statement-1 is False, Statement-2 is True.

SECTION - IV : TRUE AND FALSE TYPE

5.31 The addition of HBr to butadiene at –80°C to give 1, 2-adduct is kinetically controlled while that at 40°C to give 1, 4-adduct is thermodynamically controlled.

5.32 In preparation of terminal alkynes from vicinal dihalides, at least 2 equivalents of sodium amide must be added per mole of vicinal dihalide.

SECTION - V : COMPREHENSION TYPE

Comprehension # 1

Demercuration allows Mardownikoffs addtion of H, OH without re arangement. The net result is the addition of H2O. Answer the following question.

5.33 CH3

CH3

CH3–C–CH =CH2 i)Hg(OAc) . THF2

ii)CH OH, NaBH NaOH3 4 A HI (Conc.) B, Product B is :

(A) (CH ) CCH– CH3 3 3

OH

(B) CH3I (C) CH CH3 2I (D) (CH ) CCH– CH3 3 3 I

5.34

CH CH = CH3 2 O

N–Br

O A

1) Hg)OAc) , THF 2) H O

2 2

3) NaBH , NaOH4 B OH C.

The product 'C' formation from B occurs throuth

(A) enol formation (B) SN1mechanism

(C) Neighbouring group particitation (D) SNAR mechanism

5.35

OH

i) Hg(OAC) .THF2 ii) NaBH , NaOH4 A, Product 'A' is :

(A)

OH

HO (B)

OH (C)

OH

(D) OH

OH

Comprehension # 2

(A) AI O2 3 250°C

(B) HI (ii) AgOH

(C) AI O2 3 150°C

(B) (i) B H2 6 (A) (ii) H O ,OH2 2

In the above reaction sequence (A) and (c)are isomers. MOlecular formula of B is C5H10, which can also be obtained from the product of the reaction with CH3CH2MgBr and (CH3) CO and followed followed by acidification.

5.36 Identify the structure of A

(A) CH3–CH2–CH2–CH–CH3 (B) (CH3)2 CHCHOHCH3 (C) (CH3)3 C–CH2–OH (D) CH3–CH2–CH–CH2–CH3

OH OH 5.37 Identify th structure of B

(A) (CH ) –CH–CH=CH3 2 2(B)

CH3 CH2 CH3 CH3 C C=

(C)(CH ) CH= CHCH3 2 3 (D) CH =CH–CH–CH2 3 CH3

5.38 Identify the structure of C

OH OH OH

CH3

(A) CH –CH –CH –CH–CH (B) CH –CH –C–CH (C) (CH ) C–CH –OH (D) CH –CH –CH–CH –CH3 2 2 3 3 2 3 3 3 2 3 2 2 3

In document EL TERRORISMO EN LA EUROPA DEL BIENESTAR (página 108-118)