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II. SITUACIÓN DE LOS PUEBLOS INDÍGENAS EN ALC……………………………………………………….11-64

2.4. Paz y Gobernabilidad……………………………………………………………………………….54-64

2.4.3. Acceso a la Justicia

The inflow to a reservoir is the most important random variable that introduces uncertainty in reservoir planning and operation problems. In Section 5.1, a deterministic LP model was formulated to obtain the reservoir capacity to meet a specified demand, Dt, during period t, when inflow Qt and evaporation Et during period t are known. The deterministic model is rewritten here as

Min K subject to

St + Qt – Rt – Et = St+1 Rt³ Dt

Rt £ Rtmax

St£ K St³ Smin

where K is the reservoir capacity, St is the storage at the beginning of period t, Rt is the release during period t, Rtmax is the maximum release that can be made in period t (normally decided by canal capacities), and Smin is the minimum storage below which no release is made.

In this model, the demands from the reservoir are met 100% of the time, in a feasible solution, provided all variables are deterministic. The inflow Qt, how-ever, is a random variable and thus is not known with certainty. Its probability distribution, however, may be estimated from the historical sequence of in-flows. Being functions of the random variable Qt, the storage St and the release Rt are also random variables.

In a constraint containing two random variables, if the probability distribu-tion of one is known, the probabilistic behavior of the second can be expressed as a measure of chance in terms of the probability of the first variable. If a constraint contains more than two random variables, we get into computational complications, and we need to understand the specific problem clearly to reformulate the problem, if necessary, and avoid those complications.

Chance Constraint

The constraint, relating the release, Rt (random) and demand, Dt (determinis-tic), is expressed as a chance constraint, P[Rt ³ Dt] ³ a1; meaning that the probability of release equalling or exceeding the known demand is at least equal to a1, which is referred to as the reliability level. The interpretation of this chance constraint is simply that the reliability of meeting the demand in period t is at least a1.

Similarly, the maximum release and the maximum and minimum storage constraints are written as

P[Rt £ Rtmax ] ³ a2 (6.2.1)

P[St£ K] ³ a3 (6.2.2)

and P[St³ Smin] ³ a4 (6.2.3)

To use the constraints (6.2.1) to (6.2.3) in an optimization algorithm, we must first determine the probability distribution of Rt and St from the known probability distribution of Qt. However, because St, Qt, and Rt are all interde-pendent through the continuity equation, it is, in general, not possible to derive the probability distributions of both St and Rt. To overcome this difficulty and to enable the use of linear programming in the solution, a linear decision rule is appropriately defined.

6.2.1 Linear Decision Rule

The linear decision rule (LDR) relates the release, Rt, from the reservoir as a linear function of the water available in period t. The simplest form of such an LDR is

Rt = St + Qt – bt

where bt is a deterministic parameter called the decision parameter.

In this LDR, the entire amount, Qt, is taken into account while making the release decision. Depending on the proportion of inflow, Qt, used in the linear decision rule, a number of such LDRs may be formulated. A general form of this LDR may be written as

Rt = St + bt Qt – bt 0 £ bt£ 1

bt = 0 yields a relatively conservative release policy with release decisions related only to the storage, St; bt = 1 yields an optimistic policy where the entire amount of water available (St + Qt), is used in the LDR.

Consider the LDR

Rt = St + Qt – bt (6.2.4)

The storage continuity equation is

St+1 = St + Qt – Rt (6.2.5)

From (6.4) and (6.5)

St+1 = bt (6.2.6)

Thus, the random variable, St+1, is set equal to a deterministic parameter bt. In essence, the role of the linear decision rule in this case is to treat St deter-ministic in formulation. A main advantage of doing this is to do away with one of the random variables, St, so that the distribution of the other random vari-able, Rt, may be expressed in terms of the known distribution of Qt. This implies that the variance of Qt is entirely transferred to the variance of Rt.

Including evaporation loss as a storage-dependent term in the storage conti-nuity equation, the linear decision rule Eq. (6.2.4) is written as,

Rt = Qt – [Aoet] + [1 – (a et/2)] bt–1 – [1 + (a et/2)] bt. where Ao, a, and et are as defined earlier in Section 5.1.

6.2.2 Deterministic Equivalent of a Chance Constraint

Knowing the probability distribution of inflow, Qt, it is possible to obtain the deterministic equivalents of the chance constraints using the LDR, (6.2.4), as follows:

P[Rt ³ Dt] ³ a1

i.e. P[St + Qt – bt ³ Dt] ³ a1

P[bt–1 + Qt – bt³ Dt] ³ a1 using St = bt–1 from (6.2.6) P[Qt ³ Dt + bt – bt–1] ³ a1

P[Qt£ Dt + bt – bt–1] £ 1 – a1 see Fig. 6.9 (6.2.7)

a qt

f (qt)

P [Qt³ a] + P [Qt£ a] = 1 P [Qt£ a] = 1 – a

P [Qt³ a] = a

Fig. 6.9 Probability Density Function of Qt

The term, Dt + bt – bt–1, on the right-hand side of the inequality within brackets in Eq. (6.2.7) is deterministic, with bt–1 and bt being decision variables and the demand Dt being a known quantity for the period t. Therefore Eq.

(6.2.7) is written as

FQt (Dt + bt – bt–1) £ 1 – a1

where

Qt

F (Dt + bt – bt–1) denotes the CDF of the random variable Qt. From this we write the deterministic equivalent of the chance constraint, P [Rt ³ Dt] ³ a1 as,

(Dt + bt – bt–1£ FQ-t1 (1 – a1)

1 Qt

F- (1 – a1) is the flow, qt, at which the CDF value is 1 – a1, as shown in Fig. 6.10.

Fig. 6.10 Flow Value for a Specified CDF Value

The deterministic equivalent of the chance constraint, Eq. (6.2.1), is simi-larly obtained, as

Rtmax + bt – bt–1³ –1

Qt

F (a2)

Since the storage, St, is set equal to the deterministic parameter, bt–1, the chance constraints (6.2.2) and (6.2.3), containing only the storage random vari-able are written as deterministic constraints (without using the probability dis-tribution of inflows). The complete deterministic equivalent of the CCLP is thus written as

Min K subject to

Dt + bt – bt–1£ –1

Qt

F (1 – a1) "t Rtmax + bt – bt–1³ FQ–1t (a2) "t

bt–1 £ K "t

bt–1 ³ Smin "t

bt ³ 0 "t

K ³ 0

While solving this model, for a problem with 12 periods (months) in a year, we also set b0 = b12 for a steady state solution. Further, depending on the nature of LDR used, the decision parameters, bt, may be unrestricted in sign. For example, if we use the LDR, Rt = St – bt, the decision parameter, bt, may be

allowed to take negative values. When a particular bt is negative, it implies that the release is more than the initial storage in period t, and the volume of release over the available storage, St, is provided by part of the inflow, Qt, not included in the LDR.

Example 6.2.1 With the linear decision rule, Rt = St + (1 – a)Qt – bt, where 0 £ a £ 1, obtain the deterministic equivalent of the storage chance constraint, P(St £ K) ³ 0.9. Assume that the flows, Qt, follow exponential distribution, with pdf given by,

f (q) = be–bq q> 0.

Write down the deterministic equivalent for a two-period (t = 1 and t = 2) problem when b = 3 for period t = 1, and b = 5 for period t = 2. K is the known reservoir capacity. Neglect evaporation losses.

Solution: Deterministic equivalent of P(St £ K) ³ 0.9

P[aQt–1 + bt–1 £ K] ³ 0.9 CDF of exponential distribution is F(q) = 1 – e–bq For t = 1

Example 6.2.2 Write down the complete deterministic equivalent of the following, three-period chance constrained LP problem. Use linear decision rule, Rt = St – bt.

St is the storage at the beginning of the period t, Rt is the release during the period t, and K is the reservoir capacity. Neglect losses. The following table gives the F–1( ) values for the inflows and the Rmax and Rmin values for different periods. Solve the CCLP problem to obtain the minimum capacity required. The constraint can be written as

P[Smin £ St] ³ 0.9

From the F–1(.) values given,

Reservoir 1

Reservoir 2

Reservoir 4

Reservoir 3

Arrows Indicate Direction of Flow

Fig. 6.11 A Four-reservoir System

Capacities of the reservoirs are K1, K2, K3, and K4 respectively.

We use the following notation in this example:

Sit : Storage in reservoir i at the beginning of period t.

Rit : Release from reservoir i in period t.

Qit : Inflow to reservoir i in period t.

bit : Decision parameter for reservoir i, period t.

With the values given,

24 + b1 – b3 £

3

1

FQ- (0.25) t = 1 20 + b2 – b1£ FQ-11 (0.25) t = 2 20 + b3 – b2 £

2

1

FQ- (0.25) t = 3 24 + b1 – b3£ 21 t = 1 20 + b2 – b1£ 33 t = 2 20 + b3 – b2£ 20 t = 3 The solution of this model results in

K = 90; b1 = 0; b2 = 9; b3 = 5.

Example 6.2.3 Formulate a CCLP model to obtain minimum capacities of the reservoirs in the four-reservoir system shown in Fig. 6.11 and write down the deterministic equivalents, assuming that all water released from an upstream reservoir is available at the downstream reservoir. A minimum flood free-board is to be maintained in all reservoirs in each period.

yit : Minimum flood storage to be maintained in reservoir i, at the begin-ning of period t

Ritmin : Minimum release from reservoir i, in period t.

Ritmax: Maximum release from reservoir i, in period t.

Stimin : Storage below which no release is made from reservoir i, in period t.

Linear decision rule (LDR):

Substituting these in storage continuity equation Reservoirs 1 and 3

-å å

substituting for R1t

Reservoir 4 Sit is the initial storage for the reservoir i at period t. yit is the freeboard to be maintained at the end of period t.

The CCLP is written as

Min K1 + K2 + K3 + K4

P[Sit³ Sitmin] ³ a1,t i "i, t P[Ki – Sit³ yit] ³ a2,t i "i, t

P[Rit³ tmin

4 maxt

- (.) appearing on the RHS of the last 2 constraints of Reservoir 4 is obtained from the distribution of the sum of the flows, Q1t–1 + Q2t–1 + Q3t–1 + Q4t–1

Example 6.2.4 Relevant data for the multireservoir problem discussed in Example 6.2.3 are given in the following tables. The configuration of the system and the data are adapted from Nayak and Arora (1971), with minor modifications. All a values are set to 0.90. Flows corresponding to F–1(1 – a) are denoted as Fqmin and those corresponding to F–1(a) as Fqmax, for

(Units for flows, releases, decision parameters, and storages: Mm3) Reservoir 1

Reservoir 3

This problem is solved using LINGO (PC software for LP). The solution obtained is given in the following table.

Solution of the Multireservoir CCLP Problem (All Values in Mm3) Reservoir 1 Reservoir 2 Reservoir 3 Reservoir 4 Total

Capacity optimal capacity 566.85 656.65 691.9 570.75 2486.15

month Decision

Problems

6.2.1 At a site proposed for a reservoir, the streamflows for the two seasons within a year are known to be normally distributed with the following parameters:

Season I II

Mean 30 20

Std. Dev 18 12

The reservoir is required to serve demands of 20 and 30 units in the two seasons, respectively. Formulate a chance constrained linear pro-gramming problem to determine the minimum capacity of the reser-voir. Using an LDR of the form, Rt = St – bt, with the usual notations, write down the deterministic equivalent of the minimum release con-straints for the two seasons. The minimum reliability with which the demands must be met in the two periods are 0.95 and 0.9, respectively.

6.2.2 Ten years of data are available for the inflows at a site, for the two seasons (t = 1 and t = 2) in a year. The inflow values (Mm3) are given below:

t = 1 1500 4410 1020 8170 11750 5609 6579 1098 3200 3430 t = 2 1000 787 1020 3040 779 678 908 2200 1690 1219 Average evaporation during the two seasons is 3.0 and 1.0 Mm3, respectively. It is known that the inflows in season t = 1 are lognormally distributed, and those in season t = 2 are normally distributed. With the usual notations used in Chance Constrained LP for reservoir de-sign, write down the complete deterministic equivalents of the follow-ing chance constraints. Use the LDR, St = Rt + bt.

P[Rt³ 3000] ³ 0.85 t = 1, 2 P[Rt£ 7000] ³ 0.95 t = 1, 2

6.2.3 Monthly flows at a site proposed for a reservoir are normally distrib-uted with the following parameters:

Jun Jul Aug Sep Oct Nov Dec Jan Feb Mar Apr May Mean 624 3311 3638 1534 1196 495 207 98 55 39 52 219 Std 468 1889 1391 629 512 275 106 86 33 38 50 131 .dev

Formulate and solve a chance constrained LP problem to determine the minimum reservoir capacity required to satisfy a constant demand of 0.95A, A, and 1.05A (where A is the average of the mean flows).

Solve the problem for a reliability of 90% of meeting the demand. Use a convenient LDR.