The highest boost weight components of the Maxwell (π+ 1)βform ο¬eld strength are denoted by a GHP scalar π of boost weight 1 and spin π. In 4D (where π = 1) the quantity analogous toπsatisο¬es a decoupled equation of motion in an algebraically spe- cial background. We shall investigate the conditions under whichπ satisο¬es a decoupled equation of motion in π > 4 dimensions. The motivation for doing this is mainly that the Maxwell ο¬eld illustrates the arguments that we shall also employ in the gravitational case, but the equations are considerably simpler. For this reason, we restrict to the simplest caseπ= 1.
In this section, we show how, in a particular class of background Einstein spacetimes, we can construct decoupled 2nd order diο¬erential equations for a Maxwell test ο¬eld. We show that this decoupling is possible if and only if the background spacetime is Kundt, that is it admits a geodesic null vector ο¬eld that is not shearing, twisting or expanding.
In particular, we will show that the dynamics of a Maxwell test ο¬eld on the back- ground of a Kundt spacetime can be described by the following equation:
(2ΓΎβ²ΓΎ+kπkπ+πβ²ΓΎβ4ππkπ + Ξ¦β 2πβ3πβ1 Ξ)
ππ+(β2ππkπ+2ππkπ+2Ξ¦Sππ+4Ξ¦Aππ)ππ = 0. (4.4) We also show that analogous decoupled equations cannot be constructed for spacetimes that are not Kundt, and discuss brieο¬y whether any alternative progress can be made.
It is interesting to compare this to the equation of motion for a massive scalar ο¬eld Ξ¨:
(βπβπβπ2)Ξ¨ = 0. (4.5)
When written out in GHP form in a general background, this equation is
(2ΓΎβ²ΓΎ+kπkπ+πβ²ΓΎβ2ππkπ+πΓΎβ²βπ2)Ξ¨ = 0. (4.6) To compare this with the decoupled Maxwell equation, one must specialize to a Kundt spacetime, for which π= 0. Note thatππβ² does not appear in either equation.
4.3.1 Derivation of results
In the case of a 2-form ο¬eld strengthπΉππ, the GHP Maxwell equations (2.76-2.79) reduce to:
kπππ+ΓΎπ = ππβ²ππ+ππππΉππ βππ βπ ππβ²π (4.7) 2k[πππ]βΓΎπΉππ = 2π[πβ²ππ]+ 2ππ[ππ]+ 2πΉ[πβ£πππβ£π]+ 2π [ππβ²π] (4.8) 2ΓΎβ²ππ+kππΉππβkππ = (2πβ²[ππ]βπβ²πΏππ)ππβ2πΉππππβ2πππ+ (2π(ππ)βππΏππ)πβ²π (4.9) k[ππΉππ] = π[ππβ²ππ]+πβ²[ππππ] (4.10)
4.3. DECOUPLING OF ELECTROMAGNETIC PERTURBATIONS 89 A further three equations can be obtained by priming equations (4.7),(4.8) and (4.9).
We will often make use of the combination πΏππ(4.7)β(4.8):
ΓΎ(πΉππ +πΏπππ) = 2k[πππ]βπΏππkπππβ2π[πβ²ππ]β2ππ[ππ]β2πΉ[πβ£πππβ£π]β2π [ππβ²π]
+πΏππ(ππβ²ππ+ππππΉππβππ βπ ππβ²π) (4.11) Now consider the combinationΓΎ(4.9) +kπ(4.11). This gives
0 = (2ΓΎβ²ΓΎ+kπkπ)ππ+ 2[ΓΎ,ΓΎβ²]ππβ[ΓΎ,kπ](πΉππ +ππΏππ) + [kπ,kπ]ππ
+ΓΎ(
β(2πβ²[ππ]βπβ²πΏππ)ππ + 2(πΉππ+ππΏππ)ππβ(2π(ππ)βππΏππ)πβ²π)
(4.12) +kπ(
βππππΉππ+ππβππβ²ππ +π ππβ²π) +kπ(
2π[πβ²ππ]+ 2ππ[ππ]+ 2πΉ[πβ£πππβ£π]+ 2π [ππβ²π]) . This involves second derivatives of π, as well as of the boost weight 0 quantitiesπΉππ
and π. However, the latter occur in the form of a commutator [ΓΎ,kπ](πΉππ +ππΏππ) and can therefore be eliminated using (C2). Now we consider ο¬rst derivatives of Maxwell components other than π. We need to eliminate these from the equation if it is to decouple.
First consider terms involving ΓΎ:
β ΓΎ acts on π and πΉππ through the combination ΓΎ(πΉππ +ππΏππ), which we eliminate using equation (4.11).
β Terms involving ΓΎπβ²π are eliminated using equation (4.9)β².
β Terms in which ΓΎ acts on π, π and πβ² are eliminated using the Newman-Penrose equations (NP1), (NP2) and (NP4)β² respectively.
The resulting equation is very long:
[(2ΓΎΓΎβ²+kπkπ+πβ²ΓΎ+πΓΎβ²β2ππβ²kπβ2ππkπ)ππ
+ (βπβ²ππΓΎβ2ππkπ+πβ²ππΓΎβπππΓΎβ² + [kπ,kπ] + 2ππkπβπππΓΎβ²)ππ
βπ ππ β²πππβ2ππππππβ²ππ +ππππππβ²ππβ2ππππππβ²+ 2ππππππβ²βππππππβ²ππ +ππππβ²ππ + 2ππππππβ²+π ππ β²πππ βπ ππ β²πππ βππππππβ²ππβ2Ξ¦AππππβΞ¦ππβπβ2πβ1Ξππ
] +[
π πΓΎβ²(πΉππ +ππΏππ) +πππkππβπππkππΉππ + 2πππkππ+πππkππΉππβπππkππΉππ +πππkππΉππ
βπkππππβπΉππkππππ+πkππππ +πΉππkππππ+πkππβπΉππkππππ + 2πΓΎβ²π π+ 2πΉππΓΎβ²π π
β5ππππππ β2πΞ¨πβ4πΉπππππππβπΉππΞ¨π βπΉπππ ππβ²ππ +πΉπππ ππβ²ππβπΉππΞ¨πππβπΉπππ ππβ²ππ +πΉπππ ππβ² +ππππππ β3πΉπππππππβππππ+ 2πΉπππππππβπΉπππππππ+πΉπππππ]
+[
π πkππβ²π +π πkππβ²πβπ πkππβ²π+ 2πππππππβ²π+π ππππβ²π+πππππππβ²π +πβ²πππππππβπ ππππβ²π βπ ππππβ²π βπππππβ²π βπππππππβ²π+ 2Ξ©πππβ²π]
= 0 (4.13)
The only terms above involving derivatives of Maxwell components other than π are of the (schematic) formπΏΓΎβ²F,πΏΓΎβ²π πΏkπβ²,πkF and πkπ. We need to eliminate all of these from our equations if we are to obtain a decoupled equation for π. Consider the ο¬rst three, which are
π πΓΎβ²(πΉππ +ππΏππ) + 2π πk[ππβ²π]+π πkππβ²π = 2π πΓΎβ²(πΉππ +ππΏππ) +. . . (4.14) where we have used (4.11)β² to eliminate the πΏkπβ² terms in favour of πΏΓΎβ²F, πΏΓΎβ²π and some other terms not involving derivatives.
Now, the Maxwell equations cannot be used to eliminate the terms of the form πΏΓΎβ²(F+π) without re-introducing 1-derivative terms of the form πΏkπβ². Hence the only way in which theπΏΓΎβ²(F+π) terms can be eliminated is ifπΏ=0, and therefore the vector ο¬eld β must be geodesic for decoupling to be possible. We assume henceforth that this is the case.
Now examine the πkFand πkπ terms above. These are:
πππkππ βπππkππΉππ+ 2πππkππ +πππkππΉππβπππkππΉππ+πππkππΉππ (4.15) To achieve decoupling, we need to eliminate these terms from the equation without introducing any 1-derivative terms (unless the derivative acts on π). It is convenient to decomposekππΉππ into parts that transform irreducibly under ππ(πβ2):
kππΉππ =β±πππ+ 2
πβ3πΏπ[πkβ£ππΉπβ£π], (4.16) where β±πππ is traceless and can be decomposed further into objects transforming irre- ducibly according to the Young tableaux and . The quantity kππ transforms in the same way askππΉππ, i.e. as a vector ( ) under ππ(πβ2). The latter can be eliminated in favour of the former using equation (4.9), which giveskππΉππ =kππ+. . ., where the ellipsis denotes terms in which derivatives act only onπ. The contribution of the βvectorβ terms to (4.15) is then
2
πβ3(πππ+ (πβ3)πππ βππΏππ)kππ (4.17) We can substitute our decomposition of kπΉ into the Maxwell equations. There are no Maxwell equations that can be used to eliminate kππ without reintroducing new derivative terms of the form πΓΎπβ². Hence the only way in which the Maxwell equation will decouple is if the expression in brackets in (4.17) vanishes. The symmetric and antisymmetric parts of the resulting equation give
πππ = 0 = (πβ4)πππ, (4.18)
whereπ and πare the shear and rotation of βrespectively. Hence a necessary condition for decoupling is thatβ be shearfree and, forπ >4, rotation free (and hence hypersurface
4.3. DECOUPLING OF ELECTROMAGNETIC PERTURBATIONS 91 orthogonal sinceβ is geodesic). We now assume π >4, so we setπ =π =0 henceforth, and therefore have
πππ = π
πβ2πΏππ. (4.19)
A spacetime admitting a null geodesic congruence with vanishing rotation and shear is called a Robinson-Trautman spacetime ifπβ= 0 and a Kundt spacetime ifπ= 0. We saw in Chapter 3that an Einstein spacetime of either of these types is algebraically special, with the vector ο¬eld β aligned with the congruence being a multiple WAND. Therefore we can take Ξ©=0=Ξ¨. Note that (NP3) now implies kππ= 0.
It is now guaranteed that we can use equation (4.9) to eliminate βvectorβ terms of the formkππΉππ orkππ from (4.13). Upon doing so, we ο¬nd that the terms involving β±πππ
all drop out. The commutators [ΓΎ,ΓΎβ²] and [kπ,kπ] can be used to tidy up the equation, giving
0 = [
2ΓΎβ²ΓΎ+kπkπ +πβ²ΓΎ+π+2πβ2πΓΎβ²β4ππkπ]
ππ+ 2(ππkπβππkπ)ππ +
[
3Ξ¦ππ βΞ¦ππβ 2π
πβ2πβ²[ππ]+ (
Ξ¦ + ππβ²
πβ2 β2πβ3 πβ1 Ξ
) πΏππ
] ππ
+πβ4 πβ2π
[
ππ(πΉππ βπΉ πΏππ) + π πβ2πβ²π
]
. (4.20) The only term involvingπβ² is the ο¬nal one, so forπβ² to decouple we need (πβ4)π= 0.
This also ensures that the terms involving πΉππ and π drop out of the equation. Hence decoupling requires π = 0 (since π > 4), which implies πππ = 0, so β must be free of expansion as well as shear and rotation. That is, the spacetime must be Kundt. The equation reduces to
[2ΓΎβ²ΓΎ+kπkπ +πβ²ΓΎβ4ππkπ + Ξ¦β 2πβ3πβ1 Ξ]
ππ + (2ππkπ β2ππkπ + 3Ξ¦ππ β Ξ¦ππ)ππ = 0.
(4.21) which is equivalent to (4.4).
To summarize, for π > 4, π satisο¬es a second-order decoupled equation if, and only if, β is geodesic with vanishing expansion, rotation and shear. The existence of such a choice of β implies, by deο¬nition, that the spacetime is Kundt.
Note the presence of factors of (π β4) in several of our equations above. When π= 4, it is not necessary for the rotation π of β to vanish in equation (4.18), or for the expansion π to vanish in equation (4.20). Indeed, in 4D, all that is required is that β be geodesic and shearfree, which is equivalent (by the Goldberg-Sachs theorem) to the spacetime being algebraically special.
It is clear that πβ² will satisfy a second-order decoupled equation (the prime of the above equation) if, and only if, π is geodesic with vanishing expansion, rotation and
shear. Hence π and πβ² will both satisfy second order decoupled equations if, and only if, πΏ = πΏβ² = π = πβ² = 0. A natural name for a spacetime admitting such null vector ο¬elds seems to be:
Deο¬nition 4.2 A spacetime is doubly Kundt if and only if it admits a pair of non- expanding, non-shearing, non-twisting geodesic null vector ο¬elds β and π with β.πβ= 0.
4.3.2 The Schwarzchild Solution
Consider the special case of the higher-dimensional Schwarzschild solution, which is not Kundt. This solution has π = πβ2π 1 and π =0 (a consequence of spherical symmetry).
The latter implies that the terms inFandπ drop out of equation (4.20), leaving us with an equation of the form
(β‘π)π+ (πβ4)
(πβ2)2π2πβ²π = 0, (4.22) whereβ‘is a second order diο¬erential operator. The second term remains an obstruction to decoupling. For the Schwarzschild solution, the two multiple WANDs have identical properties so we can take the prime of the equation to obtain
(β‘β²πβ²)π+ (πβ4)
(πβ2)2πβ²2ππ = 0, (4.23)
and hence [
β‘β² ( 1
π2β‘π )]
πβ (πβ4)2
(πβ2)4πβ²2ππ = 0. (4.24) So in factπdoes satisfy a decoupled equation but it is fourth order in derivatives. Note that we had to make use of several special properties of the Schwarzschild solution to obtain this result. It would be interesting to investigate more generally the circumstances under which one can obtain a decoupled equation of higher order forπ.